Problem 97
Question
A gold prospector finds a solid rock that is composed solely of quartz and gold. (a) How is the total mass \(m_{\mathrm{T}}\) of the rock related to the mass \(m_{\mathrm{G}}\) of the gold and the mass \(m_{\mathrm{Q}}\) of the quartz? (b) What is the relationship between the total volume \(V_{\mathrm{T}}\) of the rock, the volume \(V_{\mathrm{G}}\) of the gold, and the volume \(V_{\mathrm{Q}}\) of the quartz? (c) How is the volume of a substance (gold or quartz) related to the mass of the substance and its density? The mass and volume of the rock are, respectively, \(12.0 \mathrm{~kg}\) and \(4.00 \times 10^{-3} \mathrm{~m}^{3}\). Find the mass of the gold in the rock.
Step-by-Step Solution
Verified Answer
(a) Total mass is the sum of gold and quartz masses: \(m_{\mathrm{T}} = m_{\mathrm{G}} + m_{\mathrm{Q}}\). (b) Total volume is the sum of gold and quartz volumes: \(V_{\mathrm{T}} = V_{\mathrm{G}} + V_{\mathrm{Q}}\). (c) Volume is mass divided by density: \(V = \frac{m}{\rho}\).
1Step 1: Understand Total Mass Relationship
The total mass of the rock, \(m_{\mathrm{T}}\), is the sum of the mass of the gold, \(m_{\mathrm{G}}\), and the mass of the quartz, \(m_{\mathrm{Q}}\). So, we can express this relationship as: \[ m_{\mathrm{T}} = m_{\mathrm{G}} + m_{\mathrm{Q}}. \]
2Step 2: Understand Total Volume Relationship
Since volume is an additive property for non-reactive materials, the total volume of the rock, \(V_{\mathrm{T}}\), is the sum of the volume of the gold, \(V_{\mathrm{G}}\), and the volume of the quartz, \(V_{\mathrm{Q}}\). Thus, the relationship is: \[ V_{\mathrm{T}} = V_{\mathrm{G}} + V_{\mathrm{Q}}. \]
3Step 3: Relating Volume, Mass, and Density
The volume \(V\) of a substance can be found using its mass \(m\) and density \(\rho\). The relationship is given by: \[ V = \frac{m}{\rho}, \] where \(\rho\) is the density of the substance. Therefore, for a given mass, you can compute the volume using this formula.
Key Concepts
Mass of SubstancesVolume of SubstancesDensity Formula
Mass of Substances
In understanding the mass of substances, it is essential to recognize that the total mass of a mixture, like a rock composed of gold and quartz, is the sum of the masses of its individual components. The mass of each substance contributes to the total mass. For example, if you have a rock containing both gold and quartz, the masses of the gold and quartz are simply added together to find the total mass of the rock.
This can be expressed mathematically as:
This can be expressed mathematically as:
- Total Mass Formula: The total mass of the rock, \( m_{\mathrm{T}} \), equals the mass of the gold, \( m_{\mathrm{G}} \), plus the mass of the quartz, \( m_{\mathrm{Q}} \). Therefore, \( m_{\mathrm{T}} = m_{\mathrm{G}} + m_{\mathrm{Q}} \).
Volume of Substances
Volume, much like mass, can also be considered an additive property for non-reactive substances. When dealing with a rock composed of gold and quartz, the total volume is the sum of the individual volumes of the gold and quartz within the rock. This is particularly straightforward as gold and quartz in their solid states do not react with each other.
The relationship can be stated as follows:
The relationship can be stated as follows:
- Total Volume Formula: The total volume of the rock, \( V_{\mathrm{T}} \), is the sum of the volume of the gold, \( V_{\mathrm{G}} \), and the quartz, \( V_{\mathrm{Q}} \); hence, \( V_{\mathrm{T}} = V_{\mathrm{G}} + V_{\mathrm{Q}} \).
Density Formula
The concept of density helps us relate the mass and volume of a substance. Density is defined as the mass of a substance per unit volume, and it determines how much mass is contained in a given volume of a material. The formula for density is expressed as:\( \rho = \frac{m}{V} \), where \( \rho \) represents density, \( m \) is mass, and \( V \) is volume.
This relationship can be rearranged to find volume if mass and density are known, using the formula:
This relationship can be rearranged to find volume if mass and density are known, using the formula:
- Volume from Mass and Density: \( V = \frac{m}{\rho} \). This tells us how to calculate the volume of a substance if we know its mass and density.
Other exercises in this chapter
Problem 93
In a very large closed tank, the absolute pressure of the air above the water is \(6.01 \times 10^{5} \mathrm{~Pa}\). The water leaves the bottom of the tank th
View solution Problem 94
Interactive LearningWare 11.1 at provides a review of the concepts that are important in this problem. A spring is attached to the bottom of an empty swimming p
View solution Problem 98
A meat baster consists of a squeeze bulb attached to a plastic tube. When the bulb is squeezed and released, with the open end of the tube under the surface of
View solution Problem 99
A hydrometer is a device used to measure the density of a liquid. It is a cylindrical tube weighted at one end, so that it floats with the heavier end downward.
View solution