Problem 97
Question
The half-life of a chemical reaction at a particular concentration is \(50 \mathrm{~min}\), when the concentration of reactants is doubled, the half-life becomes \(100 \mathrm{~min}\). Find the order. (a) zero (b) first (c) second (d) third
Step-by-Step Solution
Verified Answer
The order of the reaction is second, corresponding to option (c).
1Step 1: Understand reaction order concept
In chemical kinetics, the order of a reaction refers to the power to which the concentration of a reactant is raised in the rate equation. Half-life, which is the time needed for a reactant concentration to reduce to half its initial value, depends differently on concentrations based on the order of the reaction.
2Step 2: Analyze given half-life data
We are given two half-life times: 50 minutes and 100 minutes. Initially, the half-life is 50 minutes, and when the concentration of reactants is doubled, the half-life becomes 100 minutes. This change in half-life duration with a change in concentration will help determine the order of the reaction.
3Step 3: Apply half-life relation for order determination
For a zero-order reaction, half-life is inversely proportional to initial concentration; for a first-order reaction, half-life is constant; for a second-order reaction, half-life is directly proportional to the initial concentration. For this problem, the half-life doubles when the concentration is doubled, which indicates a second-order reaction where \[ t_{1/2} \propto \frac{1}{[A]}\].
4Step 4: Conclude the reaction order
The doubling of the half-life when the concentration is doubled is consistent with the behavior of a second-order reaction. This verifies that the reaction's half-life directly depends on the initial concentration, confirming the order of the reaction is second.
Key Concepts
Reaction OrderHalf-LifeSecond-Order Reaction
Reaction Order
Reaction order is a fundamental concept in chemical kinetics, helping us understand how a reaction's rate depends on the concentration of reactants. It reflects the sum of powers to which the concentration terms are raised in the rate equation. For example, in the rate equation \[ rate = k[A]^m[B]^n \]"m" and "n" represent the reaction orders with respect to reactants A and B.
- A reaction order of zero means that the rate is independent of the concentration of the reactants.
- A first-order reaction means the reaction rate is directly proportional to the concentration of one reactant.
- The second-order reaction implies that the rate is proportional to the square of the concentration of one reactant or to the product of the concentrations of two reactants.
Half-Life
The half-life of a chemical reaction is the time it takes for half of the reactant to be consumed. It provides insight into the speed of a reaction and is particularly useful for understanding kinetic behaviors. The relationship between half-life and concentration varies depending on the order of the reaction.
- **Zero-order reactions** have a half-life that decreases with decreasing concentration, specifically, it's inversely proportional to the initial concentration.
- **First-order reactions** feature a constant half-life that remains unchanged regardless of concentration. This characteristic makes isotopic decay processes fall under first-order reactions.
- **Second-order reactions** have a half-life that is inversely proportional to the initial concentration, so as the concentration increases, the half-life decreases, and vice versa.
In the exercise, as the concentration of the reactant is doubled and the half-life doubles, this unique relationship confirms a second-order reaction.
Second-Order Reaction
Second-order reactions are characterized by a reaction rate proportional to either the square of the concentration of a single reactant or the product of concentrations of two different reactants. The rate law for a simple second-order reaction can be expressed as:\[rate = k[A]^2\]Or, in the case involving two reactants, it may look like:\[rate = k[A][B]\]The half-life equation for a second-order reaction is:\[t_{1/2} = \frac{1}{k[A]_0}\]Here, \([A]_0\) is the initial concentration, and "k" is the rate constant. This relationship implies that as the reactant concentration increases, the half-life decreases, which explains why doubling the concentration also doubles the half-life in our exercise.In a laboratory or industrial setting, understanding second-order reactions helps in adjusting concentrations to control reaction times and ensure optimal product yields.
Other exercises in this chapter
Problem 93
In a first-order reaction the concentration of reactant decreases from \(800 \mathrm{~mol} / \mathrm{dm}^{3}\) to \(50 \mathrm{~mol} / \mathrm{dm}^{3}\) in \(2
View solution Problem 96
Which of the following statements is correct? (1) order of a reaction can be known from experimental results and not from the stoichiometry of a reaction. (2) m
View solution Problem 98
The half-life of a chemical reaction at a particular concentration is \(50 \mathrm{~min}\), when the concentration of reactants is doubled, the half-life become
View solution Problem 100
If the half life period of a radioactive isotope is \(10 \mathrm{~s}\), then its average life will be (a) \(14.4 \mathrm{~s}\) (b) \(1.44 \mathrm{~s}\) (c) \(0.
View solution