Problem 97
Question
If, \(A, B, C\) be the centres of three coaxal circles and \(t_{1}, t_{2}, t_{3}\) be the tangents to them from any point, then \(B C \cdot t_{1}^{2}+C A \cdot t_{2}^{2}+A B \cdot t_{3}^{2}\) (A) 0 (B) 1 (C) \(-1\) (D) none of these
Step-by-Step Solution
Verified Answer
The expression evaluates to 0.
1Step 1: Understanding the Problem
We need to evaluate the expression \(B C \cdot t_{1}^{2}+C A \cdot t_{2}^{2}+A B \cdot t_{3}^{2}\), where \(t_1, t_2, t_3\) are tangents from a point to three coaxial circles with centers \(A, B, C\). We need to find which value among the given options the expression evaluates to.
2Step 2: Using the Power of a Point Theorem
The power of a point theorem states that the power of a point relative to a circle entails the relation \(t^2 = OP^2 - r^2\), where \(OP\) is the distance from the point to the circle center and \(r\) is the radius. Applying to all circles, we have: \(t_1^2 = PA^2 - R_1^2\), \(t_2^2 = PB^2 - R_2^2\), \(t_3^2 = PC^2 - R_3^2\).
3Step 3: Relating Tangents to Distances
For coaxial circles, the pivotal property is that the differences between their squared radii remain constant across any pair of circles. Hence, if \(A, B, C\) form a line, \(BC = AB + AC\) or any other following properties influence each tangent squared term resulting in telescopic cancellations when summed.
4Step 4: Substituting Relations
Since \(t_1^2, t_2^2, t_3^2\) can be exactly expressed with differences relative to coaxial properties, substituting these relations into \(B C \cdot t_{1}^{2}+C A \cdot t_{2}^{2}+A B \cdot t_{3}^{2}\) effectively simplifies, resulting in the equation eliminating radii terms, resulting in perfect zeroes through subtraction.
5Step 5: Evaluating the Expression
After substituting, the expression \(B C \cdot t_{1}^{2}+C A \cdot t_{2}^{2}+A B \cdot t_{3}^{2}\) simplifies to zero due to the coaxial alignment and cancellation of all respective squared radius relations.
Key Concepts
Coaxial CirclesCircle GeometryTelescopic Sum
Coaxial Circles
Coaxial circles, or coaxal circles, refer to a system of circles that share the same line, known as their axis. The axis can either be a real line or an imaginary line if the circles are considered in complex planes. A unique characteristic of coaxial circles is that every pair of circles in the system has the same radical axis—a line that is perpendicular to the line joining their centers and is equidistant from all pairs of intersecting circles.
Understanding coaxial circles is important since their setup creates predictable geometric properties, such as constant differences between their squared radii regardless of the specific pair of circles in the system. This property simplifies the calculation of expressions involving tangents from a common external point to these circles. Such simplifications play a vital role in solving problems related to the Power of a Point and telescopic sum cancellations as seen in the exercise.
Understanding coaxial circles is important since their setup creates predictable geometric properties, such as constant differences between their squared radii regardless of the specific pair of circles in the system. This property simplifies the calculation of expressions involving tangents from a common external point to these circles. Such simplifications play a vital role in solving problems related to the Power of a Point and telescopic sum cancellations as seen in the exercise.
Circle Geometry
Circle geometry focuses on properties and relationships related to circles, involving points, lines, and angles related to circles. A core concept here is the Power of a Point theorem, a powerful result used for solving problems with tangents and distances.
This theorem states that for any point outside a circle, the square of the length of a tangent drawn from that point to the circle is equal to the difference between the square of the distance from the point to the center and the square of the radius. If a point is outside multiple circles, as with coaxial circles, this theorem applies repeatedly, simplifying expressions involving tangents significantly.
This theorem states that for any point outside a circle, the square of the length of a tangent drawn from that point to the circle is equal to the difference between the square of the distance from the point to the center and the square of the radius. If a point is outside multiple circles, as with coaxial circles, this theorem applies repeatedly, simplifying expressions involving tangents significantly.
- To apply the Power of a Point in problems, determine the distance from the point to each circle's center and know the radii.
- Another critical factor in circle geometry is understanding how to leverage properties of symmetry and aligned centers (as seen in the exercise) for problem simplification.
Telescopic Sum
A telescopic sum is a series of numbers, terms, or expressions where most intermediate terms cancel each other out when expanded in a sequence. This concept is invaluable for simplifying complicated arithmetic or algebraic expressions, often reducing them to simpler terms or even zero.
In the context of the given exercise, the expression involving tangent lengths squared simplifies due to the property of coaxial circles. Each tangent squared term is paired with distances and radius squares that align in such a way that they form a telescopic sum. Here’s how it typically works:
In the context of the given exercise, the expression involving tangent lengths squared simplifies due to the property of coaxial circles. Each tangent squared term is paired with distances and radius squares that align in such a way that they form a telescopic sum. Here’s how it typically works:
- The matching algebraic terms cancel due to properties relating tangents and distances in coaxial circles.
- For example, in the expression: \(BC \cdot t_1^2 + CA \cdot t_2^2 + AB \cdot t_3^2\), the squared tangent expressions derive from distance equations \(PA^2, PB^2,\) etc., with coaxial properties ensuring cancellation.
Other exercises in this chapter
Problem 94
The pole of the chord of the circle \(x^{2}+y^{2}=16\) which is bisected at the point \((-2,3)\), with respect to the circle is (A) \(\left(\frac{-32}{13}, \fra
View solution Problem 95
The coordinates of the poles of the common chord of the circles \(x^{2}+y^{2}=12\) and \(x^{2}+y^{2}-5 x+2 y-2=0\) with respect to the circle \(x^{2}+y^{2}=12\)
View solution Problem 98
The limiting points of the coaxal system determined by the circles \(x^{2}+y^{2}-2 x-6 y+9=0\) and \(x^{2}+y^{2}+6 x\) \(-2 y+1=0\) are (A) \((-1,2),\left(\frac
View solution Problem 99
The equation of the circle which passes through the origin and belongs to the coaxal system whose limiting points are \((1,2)\) and \((4,3)\), is (A) \(2 x^{2}+
View solution