Problem 96
Question
Suppose that a construction zone can allow 50 cars per hour to pass through and that cars arrive randomly at a rate of \(x\) cars per hour. Then the average number of cars waiting in line to get through the construction zone can be estimated by $$ N(x)=\frac{x^{2}}{2500-50 x} $$ (a) Evaluate \(N(20), N(40),\) and \(N(49)\) (b) Explain what happens to the length of the line as \(x\) approaches \(50 .\) (c) Find any vertical asymptotes of the graph of \(N .\)
Step-by-Step Solution
Verified Answer
(a) \(N(20) \approx 0.267\), \(N(40) = 3.2\), \(N(49) = 48.02\).
(b) Lines grow as \(x\) approaches 50.
(c) Vertical asymptote at \(x=50\).
1Step 1: Evaluating N(20)
To find \(N(20)\), substitute \(x = 20\) into the given function:\[N(20) = \frac{20^2}{2500 - 50 \times 20}\]Calculate the numerator and the denominator:\[N(20) = \frac{400}{2500 - 1000} = \frac{400}{1500}\]Simplify the fraction:\[N(20) = \frac{4}{15}\approx 0.267\]
2Step 2: Evaluating N(40)
Substitute \(x = 40\) into the function:\[N(40) = \frac{40^2}{2500 - 50 \times 40}\]Calculate the numerator and the denominator:\[N(40) = \frac{1600}{2500 - 2000} = \frac{1600}{500}\]Simplify the fraction:\[N(40) = \frac{16}{5} = 3.2\]
3Step 3: Evaluating N(49)
Substitute \(x = 49\) into the function:\[N(49) = \frac{49^2}{2500 - 50 \times 49}\]Calculate the numerator and the denominator:\[N(49) = \frac{2401}{2500 - 2450} = \frac{2401}{50}\]Evaluate the division:\[N(49) = 48.02\]
4Step 4: Behavior as x approaches 50
As \(x\) approaches 50, the denominator \(2500 - 50x\) approaches zero, which makes the value of \(N(x)\) increase significantly towards infinity. This indicates that the number of cars waiting in line grows very large as the rate of arriving cars approaches the zone's maximum capacity of 50 cars per hour.
5Step 5: Finding Vertical Asymptotes
A vertical asymptote occurs where the denominator approaches zero, causing the function to become undefined. Set the denominator equal to zero:\[2500 - 50x = 0\]Solve for \(x\):\[50x = 2500\]\[x = 50\]Therefore, there is a vertical asymptote at \(x = 50\).
Key Concepts
Average Number of Cars WaitingVertical AsymptotesLimit Behavior in Functions
Average Number of Cars Waiting
In a construction zone, the average number of cars waiting to get through is a pivotal measure of traffic congestion. The function provided, \( N(x) = \frac{x^2}{2500 - 50x} \), tells us this average based on the car arrival rate \( x \). As cars arrive randomly at the given rate, knowing how many cars on average are stuck in line is useful for planning and managing traffic flow.
- If fewer cars arrive than the zone can handle, fewer cars wait in line.
- If cars arrive near the zone's maximum capacity, more cars wait in line.
Vertical Asymptotes
Vertical asymptotes are those invisible lines where a graph shoots off towards infinity. These often make the behavior of certain functions quite dramatic. In the context of our construction zone scenario, the function \( N(x) = \frac{x^2}{2500 - 50x} \) reaches a vertical asymptote at \( x = 50 \), as seen in the calculations.
- At a vertical asymptote, the function becomes undefined.
- This stems from the denominator approaching zero, causing \( N(x) \) to soar towards infinity.
Limit Behavior in Functions
The concept of limit behavior describes how a function behaves as it approaches a particular point or value. In relation to our construction zone function \( N(x) = \frac{x^2}{2500 - 50x} \), limit behavior is analyzed as \( x \) nears 50.
- As the arrival rate approaches 50, \( N(x) \) climbs higher and higher, indicating longer waits.
- This increase is due to the shrinking denominator ∝ as \( x \) approaches the asymptote value, making \( N(x) \) infinitely large.
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