Problem 96
Question
When \(\mathrm{X}\) amperes of current is passed through molten \(\mathrm{AlCl}_{3}\) for \(96.5\) seconds, \(0.09\) grams of aluminium is deposited. What is the value of \(X\) ? (a) 10 (b) 20 (c) 30 (d) 40
Step-by-Step Solution
Verified Answer
Option (a) 10 amperes is the value of X.
1Step 1: Determine Moles of Aluminium
Firstly, calculate the number of moles of aluminium deposited using the formula: \( \text{moles} = \frac{\text{mass}}{\text{molar mass}} \). The molar mass of aluminium (Al) is approximately 27 g/mol. \[ \text{moles of Al} = \frac{0.09}{27} \approx 0.00333 \text{ moles} \]
2Step 2: Understand the Electrochemical Reaction
The reaction for aluminum deposition in electrolysis is:\[ \text{Al}^{3+} + 3e^- \rightarrow \text{Al} \]This tells us that depositing one mole of aluminum requires three moles of electrons.
3Step 3: Calculate Total Charge Required
Using Faraday’s laws of electrolysis, 1 mole of electrons corresponds to a charge of 96500 Coulombs (Faraday's constant). Therefore, for 0.00333 moles of aluminum using 3 moles of electrons per mole of Al:\[ \text{Total charge} = 0.00333 \times 3 \times 96500 \approx 963.65 \text{ Coulombs} \]
4Step 4: Use Current Formula to Find X
Current is the total charge passed divided by the time spent in seconds. Given that the time is 96.5 seconds, apply:\[ \text{Current} (I) = \frac{\text{Total charge}}{\text{Time}} = \frac{963.65}{96.5} \approx 10 \text{ Amperes} \]
Key Concepts
Faraday's Laws of ElectrolysisCurrent CalculationMoles and Molar Mass Calculation
Faraday's Laws of Electrolysis
Faraday's Laws of Electrolysis are fundamental principles that help us understand how electrolysis works. These laws were formulated by Michael Faraday, a pioneer in electrochemistry. They help us calculate the amount of substance produced or consumed during an electrolysis process.
When we pass electrical current through a compound, it causes a chemical reaction. The Laws of Electrolysis quantify this process by relating the amount of electric current to the amount of substance deposited.
When we pass electrical current through a compound, it causes a chemical reaction. The Laws of Electrolysis quantify this process by relating the amount of electric current to the amount of substance deposited.
- First Law: The mass of a substance deposited or released at an electrode is directly proportional to the quantity of electric charge passed through the electrolyte.
- Second Law: When the same quantity of electricity flows through different electrolytes in series, the masses of the substances deposited are proportional to their equivalent weights.
Current Calculation
Calculating electrical current during electrolysis is essential to understanding how much charge flows through an electrolyte. Electrolysis makes use of electric current to drive a non-spontaneous chemical reaction.
Electric current, measured in amperes, represents the flow of electric charge in a circuit. During electrolysis, this charge is transferred in the form of electrons.
The formula used for current calculation in electrolysis is:
Electric current, measured in amperes, represents the flow of electric charge in a circuit. During electrolysis, this charge is transferred in the form of electrons.
The formula used for current calculation in electrolysis is:
- \[I = \frac{Q}{t}\]
- Where \(I\) is the current in amperes, \(Q\) is the total charge in coulombs, and \(t\) is the time in seconds.
Moles and Molar Mass Calculation
Understanding the concept of moles and molar mass is crucial in chemistry, especially when dealing with chemical reactions and electrolysis.
Moles help us to express amounts of a chemical substance. It provides a bridge between the atomic world (atoms, molecules) and the real-world amount of substance we can measure.
To calculate moles, we use the formula:
Moles help us to express amounts of a chemical substance. It provides a bridge between the atomic world (atoms, molecules) and the real-world amount of substance we can measure.
To calculate moles, we use the formula:
- \[\text{moles} = \frac{\text{mass}}{\text{molar mass}}\]
- Mass is the substance's mass in grams, and molar mass is the mass of one mole of the substance in grams per mole \(\text{g/mol}\).
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