Problem 98
Question
Solve each equation. $$3^{x^{2}-12}=9^{2 x}$$
Step-by-Step Solution
Verified Answer
The solutions are \(x = 6\) and \(x = -2\).
1Step 1: Write bases in terms of 3
3 is a common base for both sides. Left side is already with base 3. The base on the right side, 9, can also be written as \(3^{2}\). So, \(9^{2x} = (3^{2})^{2x} = 3^{4x}\). So the equation becomes: \(3^{x^2-12} = 3^{4x}\).
2Step 2: Equating the exponents
Since the bases are equal, the exponents must also be equal. Thus, set the exponents equal to each other: \(x^2 - 12 = 4x\). This is a quadratic equation.
3Step 3: Rearranging the equation
Rearrange the equation to make it easier to solve. It is possible to do this by setting the equation to zero: \(x^{2} - 4x - 12 = 0\)
4Step 4: Solving the equation
Now, solve the quadratic equation. This can be done by factoring or applying the quadratic formula, which gives \(x = 6\) or \(x = -2\) as the roots of this equation
Other exercises in this chapter
Problem 97
Describe the power rule for logarithms and give an example.
View solution Problem 98
Explain how to use the graph of \(f(x)=2^{x}\) to obtain the \(\operatorname{graph}\) of \(g(x)=\log _{2} x\)
View solution Problem 98
Without showing the details, explain how to condense \(\ln x-2 \ln (x+1)\)
View solution Problem 99
Explain how to find the domain of a logarithmic function.
View solution