Problem 97
Question
The root mean square velocity of one mole of a monoatomic gas having molar mass \(\mathrm{M}\) is \(u_{\mathrm{rms}}\). The relation between the average kinetic energy (E) of the gas and \(u_{r m}\) is (a) \(\mathrm{u}_{\mathrm{rm}}=\sqrt{(3 \mathrm{E} / 2 \mathrm{M})}\) (b) \(\mathrm{u}_{\mathrm{ms}}=\sqrt{(2 \mathrm{E} / 3 \mathrm{M})}\) (c) \(\mathrm{u}_{\mathrm{mas}}=\sqrt{(2 \mathrm{E} / \mathrm{M})}\) (d) \(u_{\operatorname{me}}=\sqrt{(E / 3 M)}\)
Step-by-Step Solution
Verified Answer
The correct relation is (c) \(u_{rms} = \sqrt{\frac{2E}{M}}\).
1Step 1: Formula for Root Mean Square Velocity
The root mean square (RMS) velocity of a gas is given by the formula: \[u_{rms} = \sqrt{\frac{3RT}{M}}\] where \(R\) is the gas constant, \(T\) is the temperature in Kelvin, and \(M\) is the molar mass.
2Step 2: Formula for Average Kinetic Energy
The average kinetic energy \(E\) for one mole of a monoatomic gas is given by: \[E = \frac{3}{2}RT\].
3Step 3: Relate RMS Velocity with Kinetic Energy
We know that \(u_{rms} = \sqrt{\frac{3RT}{M}}\) and \(E = \frac{3}{2}RT\). Solve for \(RT\) from the kinetic energy formula: \[RT = \frac{2E}{3}\].
4Step 4: Substitute to Find u_{rms} in Terms of E
Substitute \(RT = \frac{2E}{3}\) into the RMS velocity formula: \[u_{rms} = \sqrt{\frac{3(\frac{2E}{3})}{M}} = \sqrt{\frac{2E}{M}}\]. This matches option (c).
Key Concepts
Kinetic Energy of GasesMolar MassGas Laws
Kinetic Energy of Gases
Understanding the kinetic energy of gases is crucial in exploring the behavior of gases under various conditions. In physics and chemistry, kinetic energy refers to the energy that an object possesses due to its motion. For gases, this concept helps explain how their temperature relates to their internal energy.In the context of monoatomic gases, the average kinetic energy per mole is given by the formula: \[ E = \frac{3}{2} RT \]where:
- \(E\) is the average kinetic energy,
- \(R\) is the universal gas constant (approximately 8.314 J/mol·K), and
- \(T\) is the temperature in Kelvin.
Molar Mass
Molar mass, a fundamental property of substances, refers to the mass of one mole of a substance and is expressed in grams per mole (g/mol). It plays a significant role when studying gases, particularly in the context of the root mean square velocity and other properties that depend on the mass of gas molecules.To find the molar mass, one usually adds the atomic masses of all atoms in a molecule. For example, the molar mass of oxygen (O₂) is calculated by adding the atomic masses of two oxygen atoms, each approximately 16 g/mol, which results in a molar mass of 32 g/mol.The molar mass affects the root mean square velocity, given by the formula:\[ u_{rms} = \sqrt{\frac{3RT}{M}} \]Here:
- \(M\) represents the molar mass,
- \(R\) is the gas constant, and
- \(T\) is the temperature in Kelvin.
Gas Laws
Gas laws are a set of relationships that describe how gases behave under various conditions. These laws—derived from experimental observations—help predict the properties of gases and establish connections between variables such as temperature, pressure, volume, and number of particles.Some of the crucial gas laws include:
- **Boyle's Law**: This law states that the pressure of a fixed amount of gas at constant temperature is inversely proportional to its volume. Mathematically, it's expressed as \(PV = \text{constant}\).
- **Charles's Law**: According to Charles's Law, the volume of a fixed quantity of gas is directly proportional to its temperature (in Kelvin) when the pressure is kept constant. This is given by \(\frac{V}{T} = \text{constant}\).
- **Avogadro's Law**: This law posits that equal volumes of gases, at the same temperature and pressure, contain equal numbers of molecules, \(\frac{V}{n} = \text{constant}\), where \(n\) is the number of moles.
- **Ideal Gas Law**: Combining the previous laws, the ideal gas law provides a more general relationship: \(PV = nRT\). Here, \(n\) is the number of moles of the gas.
Other exercises in this chapter
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