Problem 97
Question
Consider the following compounds:
Step-by-Step Solution
Verified Answer
Phenol is stronger due to the resonance-stabilized phenoxide ion.
1Step 1: Identify the compounds
The given compounds are phenol and methanol. Their chemical formulas are C₆H₅OH for phenol and CH₃OH for methanol.
2Step 2: Understand the acid-base reaction
When phenol or methanol donates a proton (H⁺), they form their respective conjugate bases, namely phenoxide ion (C₆H₅O⁻) and methoxide ion (CH₃O⁻). The stability of these conjugate bases determines the acidity of the original compounds.
3Step 3: Analyze the resonance stability of phenoxide
In phenol, the conjugate base is the phenoxide ion. It can undergo resonance because the negative charge on the oxygen is delocalized onto the aromatic ring. This delocalization leads to several resonance structures, making the phenoxide ion more stable.
4Step 4: Analyze the methoxide ion structure
Methanol, when it loses a proton, forms methoxide ion. This ion does not have any resonance structures since the negative charge is localized on the oxygen atom, making it less stable compared to the phenoxide ion.
5Step 5: Compare conjugate base stability
The resonance stabilization in the phenoxide ion makes it more stable than the methoxide ion, which lacks resonance. The greater stability of the phenoxide ion means that phenol is a stronger acid than methanol, as a more stable conjugate base promotes ionization.
Key Concepts
PhenolConjugate Base StabilityResonance Structures
Phenol
Phenol is an aromatic compound consisting of a hydroxyl group (-OH) attached to a benzene ring. This structure is important in acid-base chemistry because phenol can donate a proton (H⁺) from its hydroxyl group, forming the phenoxide ion
- Chemical Formula: C₆H₅OH
- Structure: Hydroxyl group (-OH) attached to an aromatic ring
Conjugate Base Stability
The stability of a conjugate base directly influences the acidity of a compound. More stable conjugate bases result in stronger acids as they favor dissociation. In the case of phenol and methanol:
- Phenol forms the phenoxide ion (C₆H₅O⁻) upon losing a proton.
- Methanol forms the methoxide ion (CH₃O⁻) when it loses a proton.
Resonance Structures
Resonance structures are critical for understanding the stability of the phenoxide ion formed from phenol. They demonstrate how the negative charge can be delocalized over a molecular structure, which in turn stabilizes the ion. In the phenoxide ion:
- The lone pair of electrons from the oxygen can be delocalized into the benzene ring.
- This delocalization results in multiple resonance structures.
Other exercises in this chapter
Problem 95
Compare the strengths of the following pairs of acids: (a) \(\mathrm{H}_{2} \mathrm{SO}_{4}\) and \(\mathrm{H}_{2} \mathrm{SeO}_{4}\) (b) \(\mathrm{H}_{3} \math
View solution Problem 96
Which of the following is the stronger acid: \(\mathrm{CH}, \mathrm{ClCOOH}\) or \(\mathrm{CHCl}_{2} \mathrm{COOH}\) ? Explain your choice.
View solution Problem 98
Define salt hydrolysis. Categorize salts according to how they affect the \(\mathrm{pH}\) of a solution.
View solution Problem 99
Explain why small, highly charged metal ions are able to undergo hydrolysis.
View solution