Problem 97
Question
Determine whether each pair of lines is parallel, perpendicular, or neither. $$2 x-4 y=9, \frac{1}{3} x=\frac{2}{3} y-8$$
Step-by-Step Solution
Verified Answer
The lines are parallel.
1Step 1 - Convert the equations to slope-intercept form
First, convert both equations into the slope-intercept form, which is given by: \[y = mx + b\]where \(m\) is the slope and \(b\) is the y-intercept.
2Step 2 - Convert the first equation
Starting with the first equation \(2x - 4y = 9\), rearrange it to the form \(y = mx + b\):\[2x - 4y = 9 \-4y = -2x + 9 \y = \frac{1}{2}x - \frac{9}{4}\]Here, the slope \(m\) is \(\frac{1}{2}\).
3Step 3 - Convert the second equation
Next, convert the second equation \(\frac{1}{3}x = \frac{2}{3}y - 8\) into the slope-intercept form:\[\frac{1}{3}x = \frac{2}{3}y - 8 \frac{1}{3}x + 8 = \frac{2}{3}y \8 = \frac{2}{3}y - \frac{1}{3}x \8 = \frac{2}{3}y - \frac{1}{3}x \2y = x - 24 \y = \frac{1}{2}x - 12\]Here, the slope \(m\) is also \(\frac{1}{2}\).
4Step 4 - Compare the slopes
Compare the slopes of the two lines obtained:\(m_1 = \frac{1}{2}\) and \(m_2 = \frac{1}{2}\).Since the slopes are equal, the lines are parallel.
Key Concepts
slope-intercept formslopes of linesequation conversion
slope-intercept form
To understand if lines are parallel or perpendicular, we first need to convert their equations into the slope-intercept form. The slope-intercept form is expressed as: \( y = mx + b \) where \( m \) represents the slope of the line, and \( b \) is the y-intercept.
By converting equations to this form, we can easily identify the slope and determine relationships between lines.
To convert any equation to slope-intercept form:
By converting equations to this form, we can easily identify the slope and determine relationships between lines.
To convert any equation to slope-intercept form:
- Isolate the \( y \) variable on one side.
- Ensure \( y \) is by itself and in the form of \( y = mx + b \).
slopes of lines
The slope of a line in the slope-intercept form \( y = mx + b \) is the coefficient \( m \) of the \( x \) term. A slope indicates how steep a line is.
Here are key points about slopes when comparing lines:
Here are key points about slopes when comparing lines:
- If two lines have the same slope, they are parallel. This means they never intersect and are equidistant.
In the exercise, both lines had slopes of \( \frac{1}{2} \) indicating they are parallel. - If the product of their slopes is \( -1 \), the lines are perpendicular. Perpendicular lines intersect at a right angle (90 degrees).
For example, if one line has a slope of \( \frac{3}{4} \), a line perpendicular to it would have a slope of \( - \frac{4}{3} \). - If the slopes are neither equal nor multiplied to \( -1 \), the lines are neither parallel nor perpendicular.
They will intersect at some angle other than 90 degrees.
equation conversion
Converting an equation to slope-intercept form involves straightforward algebraic manipulation. Let's look at the provided exercise step by step.
First, take the initial equation:
First, take the initial equation:
- For \( 2x - 4y = 9 \)
- Re-arrange terms to isolate \( y \) : \( -4y = -2x + 9 \)
- Divide entire equation by -4: \( y = \frac{1}{2}x - \frac{9}{4} \)
- For \( \frac{1}{3}x = \frac{2}{3}y - 8 \)
- Re-arrange terms to isolate \( y \): \( \frac{1}{3}x + 8 = \frac{2}{3}y \)
- Multiply through by 3 to clear fractions: \( x + 24 = 2y \)
- Solve for \( y \) : \( y = \frac{1}{2}x - 12 \)
Other exercises in this chapter
Problem 95
Determine whether each pair of lines is parallel, perpendicular, or neither. $$y=3 x-8, x+3 y=7$$
View solution Problem 96
Determine whether each pair of lines is parallel, perpendicular, or neither. $$y=\frac{1}{2} x-4, \frac{1}{2} x+\frac{1}{4} y=1$$
View solution Problem 97
Let \(f(x)=3 x-2, g(x)=-x^{2}+3 x-2,\) and \(h(x)=|x+2|\). Evaluate each expression. See Example 9. $$ f(2)+g(3) $$
View solution Problem 98
Determine whether each pair of lines is parallel, perpendicular, or neither. $$\frac{1}{4} x-\frac{1}{6} y=\frac{1}{3}, \frac{1}{3} y=\frac{1}{2} x-2$$
View solution