Problem 98
Question
Show that \(\lim _{x \rightarrow a} \cos x=\cos a\). (See the hint for Exercise 97.)
Step-by-Step Solution
Verified Answer
To show that \(\lim_{x \rightarrow a} \cos x = \cos a\), we used the limit definition and introduced the auxiliary function g(x) = cos(x). We rewrote \(|cos(x) - cos(a)|\) using a trigonometric identity involving the sine function: \[|cos(x) - cos(a)| = |-2 sin(\frac{x - a}{2}) sin(\frac{x + a}{2})|\]. Applying inequalities for the sine function and using the facts that the sine function is continuous and differentiable, we showed that for every ε > 0, there exists δ > 0, such that if 0 < |x - a| < δ, then \(-2 ε \leq -2 sin(\frac{x - a}{2}) sin(\frac{x + a}{2}) \leq 2 ε\), thus proving that \(\lim_{x \rightarrow a} \cos x = \cos a\).
1Step 1: Recall Limit Definition
Recall the limit definition:
If \[ \lim _{x \rightarrow a} f(x) = L\], then for every ε > 0, there exists a δ > 0, such that if 0 < |x - a| < δ, then |f(x) - L| < ε.
In our case, we have to show that for every ε > 0, there exists a δ > 0, such that if 0 < |x - a| < δ, then |cos(x) - cos(a)| < ε.
2Step 2: Introduce Auxiliary Function
To proof the limit, let's use the auxiliary function g(x) = cos(x), then
\[|g(x) - g(a)| = |cos(x) - cos(a)|\]
3Step 3: Use Trigonometric Identity for |cos(x) - cos(a)|
We can rewrite |cos(x) - cos(a)| using a trigonometric identity that involves the sine function, which is:
\[|cos(x) - cos(a)| = |-2 sin(\frac{x - a}{2}) sin(\frac{x + a}{2})|\]
Keep in mind that the sine function is always between -1 and 1, so we can apply the inequality
\(-1 \leq sin(t) \leq 1\)
4Step 4: Apply Inequalities for Sine Function and Combine them with Limit Definition
We apply inequality for sine function, and thus have
\(-2 |sin(\frac{x - a}{2}) sin(\frac{x + a}{2})| \leq -2 sin(\frac{x - a}{2}) sin(\frac{x + a}{2}) \leq 2 |sin(\frac{x - a}{2}) sin(\frac{x + a}{2})|\)
Now, for every ε > 0, there exists δ > 0, such that if 0 < |x - a| < δ, then
\(-2 ε \leq -2 sin(\frac{x - a}{2}) sin(\frac{x + a}{2}) \leq 2 ε\)
Since sin(x) is continuous and differentiable, we know that \(\lim _{x \rightarrow 0} sin(x) = 0\). This means that
\[\lim _{x \rightarrow a} sin(\frac{x - a}{2}) sin(\frac{x + a}{2}) = 0\]
As a result, we can choose δ > 0 such that
\[ -2 sin(\frac{x - a}{2}) sin(\frac{x + a}{2}) \leq -2 ε\]
and
\[2 sin(\frac{x - a}{2}) sin(\frac{x + a}{2}) \leq 2 ε\]
Since we have proven these inequalities for every ε, it proves that \[\lim_{x \rightarrow a} \cos x = \cos a\]
Key Concepts
Trigonometric LimitsContinuityEpsilon-Delta DefinitionTrigonometric Identities
Trigonometric Limits
The limit of a trigonometric function as a variable approaches a certain value concerns understanding how the function behaves close to that point. Trigonometric limits often involve functions like sine, cosine, and tangent. When considering limits at particular points, the goal is to determine the output value the function approaches.
For example, in the limit \[\lim _{x \to a} \cos x = \cos a,\]the task is to show that the cosine of \(x\), as \(x\) nears \(a\), approaches the cosine of \(a\).
For example, in the limit \[\lim _{x \to a} \cos x = \cos a,\]the task is to show that the cosine of \(x\), as \(x\) nears \(a\), approaches the cosine of \(a\).
- Trigonometric limits use algebraic manipulation and well-accepted trigonometric identities to simplify expressions.
- Evaluating these limits often requires understanding core properties of trigonometric functions, such as their periodic nature and bounded values.
Continuity
Continuity of a function at a particular point means there is no interruption in the graph of the function at that point. For a function to be continuous at a point \(a\), three conditions must be satisfied:
Continuity not only aids in simplifying limit calculations but also in understanding the behavior of functions across their domains.
- \(f(a)\) must be defined.
- The limit \(\lim_{x \to a} f(x)\) must exist.
- \(\lim_{x \to a} f(x) = f(a)\).
Continuity not only aids in simplifying limit calculations but also in understanding the behavior of functions across their domains.
Epsilon-Delta Definition
The epsilon-delta definition of a limit rigorously defines what it means for a function to approach a certain value as the input approaches a particular point. It asserts that for every given epsilon \(\varepsilon\) greater than zero, there exists a delta \(\delta\) such that whenever \(|x - a| < \delta\), it follows that \(|f(x) - L| < \varepsilon\).
This formalism is crucial for rigorously proving limits, especially when dealing with more complex functions like trigonometric ones.
This formalism is crucial for rigorously proving limits, especially when dealing with more complex functions like trigonometric ones.
- The epsilon represents how close the function's value should be to the limit \(L\).
- The delta represents how close \(x\) should be to \(a\) for \(f(x)\) to be that close to \(L\).
Trigonometric Identities
Trigonometric identities are equations involving trigonometric functions that are true for all variables within their definitions. These identities are pivotal tools in trigonometry and calculus, particularly in the manipulation and simplification of expressions.
In the context of limits, identities like \[\cos(x) - \cos(a) = -2\sin\left(\frac{x - a}{2}\right)\sin\left(\frac{x + a}{2}\right)\]are employed to express differences in ways that are conducive to limit evaluation.
In the context of limits, identities like \[\cos(x) - \cos(a) = -2\sin\left(\frac{x - a}{2}\right)\sin\left(\frac{x + a}{2}\right)\]are employed to express differences in ways that are conducive to limit evaluation.
- Simplifying trigonometric expressions often requires recognizing opportunities to apply these identities.
- They allow translation of complex trigonometric expressions into simpler forms amenable to limit evaluation using algebraic tools like factorization and inequality.
Other exercises in this chapter
Problem 95
Prove that if \(f\) and \(g\) are continuous at \(a\) with \(g(a) \neq 0\), then \(f / g\) is continuous at \(a\).
View solution Problem 95
Suppose that \(f(x)
View solution Problem 99
In Exercises 99-102, determine whether the statement is true or false. If it is true, explain why. If it is false, explain why or give an example that shows it
View solution Problem 100
Determine whether the statement is true or false. If it is true, explain why. If it is false, explain why or give \(a n\) example that shows it is false. If \(f
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