Problem 96
Question
The use of a different system of coordinates simplifies many mathematical expressions and some calculations are performed in an easier way. The rectangular coordinates \((x, y)\) are transformed into polar coordinates by the equations $$x=r \cos \theta \quad \text { and } \quad y=r \sin \theta$$ where \(r=\sqrt{x^{2}+y^{2}}(r \neq 0)\) and \(\tan \theta=\frac{y}{x}(x \neq 0) .\) In polar coordinates, the equation of the unit circle \(x^{2}+y^{2}=1\) is just \(r=1\) In calculus, we use polar coordinates extensively. Transform the rectangular equation to polar form. $$x^{2}+y^{2}=4 x$$
Step-by-Step Solution
Verified Answer
The polar form of the equation is \(r = 4 \cos \theta\).
1Step 1: Identify the Rectangular Equation
The given rectangular equation is \(x^2 + y^2 = 4x\). This equation needs to be converted into polar coordinates.
2Step 2: Use Polar Coordinate Definitions
Recall from the problem statement that in polar coordinates, \(x = r \cos \theta\) and \(y = r \sin \theta\). Thus, \(x^2 + y^2 = r^2\). Additionally, \(x = r \cos \theta\).
3Step 3: Substitute Polar Definitions
Substitute \(x = r \cos \theta\) and \(x^2 + y^2 = r^2\) into the rectangular equation: \(r^2 = 4(r \cos \theta)\).
4Step 4: Simplify the Polar Equation
Simplify the equation \(r^2 = 4r \cos \theta\) by dividing both sides by \(r\) (assuming \(r eq 0\)): \(r = 4 \cos \theta\).
5Step 5: Conclusion
The rectangular equation \(x^2 + y^2 = 4x\) is transformed into the polar equation \(r = 4 \cos \theta\).
Key Concepts
Rectangular CoordinatesCoordinate TransformationTrigonometric FunctionsUnit CircleEquation Conversion
Rectangular Coordinates
Rectangular coordinates are often referred to as Cartesian coordinates. They use two perpendicular axes, typically labeled as the x-axis and the y-axis. Each point is represented as
- \((x, y)\) in a plane which describes the distance from the origin along the x-axis and the y-axis.
Coordinate Transformation
Coordinate transformation involves converting one set of coordinates to another. This is essential in converting between rectangular and polar coordinates.
- For rectangular to polar, use the transformations \(x = r \cos \theta\) and \(y = r \sin \theta\).
- To find \(r\), the radial distance, use \(r = \sqrt{x^2 + y^2}\).
- The angle \(\theta\) can be found using \(\tan \theta = \frac{y}{x}\).
Trigonometric Functions
Understanding trigonometric functions is crucial in coordinate transformation, as they directly relate angles to side lengths in triangles.
- \(\cos \theta\) represents the adjacent side over the hypotenuse in a right triangle.
- \(\sin \theta\) represents the opposite side over the hypotenuse.
- \(\tan \theta\) is the ratio of \(\sin \theta\) to \(\cos \theta\), or the opposite side over the adjacent side.
Unit Circle
The unit circle is a fundamental tool in trigonometry and calculus. It is a circle with a radius of one unit, centered at the origin of a coordinate system.
- The equation for the unit circle in rectangular coordinates is \(x^2 + y^2 = 1\).
- In polar coordinates, the unit circle is simply \(r = 1\).
Equation Conversion
Equation conversion refers to the process of transforming equations from one form into another, such as converting from rectangular to polar forms.
- Start with a rectangular equation, like \(x^2 + y^2 = k\) or other forms.
- Substitute \(x\) and \(y\) with their polar coordinate equivalents: \(x = r \cos \theta\) and \(y = r \sin \theta\).
- Simplify the resulting equation to express it in terms of \(r\) and \(\theta\).
Other exercises in this chapter
Problem 95
Find the magnitude of the vector \((-a, b)\) if \(a>0\) and \(b>0\)
View solution Problem 96
In calculus, when we need to find the area enclosed by two polar curves, the first step consists of finding the points where the curves coincide. Find the point
View solution Problem 96
Find the direction angle of the vector \(\langle-a, b\rangle\) if \(a>0\) and \(b>0\)
View solution Problem 97
In calculus, when we need to find the area enclosed by two polar curves, the first step consists of finding the points where the curves coincide. Find the point
View solution