Problem 98
Question
In Exercises \(91-98\) , assume that each sequence converges and find its limit. $$ \begin{array}{l}{\sqrt{1}, \sqrt{1+\sqrt{1}}, \sqrt{1+\sqrt{1+\sqrt{1}}}} \\\ {\sqrt{1+\sqrt{1+\sqrt{1+\sqrt{1}}}}, \ldots}\end{array} $$
Step-by-Step Solution
Verified Answer
The limit of the sequence is \( \frac{1 + \sqrt{5}}{2} \).
1Step 1: Identify the Sequence
Observe that the sequence is given as a nested radical: \(a_1 = \sqrt{1}\), \(a_2 = \sqrt{1 + a_1}\), \(a_3 = \sqrt{1 + a_2}\), and so on. Each term is justified by the previous term in the sequence.
2Step 2: Assume the Limit Exists
Assuming the sequence \(a_n\) converges, let's denote the limit by \(L\). Therefore, the sequence satisfies \( a_n \to L \) as \( n \to \infty \).
3Step 3: Formulate the Equation
Since \(a_n \) converges to \( L \), it follows from the sequence definition that \( L = \sqrt{1 + L} \).
4Step 4: Solve the Equation
To solve \( L = \sqrt{1 + L} \), square both sides to eliminate the square root: \( L^2 = 1 + L \). Rearrange the terms to form a quadratic equation: \( L^2 - L - 1 = 0 \).
5Step 5: Apply the Quadratic Formula
Use the quadratic formula \( L = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \) where \( a=1, b=-1, c=-1\). This gives \( L = \frac{1 \pm \sqrt{1 + 4}}{2} = \frac{1 \pm \sqrt{5}}{2} \).
6Step 6: Select the Appropriate Solution
The only meaningful solution in this context is \( L = \frac{1 + \sqrt{5}}{2} \), since the sequence terms are positive and increasingly larger.
Key Concepts
Convergence of SequencesNested RadicalsQuadratic Equation Solutions
Convergence of Sequences
Have you ever noticed how some patterns settle down to a single value as they grow? That's precisely what's happening when we talk about the convergence of sequences. In mathematics, a sequence is simply an ordered list of numbers. As we keep listing these numbers, sometimes they approach what is called a "limit." Imagine getting closer and closer to a destination without ever stepping back.
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A sequence converges if, as we move through the sequence, the numbers get arbitrarily close to a specific number that we call the limit. Here are some key points to understand:
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A sequence converges if, as we move through the sequence, the numbers get arbitrarily close to a specific number that we call the limit. Here are some key points to understand:
- The limit is the value that the terms of the sequence "aim" towards as the sequence progresses.
- It is assumed that the sequence approaches the limit smoothly without any jumps or interruptions.
- Exploring the limit often involves rigorous proof to ensure that it remains consistent within the sequence's context.
Nested Radicals
Nested radicals, sometimes called repeated radicals, look complicated but can carry a lot of meaningful structure. Imagine having a situation where a square root is inside another square root repeatedly. That's a nested radical. For example, \( \sqrt{1}, \sqrt{1 + \sqrt{1}}, \sqrt{1 + \sqrt{1 + \sqrt{1}}}, \dots \)
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Understanding them involves recognizing a chain-like dependency between each term: the next term includes the previous one inside a square root. Here are some things to consider:
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Understanding them involves recognizing a chain-like dependency between each term: the next term includes the previous one inside a square root. Here are some things to consider:
- Start by understanding the first few terms because they lay the groundwork for the entire sequence.
- Each subsequent term is created by inserting the previous term into the square root, meaning new levels of complexity arise as more terms are added.
- Nesting often leads to sequences that are interesting in nature because they can converge to a finite limit even though they may appear infinite.
Quadratic Equation Solutions
Solving equations is like finding the paths of certain curves. Quadratic equations, which take the form \( ax^2 + bx + c = 0 \), describe a parabola. Fortunately, we have a reliable tool called the quadratic formula to find solutions:
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This method demonstrates how a variety of equations, including those emerging from converging sequences, can be approached and solved using consistent mathematical techniques.
- \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)
- This formula allows us to quickly calculate the roots of any quadratic equation.
- Depending on the discriminant \( (b^2 - 4ac) \), solutions might be real and distinct, real and repeated, or complex.
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This method demonstrates how a variety of equations, including those emerging from converging sequences, can be approached and solved using consistent mathematical techniques.
Other exercises in this chapter
Problem 96
In Exercises \(91-98\) , assume that each sequence converges and find its limit. $$ a_{1}=3, \quad a_{n+1}=12-\sqrt{a_{n}} $$
View solution Problem 97
In Exercises \(91-98\) , assume that each sequence converges and find its limit. $$ 2,2+\frac{1}{2}, 2+\frac{1}{2+\frac{1}{2}}, 2+\frac{1}{2+\frac{1}{2+\frac{1}
View solution Problem 99
The first term of a sequence is \(x_{1}=1 .\) Each succeeding term is the sum of all those that come before it: $$x_{n+1}=x_{1}+x_{2}+\dots+x_{n}$$ Write out en
View solution Problem 100
A sequence of rational numbers is described as follows: $$\frac{1}{1}, \frac{3}{2}, \frac{7}{5}, \frac{17}{12}, \ldots, \frac{a}{b}, \frac{a+2 b}{a+b}, \ldots$$
View solution