Problem 98
Question
The product(s) obtained via oxymercuration \(\left(\mathrm{HgSO}_{4}\right.\)
\(+\mathrm{H}_{2} \mathrm{SO}_{4}\) ) of but-1-yne would give
(a)
Step-by-Step Solution
Verified Answer
The product obtained is (a) \(CCC(C)=O\).
1Step 1: Identify the Reaction Type
The reaction involves oxymercuration, specifically the oxymercuration of an alkyne (but-1-yne). Oxymercuration typically adds water across a carbon-carbon multiple bond, resulting in an enol, which can then tautomerize to a more stable ketone.
2Step 2: Write the Reaction
The starting material is but-1-yne. The reagents, HgSO4 and H2SO4, will add across the triple bond of the but-1-yne, converting it into an enol intermediate: \[C_4H_6 \xrightarrow{HgSO_4, H_2SO_4, H_2O} C_4H_8O \text{(enol)}\]
3Step 3: Understand Tautomerization
The enol formed in the previous step is not stable and undergoes keto-enol tautomerization. This means the enol will convert into a more stable keto form, which is a ketone.
4Step 4: Determine the Final Product
The enol formed from but-1-yne will specifically tautomerize to butan-2-one. This is because the addition of water occurs at the more substituted position (Markovnikov addition), leading to the ketone with a methyl group at the second carbon.
5Step 5: Match Chemical Structure
Compare the product obtained, butan-2-one, which can be represented as \( CCC(C)=O \), with the given options. This matches option (a): \( CCC(C)=O\).
Key Concepts
Alkyne ChemistryKeto-Enol TautomerizationMarkovnikov Addition
Alkyne Chemistry
Alkyne chemistry is a fascinating area that delves into the reactions and properties of alkynes, which are hydrocarbons characterized by the presence of a carbon-carbon triple bond. These triple bonds are highly reactive, making alkynes a central focus in organic reactions.
One important aspect of alkyne chemistry is their ability to participate in addition reactions. Because the triple bond consists of one sigma bond and two pi bonds, it can be broken and transformed into single or double bonds by adding atoms or groups.
Oxymercuration is a specific type of reaction involving alkynes, where reagents like mercury sulfate and sulfuric acid (HgSO4 and H2SO4) help in the addition of water. This reaction typically turns an alkyne into a more stable ketone by going through an enol intermediate, which is a temporary structure where the oxygen and hydrogen add across the triple bond.
Understanding alkyne chemistry is essential for recognizing how different reactions can transform the structure and reactivity of molecules, leading to products that are often more stable.
One important aspect of alkyne chemistry is their ability to participate in addition reactions. Because the triple bond consists of one sigma bond and two pi bonds, it can be broken and transformed into single or double bonds by adding atoms or groups.
Oxymercuration is a specific type of reaction involving alkynes, where reagents like mercury sulfate and sulfuric acid (HgSO4 and H2SO4) help in the addition of water. This reaction typically turns an alkyne into a more stable ketone by going through an enol intermediate, which is a temporary structure where the oxygen and hydrogen add across the triple bond.
Understanding alkyne chemistry is essential for recognizing how different reactions can transform the structure and reactivity of molecules, leading to products that are often more stable.
Keto-Enol Tautomerization
Keto-enol tautomerization is a fundamental concept in organic chemistry that describes the chemical process through which enols and ketones interconvert. An enol is a compound that has an alcoholic group (-OH) directly connected to a carbon-carbon double bond, whereas a ketone features a carbonyl group (C=O). These forms are both structural isomers called tautomers, and they exist in a dynamic equilibrium.
During this tautomerization, the enol form can spontaneously rearrange to become a ketone, which is usually more stable. This involves a proton transfer from the hydroxyl group to another atom, often leading to the migration of a double bond.
In the context of the oxymercuration of an alkyne such as but-1-yne, the initial product is an enol that swiftly undergoes tautomerization to form butan-2-one, a ketone. The conversion from enol to ketone is driven by the thermodynamic stability provided by stronger carbon-oxygen bonds.
Keto-enol tautomerization is a critical concept to grasp because it underscores how molecular structures can dynamically evolve into more stable configurations under certain conditions.
During this tautomerization, the enol form can spontaneously rearrange to become a ketone, which is usually more stable. This involves a proton transfer from the hydroxyl group to another atom, often leading to the migration of a double bond.
In the context of the oxymercuration of an alkyne such as but-1-yne, the initial product is an enol that swiftly undergoes tautomerization to form butan-2-one, a ketone. The conversion from enol to ketone is driven by the thermodynamic stability provided by stronger carbon-oxygen bonds.
Keto-enol tautomerization is a critical concept to grasp because it underscores how molecular structures can dynamically evolve into more stable configurations under certain conditions.
Markovnikov Addition
Markovnikov Addition is a principle in organic chemistry that predicts how a compound will add across a double or triple bond. According to Markovnikov's rule, during the addition of a reagent to an unsymmetrical alkene or alkyne, the more stable carbocation intermediate forms preferentially.
This pattern of addition ensures that the oxymercuration proceeds to give the Markovnikov product. For but-1-yne, this results in the enol intermediate rearranging through keto-enol tautomerization into butan-2-one, a ketone.
Understanding Markovnikov Addition helps predict and control the outcome of reactions involving alkenes and alkynes, greatly benefiting synthetic chemistry and the construction of complex organic molecules.
- This means that the hydrogen atom tends to add to the carbon with the most hydrogens already attached, while the other part of the reagent will add to the carbon with the fewest hydrogens.
This pattern of addition ensures that the oxymercuration proceeds to give the Markovnikov product. For but-1-yne, this results in the enol intermediate rearranging through keto-enol tautomerization into butan-2-one, a ketone.
Understanding Markovnikov Addition helps predict and control the outcome of reactions involving alkenes and alkynes, greatly benefiting synthetic chemistry and the construction of complex organic molecules.
Other exercises in this chapter
Problem 92
In the presence of peroxide, and hydrogen chloride, hydrogen iodide does not undergo antiMarkovnikov's addition to alkenes because (a) both are highly ionic (b)
View solution Problem 93
The reaction of propene with HOCl proceeds via the addition of (a) \(\mathrm{H}^{+}\)in the first step (b) \(\mathrm{Cl}^{+}\)in the first step (c) \(\mathrm{OH
View solution Problem 100
Ethene and ethyne can be distinguished by (a) \(\mathrm{Br}_{2}\) water (b) \(\mathrm{KMnO}_{4}\) solution (c) cuprous chloride solution (d) any of the above
View solution Problem 101
Ethene and ethyne can be distinguished by (a) \(\mathrm{Br}_{2}\) water (b) \(\mathrm{KMnO}_{4}\) solution (c) cuprous chloride solution (d) any of the above
View solution