Problem 98
Question
Simplify each expression, if possible. All variables represent positive real numbers. $$ \sqrt[3]{\frac{4}{125}} $$
Step-by-Step Solution
Verified Answer
\( \sqrt[3]{\frac{4}{125}} = \frac{\sqrt[3]{4}}{5} \)
1Step 1: Understand the Expression
We need to simplify the expression \( \sqrt[3]{\frac{4}{125}} \). This is the cube root of the fraction \( \frac{4}{125} \). The goal is to express this in simplest form.
2Step 2: Simplify the Denominator
Notice that 125 is a perfect cube because \( 125 = 5^3 \). Thus, the cube root of 125 is 5. So, \( \sqrt[3]{125} = 5 \).
3Step 3: Simplify the Numerator
The numerator is 4, which is not a perfect cube. Therefore, the cube root of 4 will remain \( \sqrt[3]{4} \).
4Step 4: Combine Results
Combine the simplified results from Steps 2 and 3. The expression \( \sqrt[3]{\frac{4}{125}} \) simplifies to \( \frac{\sqrt[3]{4}}{5} \).
Key Concepts
Cube Root SimplificationFractional RadicalsAlgebraic Expressions
Cube Root Simplification
The cube root of a number is a special root that asks, "What number, when multiplied by itself three times, gives me this number?" It is slightly more complex than the square root.
In this exercise, we are working with the cube root of a fraction, \( \sqrt[3]{\frac{4}{125}} \). The cube root can be applied separately to the numerator and the denominator because of the property of radicals: \( \sqrt[3]{\frac{a}{b}} = \frac{\sqrt[3]{a}}{\sqrt[3]{b}} \).
In this exercise, we are working with the cube root of a fraction, \( \sqrt[3]{\frac{4}{125}} \). The cube root can be applied separately to the numerator and the denominator because of the property of radicals: \( \sqrt[3]{\frac{a}{b}} = \frac{\sqrt[3]{a}}{\sqrt[3]{b}} \).
- Step 1: Identify if the denominator or numerator is a perfect cube. A perfect cube is a number you can get by raising another number to the third power.
- Step 2: Simplify the cube root of any perfect cubes.
- Step 3: Leave the cube root of non-perfect cubes as-is, if they cannot be simplified further.
Fractional Radicals
Fractional radicals involve taking the root of a fraction, like \( \sqrt[3]{\frac{4}{125}} \). The main strategy is to treat the numerator and denominator separately.
By simplifying each part individually, we get a clearer view of how the expression behaves.
By simplifying each part individually, we get a clearer view of how the expression behaves.
- Focus on the Denominator: For instance, with the denominator \( 125 \), we know this is \( 5^3 \). Thus, \( \sqrt[3]{125} = 5 \).
- Focus on the Numerator: In our case, \( 4 \) does not break down into a perfect cube nicely, so it stays as \( \sqrt[3]{4} \).
Algebraic Expressions
Understanding algebraic expressions is essential when simplifying exercises like these. They combine numbers, roots, and variables we manipulate to find simpler forms.
Here, we simplified the algebraic expression \( \sqrt[3]{\frac{4}{125}} \).
Steps in Tidying Expressions:
Here, we simplified the algebraic expression \( \sqrt[3]{\frac{4}{125}} \).
Steps in Tidying Expressions:
- Factor and Reduce: For radical expressions, factoring numbers helps us see simpler cube roots and reduces fractions where possible.
- Keep a Clean Format: Write expressions clearly, avoiding clutter to maintain mathematical clarity. Utilize radical simplifications and fractions efficiently.
Other exercises in this chapter
Problem 97
Solve each equation. Write all proposed solutions. Cross out those that are extraneous. Let \(f(x)=\sqrt{x+16}\) and \(g(x)=7-\sqrt{x+9} .\) Find all values of
View solution Problem 98
Use rational exponents to simplify each radical. All variables represent positive real numbers. See Example 10 . $$ \sqrt[8]{q^{2}} $$
View solution Problem 98
Rationalize each denominator. All variables represent positive real numbers. $$ \frac{\sqrt{x}+\sqrt{y}}{\sqrt{x}-\sqrt{y}} $$
View solution Problem 98
Perform the operations. Write all answers in the form \(a+b i .\) $$ (14+4 i)-(-9-i) $$
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