Problem 97
Question
Complete the following chemical equation. $$\mathrm{CuCl}_{2}(\mathrm{s})+\mathrm{Na}_{2} \mathrm{SO}_{4}(\mathrm{aq}) \rightarrow$$
Step-by-Step Solution
Verified Answer
The balanced chemical equation is \(\mathrm{CuCl}_{2}(\mathrm{s}) + \mathrm{Na}_{2}\mathrm{SO}_{4}(\mathrm{aq}) \rightarrow \mathrm{CuSO}_{4}(\mathrm{aq}) + 2\mathrm{NaCl}(\mathrm{aq})\).
1Step 1: Identify the reactants
In this chemical equation, we have copper(II) chloride, \(\mathrm{CuCl}_{2}(\mathrm{s})\), and sodium sulfate, \(\mathrm{Na}_{2}\mathrm{SO}_{4}(\mathrm{aq})\) as the reactants. These are the compounds that will undergo a chemical reaction.
2Step 2: Predict the products
The reaction between \(\mathrm{CuCl}_{2}(\mathrm{s})\) and \(\mathrm{Na}_{2}\mathrm{SO}_{4}(\mathrm{aq})\) can typically result in a double displacement reaction. In this scenario, the cations and anions exchange partners, resulting in products \(\mathrm{CuSO}_{4}\) and \(\mathrm{NaCl}\).
3Step 3: Write the balanced chemical equation
Write down the chemical equation resulting from the double displacement reactions: \[\mathrm{CuCl}_{2}(\mathrm{s}) + \mathrm{Na}_{2}\mathrm{SO}_{4}(\mathrm{aq}) \rightarrow \mathrm{CuSO}_{4}(\mathrm{aq}) + 2\mathrm{NaCl}(\mathrm{aq})\]. The \(\mathrm{CuSV} subdivision(\mathrm{aq})\) is soluble in water, and \(\mathrm{NaCl}(\mathrm{aq})\) is also soluble.
4Step 4: Check the balancing of the equation
Ensure that the equation is balanced by counting the number of atoms of each element on both sides. There are 1 Cu, 2 Cl, 2 Na, 1 S, and 4 O atoms on both sides, ensuring coefficients are correctly used for balancing.
Key Concepts
Double displacement reactionBalancing equationsReactants and products
Double displacement reaction
A double displacement reaction, also known as a metathesis reaction, occurs when the cations and anions of two different compounds switch places. This type of reaction typically forms one or more products, which can also include precipitates, gases, or water. In the example of \[\mathrm{CuCl}_{2}(\mathrm{s}) + \mathrm{Na}_{2} \mathrm{SO}_{4}(\mathrm{aq}) \rightarrow \mathrm{CuSO}_{4}(\mathrm{aq}) + 2\mathrm{NaCl}(\mathrm{aq})\], a double displacement reaction takes place as the copper ions \((\mathrm{Cu}^{2+})\) from copper(II) chloride pair with sulfate ions \((\mathrm{SO}_{4}^{2-})\), while the sodium ions \((\mathrm{Na}^{+})\) pair with chloride ions \((\mathrm{Cl}^{-})\).
- The reactants must be soluble in water to allow the ions to disassociate and recombine.
- Observing new products helps confirm a double displacement reaction has occurred.
- This reaction type frequently results in at least one product that is insoluble in water.
Balancing equations
Balancing a chemical equation is crucial to ensure it obeys the Law of Conservation of Mass. This law states that matter cannot be created or destroyed in a chemical reaction. Thus, each side of the equation must have the same number of atoms for every element involved. To balance a chemical equation, follow these steps:
- Write down the unbalanced equation.
- List the number of each type of atom for both reactants and products.
- Adjust coefficients to balance each type of atom on both sides.
- Confirm the atom count is equal in both reactants and products.
Reactants and products
In any chemical reaction, reactants are the initial substances that undergo a change to form new substances called products. Understanding the nature of reactants and products helps in predicting the outcome of a reaction and writing balanced chemical equations. In our example,
- The reactants are copper(II) chloride \(\mathrm{CuCl}_{2}(\mathrm{s})\) and sodium sulfate \(\mathrm{Na}_{2}\mathrm{SO}_{4}(\mathrm{aq})\).
- The double displacement reaction transforms these reactants into products, which are copper(II) sulfate \(\mathrm{CuSO}_{4}(\mathrm{aq})\) and sodium chloride \(\mathrm{NaCl}(\mathrm{aq})\).
- Reactants reside on the left side of a chemical equation.
- Products are found on the right side of the chemical equation.
- Understanding the solubility, state, and reactivity helps in predicting the products.
Other exercises in this chapter
Problem 95
Write the net ionic equation for a chemical reaction that occurs in an aqueous solution and produces water.
View solution Problem 96
Complete the following chemical equations. $$\begin{array}{l}{\text { a. } \mathrm{Na}(\mathrm{s})+\mathrm{H}_{2} \mathrm{O}(1) \rightarrow} \\ {\text { b. } \m
View solution Problem 99
Write complete ionic and net ionic equations for each of the following reactions. $$\begin{array}{l}{\text { a. } \mathrm{K}_{2} \mathrm{S}(\mathrm{aq})+\mathrm
View solution Problem 100
A reaction occurs when hydrosulfuric acid \(\left(\mathrm{H}_{2} \mathrm{S}\right)\) is mixed with an aqueous solution of iron(III) bromide. The reaction produc
View solution