Problem 98
Question
Which ionic compound has the largest lattice energy? Explain your choice. \(\begin{array}{lll}\mathrm{MgS} & \mathrm{RbI} & \mathrm{Li}_{2} \mathrm{~S}\end{array}\)
Step-by-Step Solution
Verified Answer
MgS has the largest lattice energy due to high charges and small ionic radii.
1Step 1: Understanding Lattice Energy
Lattice energy is the energy required to separate one mole of an ionic compound into its gaseous ions. It is an indicator of the strength of the forces holding the ions together in the solid.
2Step 2: Factors Affecting Lattice Energy
The lattice energy depends on two main factors: the charges of the ions and the distance between the ions (ionic radii). Higher charges and smaller distances result in higher lattice energy.
3Step 3: Analyze MgS
In MgS, magnesium \((\text{Mg}^{2+})\) and sulfur \((\text{S}^{2-})\) both carry a double charge. The ionic radii are relatively small, leading to a strong attraction between ions.
4Step 4: Analyze RbI
In RbI, rubidium \((\text{Rb}^{+})\) and iodine \((\text{I}^{-})\) have single charges. Both ions are relatively large, resulting in weaker attraction compared to ions with higher charge density.
5Step 5: Analyze Li2S
In Li2S, lithium \((\text{Li}^{+})\) has a single charge while sulfur \((\text{S}^{2-})\) has a double negative charge. The lattice energy is influenced by the presence of the doubly charged sulfur, but it is typically lower than MgS due to the single charge of lithium.
6Step 6: Conclusion about Largest Lattice Energy
Considering the factors of ionic charge and radius, MgS has the largest lattice energy among the given compounds due to the double charges on both its ions and relatively small ionic radius, which results in a strong electrostatic interaction.
Key Concepts
Ionic CompoundsElectrostatic ForcesIonic ChargesIonic Radius
Ionic Compounds
Ionic compounds are formed when atoms transfer electrons to achieve a stable electron configuration. Usually, this involves a metal donating electrons to a non-metal, resulting in the formation of positive and negative ions.
- Metals, like magnesium (Mg), lose electrons to form positive ions, known as cations.
- Non-metals, like sulfur (S), gain electrons to form negative ions, called anions.
Electrostatic Forces
Electrostatic forces are fundamental to the behavior of ionic compounds. These forces result from the attraction between positively and negatively charged ions.
The strength of electrostatic forces plays a crucial role in determining the lattice energy of an ionic compound. When ions have stronger electrostatic attractions:
- The lattice energy is higher, which leads to a more stable compound.
- The melting and boiling points of the compound are usually higher.
Ionic Charges
The charge on an ion profoundly influences the lattice energy of an ionic compound. The rule of thumb is: the greater the charges of the ions, the higher the lattice energy.
For example:
- In MgS, both ions (Mg2+ and S2-) have double charges, making their electrostatic forces highly significant.
- In RbI, Rb+ and I- have single charges, resulting in weaker interactions compared to ions with higher charges.
- In Li2S, the sulfur ion has a double negative charge (S2-), but the lithium ion has only a single positive charge (Li+), which reduces overall attraction compared to compounds like MgS.
Ionic Radius
Ionic radius refers to the size of an ion in a crystal lattice. The size of an ion influences how close ions can get to each other, affecting their electrostatic forces and, consequently, the lattice energy.
- Smaller ionic radii allow ions to be closer, increasing the strength of the electrostatic attractions.
- Larger ionic radii result in weaker attractions due to increased distances between ions.
Other exercises in this chapter
Problem 95
Determine the lattice energy for L.iCl(s) given these data: Sublimation enthalpy of \(\mathrm{Li}, 161 \mathrm{~kJ} / \mathrm{mol} ; \mathrm{IF}_{1}\) for \(\ma
View solution Problem 97
Which ionic compound has the lowest melting point? Explain your choice. \(\begin{array}{lll}\mathrm{LiCl} & \mathrm{NaBr} & \mathrm{KCl}\end{array}\)
View solution Problem 99
Give the symbol of the ground-state atom that (a) is in Group 8 A but has no \(p\) electrons. (b) has a single electron in the \(3 d\) subshell. (c) forms a \(1
View solution Problem 100
Give the symbol of all the ground-state atoms that have (a) no \(p\) electrons. (b) from two to four \(d\) electrons. (c) from two to four \(s\) electrons.
View solution