Problem 97
Question
Evaluate each expression. \(\frac{6-2(-3)}{4-3(-2)}\)
Step-by-Step Solution
Verified Answer
The expression simplifies to \(\frac{6}{5}\).
1Step 1: Distribute the negative sign
First, distribute the negative signs inside the parentheses in both the numerator and the denominator of the fraction. For the numerator, we have \(-2(-3)\). Distributing the negative sign gives us \(+6\). So, the numerator is now \(6 + 6\). For the denominator, \(-3(-2)\) becomes \(+6\), turning it into \(4 + 6\).
2Step 2: Simplify the expressions
Now, simplify the expressions obtained in Step 1. The numerator becomes \(6 + 6 = 12\). The denominator becomes \(4 + 6 = 10\).
3Step 3: Divide the simplified values
Finally, divide the simplified numerator by the simplified denominator to solve the expression: \(\frac{12}{10}\).
4Step 4: Simplify the fraction
Simplify the fraction \(\frac{12}{10}\) by dividing both the numerator and the denominator by their greatest common divisor, which is \(2\). This gives \(\frac{12 \div 2}{10 \div 2} = \frac{6}{5}\).
Key Concepts
Distributive PropertySimplifying FractionsOrder of Operations
Distributive Property
When faced with expressions that contain operations inside parentheses, the distributive property is a powerful tool to simplify them. This principle states that multiplying a sum or difference by a number is the same as doing each multiplication separately. For instance, the distributive property for
This is crucial when simplifying complex expressions, as it allows the elimination of parentheses and simplifies the calculation process. Here, applying the distributive property helped us to transform the expression inside the parentheses to another, easier-to-use form, ultimately simplifying the algebraic expression greatly.
- numerator as \( -2(-3) \) and
- denominator as \( -3(-2) \)
This is crucial when simplifying complex expressions, as it allows the elimination of parentheses and simplifies the calculation process. Here, applying the distributive property helped us to transform the expression inside the parentheses to another, easier-to-use form, ultimately simplifying the algebraic expression greatly.
Simplifying Fractions
Once you've worked through an expression and have a fraction to work with, simplification is key to getting the simplest form of your answer. Simplifying fractions means dividing both the numerator and the denominator by their greatest common divisor (GCD).
In our exercise, we reached the fraction \( \frac{12}{10} \). The GCD of 12 and 10 is 2. So, we divide the numerator and the denominator by 2 to simplify this fraction, resulting in \( \frac{6}{5} \).
Always remember, finding the GCD can sometimes involve prime factorization or just recognizing common factors for speed and efficiency.
In our exercise, we reached the fraction \( \frac{12}{10} \). The GCD of 12 and 10 is 2. So, we divide the numerator and the denominator by 2 to simplify this fraction, resulting in \( \frac{6}{5} \).
- This step ensures that your answer is in its simplest form.
- Simplified fractions are crucial in algebra because they are easier to work with and understand.
Always remember, finding the GCD can sometimes involve prime factorization or just recognizing common factors for speed and efficiency.
Order of Operations
Solving any algebraic expression requires a strict adherence to the order of operations, often recalled by the acronym PEMDAS:
In this exercise, after using the distributive property, we continued to use the order of operations to solve the expression inside the fraction. First, the operations within the parentheses were resolved. Following that, the results were simplified. This orderly process is essential not just for getting the correct answer, but also for understanding the flow and structure of solving equations in algebra.
Adhering to the order of operations is fundamental in avoiding common pitfalls and errors in solutions, ensuring clarity and accuracy.
- Parentheses
- Exponents
- Multiplication and Division (from left to right)
- Addition and Subtraction (from left to right)
In this exercise, after using the distributive property, we continued to use the order of operations to solve the expression inside the fraction. First, the operations within the parentheses were resolved. Following that, the results were simplified. This orderly process is essential not just for getting the correct answer, but also for understanding the flow and structure of solving equations in algebra.
Adhering to the order of operations is fundamental in avoiding common pitfalls and errors in solutions, ensuring clarity and accuracy.
Other exercises in this chapter
Problem 97
Each calculation below is incorrect. Find the error and correct it. $$ 9-(-7) \stackrel{?}{=} 2 $$
View solution Problem 97
Are parentheses necessary in the expression \(2+(3 \cdot 5) ?\) Explain your answer.
View solution Problem 98
Each calculation below is incorrect. Find the error and correct it. $$ -4-8 \stackrel{?}{=} 4 $$
View solution Problem 98
Are parentheses necessary in the expression \((2+3) \cdot 5 ?\) Explain your answer.
View solution