Problem 97
Question
In waterskiing, a "garage sale" occurs when a skier loses control and falls and waterskis fly in different directions. In one particular incident, a novice skier was skimming across the surface of the water at \(22.0 \mathrm{~m} / \mathrm{s}\) when he lost control. One ski, with a mass of \(1.50 \mathrm{~kg},\) flew off at an angle of \(12.0^{\circ}\) to the left of the initial direction of the skier with a speed of \(25.0 \mathrm{~m} / \mathrm{s}\). The other identical ski flew from the crash at an angle of \(5.00^{\circ}\) to the right with a speed of \(21.0 \mathrm{~m} / \mathrm{s} .\) What was the velocity of the \(61.0-\mathrm{kg}\) skier? Give a speed and a direction relative to the initial velocity vector.
Step-by-Step Solution
Verified Answer
Answer: To find the final velocity of the skier, first calculate the initial momentum of the skier and the momenta of the flying water skis using the given information. Then, apply the conservation of momentum principle to find the final momentum of the skier. Divide the final momentum of the skier by the skier's mass to get the final velocity. The final speed and direction can then be calculated using the magnitudes and inverse tangent function, respectively.
1Step 1: Identify the initial momentum of the skier
Before falling, the skier is moving at a velocity of \(22.0 m/s\). The mass of the skier is \(61.0 kg\). Therefore, we can calculate the initial momentum of the skier as follows:
Initial momentum of skier = mass * velocity = \(61.0 kg \times 22.0 m/s = 1342 kg\cdot m/s\)
2Step 2: Compute the momentum of water skis
Let's compute the momenta of the flying water skis:
Both skis have a mass of \(1.50 kg\).
The first ski is flying at \(25.0 m/s\) at an angle of \(12.0^\circ\) to the left and the second ski is flying at \(21.0 m/s\) at an angle of \(5.0^\circ\) to the right of the initial direction of the skier.
To find the momentum of each ski, we have to resolve the velocity vector of each ski into its horizontal and vertical components.
- For the first ski:
Horizontal component = \(25 \cos(12^\circ)\)
Vertical component = \(25 \sin(12^\circ)\)
- For the second ski:
Horizontal component = \(21 \cos(5^\circ)\)
Vertical component = \(21 \sin(5^\circ)\)
The momentum of each ski can then be computed as follows:
- Momentum of the first ski = \((1.5 kg)(25\cos(12^\circ)\hat{i} + 25\sin(12^\circ)\hat{j})\)
- Momentum of the second ski = \((1.5 kg)(21\cos(5^\circ)\hat{i} + 21\sin(5^\circ)\hat{j})\)
3Step 3: Apply the conservation of momentum
The total initial momentum equals the total final momentum. That is, the initial momentum of the skier is equal to the sum of the final momentum of the skier and the momenta of the flying water skis. Therefore, the final momentum of the skier can be calculated as follows:
Final momentum of skier = Initial momentum of skier - (momentum of first ski + momentum of second ski)
Final momentum of skier = \(1342\hat{i} kg\cdot m/s - [(1.5 kg)(25\cos(12^\circ)\hat{i} + 25\sin(12^\circ)\hat{j}) + (1.5 kg)(21\cos(5^\circ)\hat{i} + 21\sin(5^\circ)\hat{j})]\)
Now, calculate the horizontal and vertical components of the final momentum of the skier.
4Step 4: Calculate the final velocity of the skier
Now that we have the final momentum of the skier, we can find the final velocity of the skier by dividing the final momentum by the mass of the skier:
Final velocity of skier = \(\frac{Final~momentum~of~skier}{mass~of~skier}\) = \(\frac{Final~momentum~of~skier}{61.0 kg}\)
To find the final speed of the skier, we will find the magnitude of the final velocity vector:
Speed of the skier = \(|\textrm{Final velocity of skier}| = \sqrt{(Final~Horizontal~Component)^2 + (Final~Vertical~Component)^2}\)
To find the direction of the skier with respect to the initial velocity vector, we use the inverse tangent (arctan) function:
Direction of the skier = \(tan^{-1}\left(\frac{Final~Vertical~Component}{Final~Horizontal~Component}\right)\)
Calculate the final speed and direction of the skier using the computed values.
Key Concepts
Vector ComponentsProblem SolvingPhysics Applications
Vector Components
Understanding vector components is crucial in physics, particularly when analyzing motion in different directions. A vector has both magnitude and direction, making it essential to break it down into more manageable parts for calculations.
In our example, we calculated the motion of the skis after the skier fell. Each ski flies off at an angle to the initial direction of travel. To analyze these motions effectively, we resolve the velocity of each ski into horizontal (x-component) and vertical (y-component) components. This is done using trigonometric functions, sine and cosine:
In our example, we calculated the motion of the skis after the skier fell. Each ski flies off at an angle to the initial direction of travel. To analyze these motions effectively, we resolve the velocity of each ski into horizontal (x-component) and vertical (y-component) components. This is done using trigonometric functions, sine and cosine:
- Horizontal component is given by multiplying the speed by the cosine of the angle ( \( \text{velocity} \times \cos(\theta) \))
- Vertical component is found using the sine of the angle ( \( \text{velocity} \times \sin(\theta) \))
Problem Solving
Problem-solving in physics often involves creative thinking and careful calculations. The key to success usually lies in clearly understanding the problem and applying the relevant principles effectively.
In the given exercise, solving the problem involves several steps:
In the given exercise, solving the problem involves several steps:
- Calculating the initial momentum of the skier, which is straightforward (mass multiplied by velocity).
- Finding momentum vectors of the skis by resolving their velocities into components and multiplying by mass.
- Using the conservation of momentum, which states that the total momentum before an event is equal to the total momentum after it, to find the missing information regarding the skier's velocity after the skis fly off.
Physics Applications
Physics has real-world applications which, when seen through exercises like this, become more tangible and understandable. The conservation of momentum is one of the fundamental principles applicable to various phenomena, from vehicle collisions to sports incidents like water skiing crashes.
This principle allows us to predict the outcomes after events like our skier's fall. Recognizing that total momentum must remain constant tells us how different parts of the system—here, the skier and skis—move after a crash. Additionally, understanding vector components is necessary for accurately describing physical phenomena which occur in multiple directions.
By studying physics through practical applications, we gain valuable insights into how concepts like momentum and vector components interact in scenarios encountered in real life, thus improving both our problem-solving skills and our grasp of the physical world.
This principle allows us to predict the outcomes after events like our skier's fall. Recognizing that total momentum must remain constant tells us how different parts of the system—here, the skier and skis—move after a crash. Additionally, understanding vector components is necessary for accurately describing physical phenomena which occur in multiple directions.
By studying physics through practical applications, we gain valuable insights into how concepts like momentum and vector components interact in scenarios encountered in real life, thus improving both our problem-solving skills and our grasp of the physical world.
Other exercises in this chapter
Problem 93
A 170.-g hockey puck moving in the positive \(x\) direction at \(30.0 \mathrm{~m} / \mathrm{s}\) is struck by a stick at time \(t=2.00 \mathrm{~s}\) and moves i
View solution Problem 96
After several large firecrackers have been inserted into its holes, a bowling ball is projected into the air using a homemade launcher and explodes in midair. D
View solution Problem 98
An uncovered hopper car from a freight train rolls without friction or air resistance along a level track at a constant speed of \(6.70 \mathrm{~m} / \mathrm{s}
View solution Problem 99
When a \(99.5-\mathrm{g}\) slice of bread is inserted into a toaster, the toaster's ejection spring is compressed by \(7.50 \mathrm{~cm}\). When the toaster eje
View solution