Problem 98
Question
\(\frac{5 p^{8}}{100 p^{13}}\)
Step-by-Step Solution
Verified Answer
\frac{1}{20p^5}
1Step 1 - Simplify the Coefficients
First, separate the numerical coefficients from the variable terms. The fraction for the numerical coefficients is \ \( \frac{5}{100} \ \).
2Step 2 - Reduce the Numerical Coefficient
Simplify \ \( \frac{5}{100} \ \) by dividing the numerator and the denominator by their greatest common divisor, which is 5. This gives \ \( \frac{5 \div 5}{100 \div 5} = \frac{1}{20} \ \).
3Step 3 - Simplify the Variable's Exponents
For the variable terms \ \( \frac{p^8}{p^{13}} \ \), use the property of exponents \ \( \frac{a^m}{a^n} = a^{m-n} \ \) to get \ \( p^{8-13} = p^{-5} \ \).
4Step 4 - Combine Results
Combine the simplified coefficients and variable terms: \ \( \frac{1}{20} \times p^{-5} = \frac{1}{20p^5} \ \).
Key Concepts
fraction simplificationgreatest common divisorexponent propertiescombining results
fraction simplification
When faced with a fraction, always start by simplifying it. In our example, \(\frac{5p^{8}}{100p^{13}}\), you have both numerical coefficients and variable terms.
Begin with separating the numbers from the variables. Look at \(\frac{5}{100}\) and \(\frac{p^{8}}{p^{13}}\).
This makes your job easier, as you can handle the numerical part and the variable part separately. Therefore, understand that simplifying fractions means reducing both numbers and variables individually.
Begin with separating the numbers from the variables. Look at \(\frac{5}{100}\) and \(\frac{p^{8}}{p^{13}}\).
This makes your job easier, as you can handle the numerical part and the variable part separately. Therefore, understand that simplifying fractions means reducing both numbers and variables individually.
greatest common divisor
To simplify a fraction like \(\frac{5}{100}\), find the Greatest Common Divisor (GCD) of the numerator and the denominator.
The GCD is the largest number that divides both without a remainder.
Here, the GCD of 5 and 100 is 5.
By dividing both the numerator and the denominator by their GCD, you get \(\frac{5 \div 5}{100 \div 5} = \frac{1}{20}\).
This dramatically simplifies your fraction effortlessly.
The GCD is the largest number that divides both without a remainder.
Here, the GCD of 5 and 100 is 5.
By dividing both the numerator and the denominator by their GCD, you get \(\frac{5 \div 5}{100 \div 5} = \frac{1}{20}\).
This dramatically simplifies your fraction effortlessly.
exponent properties
Exponents follow specific rules that make simplification easier. One key property for division is \(\frac{a^m}{a^n} = a^{m-n}\).
This rule helps to manage terms like \(\frac{p^8}{p^{13}}\) because you can simply subtract the exponents: \(p^{8-13} = p^{-5}\).
Notice that the exponent changes into a negative because you're taking a larger power away from a smaller power.
This rule helps to manage terms like \(\frac{p^8}{p^{13}}\) because you can simply subtract the exponents: \(p^{8-13} = p^{-5}\).
Notice that the exponent changes into a negative because you're taking a larger power away from a smaller power.
combining results
Once simplified, combine both your results to get the final answer.
From the previous steps, we have \(\frac{1}{20}\) from the numerical simplification and \(p^{-5}\) from the exponent properties.
Multiplying these together gives \(\frac{1}{20} \times p^{-5}\).
Since \(p^{-5}\) can be rewritten as \(\frac{1}{p^5}\), the final expression is \(\frac{1}{20p^5}\).
This is how you combine results to finish your simplification process.
From the previous steps, we have \(\frac{1}{20}\) from the numerical simplification and \(p^{-5}\) from the exponent properties.
Multiplying these together gives \(\frac{1}{20} \times p^{-5}\).
Since \(p^{-5}\) can be rewritten as \(\frac{1}{p^5}\), the final expression is \(\frac{1}{20p^5}\).
This is how you combine results to finish your simplification process.
Other exercises in this chapter
Problem 97
\(P=\frac{3.5 \times 10^{2} \text { joule }}{2.5 \times 10^{-1} \mathrm{~s}}\)
View solution Problem 98
Problem: Simplify: \((3 p)(p+4)(p+2)\) $$ \text { Incorrect Answer: } \begin{aligned} &(3 p)(p+4)(p+2) \\ &=3 p(p+4)+3 p(p+2) \\ &=3 p(p)+3 p(4)+3 p(p)+3 p(2) \
View solution Problem 98
\(R=\frac{1.5 \times 10^{-6} \mathrm{ohm} \cdot \mathrm{m}}{3.6 \times 10^{-7} \mathrm{~m}^{2}}\)
View solution Problem 99
\(P=\left(5.0 \times 10^{-2} \mathrm{~kg}\right)\left(4.4 \times 10^{1} \frac{\mathrm{m}}{\mathrm{s}}\right)\)
View solution