Problem 97
Question
Determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false. If \(F\) and \(G\) are antiderivatives of \(f\) on an interval \(I\), then \(F(x)=G(x)+C\) on \(I\).
Step-by-Step Solution
Verified Answer
The statement is true. If \(F\) and \(G\) are antiderivatives of the same function \(f\) on the interval \(I\), then \(F(x) = G(x) + C\) on \(I\), for some constant \(C\). This is proven by defining \(H(x)=F(x)-G(x)\), showing that \(H'(x)=0\), and applying the constant function rule.
1Step 1: Properties of Antiderivatives
We are given that \(F\) and \(G\) are antiderivatives of the function \(f\) on the interval \(I\). From the definition of antiderivatives, we know that if \(F'(x)=f(x)\) and \(G'(x)=f(x)\) on \(I\).
2Step 2: Comparing Their Derivatives
Since we know that both antiderivatives \(F\) and \(G\) satisfy the condition \(F'(x)=f(x)\) and \(G'(x)=f(x)\) on the interval \(I\), we will now compare their derivatives:
\[F'(x) = G'(x)\]
This must be true for all values of \(x\) in the interval \(I\).
3Step 3: Finding the Difference
Now, let's introduce a new function, say \(H(x)=F(x)-G(x)\). Now, differentiate this function with respect to \(x\):
\[H'(x) = F'(x) - G'(x)\]
Since we know \(F'(x) = G'(x)\), we can substitute this into the equation above:
\[H'(x) = F'(x) - F'(x) = 0\]
This means that the function \(H(x)\) has a constant derivative of 0.
4Step 4: Constant Function Rule
Since we have shown that \(H'(x)=0\), we can now apply the constant function rule. The constant function rule states that if a function has a constant derivative of 0, then the function is a constant function. Thus, \(H(x)\) is constant on the interval \(I\). Consequently, we have:
\[H(x) = F(x) - G(x) = C\Rightarrow F(x)=G(x) + C\]
where \(C\) is a constant.
5Step 5: Conclusion
We have proven that if \(F\) and \(G\) are antiderivatives of the same function \(f\), then \(F(x) = G(x) + C\) on the interval \(I\), for some constant \(C\). Therefore, the statement is true.
Key Concepts
Constant Function RuleInterval AnalysisDifferentiation
Constant Function Rule
The constant function rule is a fundamental concept in calculus. It states that if the derivative of a function is zero across an interval, then the function itself is constant over that interval. This idea helps us understand situations involving antiderivatives. In the exercise mentioned, we see that two antiderivatives, \(F\) and \(G\), of a function \(f\) have their derivatives equal when compared:
- If \(F'(x) = G'(x)\) for all \(x\) in an interval \(I\), then the difference \(H(x) = F(x) - G(x)\) has a derivative of zero: \(H'(x) = 0\).
- This zero derivative implies that \(H(x)\) is a constant, thus \(F(x) = G(x) + C\) for a constant \(C\).
Interval Analysis
Interval analysis is important when working with functions in calculus, especially when dealing with derivatives and integrals. An interval is a set of real numbers lying between two numbers called endpoints. Analyzing a function over an interval is crucial because:
- It allows understanding how a function behaves between two points.
- Limits the region where certain properties apply, including constant derivatives or antiderivatives.
Differentiation
Differentiation is the process of finding the derivative of a function. It is a core operation in calculus and provides a measure of how a function changes as its input changes. Differentiating a function helps in understanding the rate of change or slope at any particular point.Key points about differentiation include:
- The derivative of a function \(f(x)\) at a point \(x\) is often denoted as \(f'(x)\) or \(\frac{df}{dx}\).
- In an antiderivative context, if \(F'(x) = f(x)\), then \(F(x)\) is an antiderivative of \(f\).
Other exercises in this chapter
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