Problem 98
Question
One way to derive Equation \(19.3\) depends on the observation that at constant \(T\) the number of ways, \(W\), of arranging \(m\) ideal-gas particles in a volume \(V\) is proportional to the volume raised to the \(m\) power: $$ W \propto V^{m} $$ Use this relationship and Boltzmann's relationship between entropy and number of arrangements (Equation 19.5) to derive the equation for the entropy change for the isothermal expansion or compression of \(n\) moles of an ideal gas.
Step-by-Step Solution
Verified Answer
To derive the equation for the entropy change for the isothermal expansion or compression of n moles of an ideal gas, we follow these steps:
1. Write down the given relationships: \(W \propto V^m\) and \(S = k ln(W)\).
2. Substitute the first relationship into the second: \(S = k ln(V^m)\).
3. Simplify the expression for entropy and relate m to the number of moles: \(S = mk ln(V)\) and \(m = nN_A\).
4. Substitute the relationship between m and n into the entropy expression: \(S = (nN_A)k ln(V)\).
5. Derive the equation for entropy change: \(\Delta S = (nN_A)kln\left(\frac{V_{final}}{V_{initial}}\right)\).
This gives us the equation for the entropy change for the isothermal expansion or compression of n moles of an ideal gas.
1Step 1: Write down the given relationships
We are given two relationships in the problem:
1. \(W \propto V^m\), where m is the number of ideal-gas particles, and W is the number of ways to arrange these particles in a volume V.
2. Boltzmann's relationship between entropy and number of arrangements, Equation 19.5, which states:
\[S = k ln(W)\]
Here, S is the entropy, k is the Boltzmann constant, and W is the number of arrangements of particles.
2Step 2: Substitute the first relationship into the second
We can substitute the relationship between W and V (from Step 1) into Boltzmann's relationship between entropy and the number of arrangements:
\[S = k ln(V^m)\]
3Step 3: Simplify the expression for entropy and relate m to the number of moles
Using the properties of logarithms, we can simplify the expression for entropy:
\[S = k ln(V^m) = mk ln(V)\]
Now, we need to relate the number of particles (m) to the number of moles (n). We know that the number of particles = number of moles × Avogadro's number:
\[m = nN_A\]
4Step 4: Substitute the relationship between m and n into the entropy expression
Now, we will substitute the relationship between m and n into the entropy expression derived in Step 3:
\[S = (nN_A)k ln(V)\]
5Step 5: Derive the equation for entropy change
To find the entropy change for the isothermal expansion or compression of n moles of an ideal gas, we will consider the final entropy (S_final) and the initial entropy (S_initial) for the system:
The final entropy is given by:
\[S_{final} = (nN_A)k ln(V_{final})\]
The initial entropy is given by:
\[S_{initial} = (nN_A)k ln(V_{initial})\]
The entropy change (\(ΔS\)) is the difference between the final and initial entropies:
\[ΔS = S_{final} - S_{initial} = (nN_A)k\left[ln(V_{final}) - ln(V_{initial})\right]\]
Using the properties of logarithms, we can combine the terms inside the brackets:
\[ΔS = (nN_A)kln\left(\frac{V_{final}}{V_{initial}}\right)\]
This is the equation for the entropy change for the isothermal expansion or compression of n moles of an ideal gas.
Key Concepts
Boltzmann's relationshipIdeal gas lawIsothermal process
Boltzmann's relationship
Boltzmann's relationship forms a core principle in statistical mechanics. It connects the disorder within a system, known as entropy, to the number of ways particles can be arranged. This relationship is mathematically expressed as:\[S = k \ln(W)\]where:
Boltzmann's relationship is powerful in analyzing the microscopic states and understanding how they relate to macroscopic thermodynamic properties. By substituting a system's microstate arrangements into this expression, one can predict changes in entropy, as demonstrated in exercises involving ideal gases.
- S is the entropy of the system.
- k is Boltzmann's constant, which is approximately \(1.38 \times 10^{-23}\, J/K\).
- W represents the number of distinct ways the particles in the system can be arranged.
Boltzmann's relationship is powerful in analyzing the microscopic states and understanding how they relate to macroscopic thermodynamic properties. By substituting a system's microstate arrangements into this expression, one can predict changes in entropy, as demonstrated in exercises involving ideal gases.
Ideal gas law
The ideal gas law is a crucial equation in physical chemistry, describing the behavior of ideal gases under various conditions. It links pressure (P), volume (V), and temperature (T) with the amount of gas (n), providing a comprehensive view of gas interactions.Mathematically, the ideal gas law is represented as:\[PV = nRT\]where:
It simplifies the understanding of complex gas behaviors by providing a straightforward, albeit idealized, model to work with.
- P is the pressure of the gas.
- V is the volume occupied by the gas.
- n is the number of moles of gas.
- R is the universal gas constant, approximately \(8.314\, J/(mol\cdot K)\).
- T is the temperature in Kelvin.
It simplifies the understanding of complex gas behaviors by providing a straightforward, albeit idealized, model to work with.
Isothermal process
An isothermal process is a thermodynamic process in which the temperature remains constant. This type of process is significant, especially in understanding how gases behave when undergoing expansion or compression without temperature change.In an isothermal process involving an ideal gas, the ideal gas law \(PV = nRT\) still applies. However, because the temperature \(T\) is constant, it implies that both pressure and volume may change, but their product will remain constant.
In practical scenarios:
Understanding these processes allows students to predict how entropic properties shift in different thermodynamic scenarios.
In practical scenarios:
- During an isothermal expansion, a gas increases in volume as it absorbs energy in the form of heat, without an increase in temperature.
- Conversely, during isothermal compression, the gas releases energy as it decreases in volume, again, without a temperature change.
Understanding these processes allows students to predict how entropic properties shift in different thermodynamic scenarios.
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