Problem 96
Question
Find (a) the distance between P and Q and (b) the coordinates of the midpoint M of the segment joining P and Q. $$P(12 y,-3 y), Q(20 y, 12 y), \quad y>0$$
Step-by-Step Solution
Verified Answer
(a) Distance = \( 17y \). (b) Midpoint \( M = \left(16y, \frac{9y}{2}\right) \).
1Step 1: Find the distance
\( d = \sqrt{(20y-12y)^2 + (12y-(-3y))^2} = \sqrt{(8y)^2 + (15y)^2} = \sqrt{64y^2 + 225y^2} = \sqrt{289y^2} = 17y \) (since \( y > 0 \)).
2Step 2: Find the midpoint
\( M = \left(\frac{12y+20y}{2}, \frac{-3y+12y}{2}\right) = \left(\frac{32y}{2}, \frac{9y}{2}\right) = \left(16y, \frac{9y}{2}\right) \).
Key Concepts
Distance FormulaMidpoint FormulaCoordinate Geometry
Distance Formula
The Distance Formula is a key tool in coordinate geometry, used to calculate the distance between two points on a coordinate plane. In a Cartesian coordinate system, each point is identified by an ordered pair of numbers (x, y). To find the distance between two points, like P(12y, -3y) and Q(20y, 12y), you can employ the distance formula:\[d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\]Here:
Substituting the given coordinates into the formula:
- \(x_1\), \(y_1\) are the coordinates of the first point (P).
- \(x_2\), \(y_2\) are the coordinates of the second point (Q).
Substituting the given coordinates into the formula:
- \(d = \sqrt{(20y - 12y)^2 + (12y - (-3y))^2} = \sqrt{(8y)^2 + (15y)^2}\)
- \(d = \sqrt{64y^2 + 225y^2} = \sqrt{289y^2} = 17y\)
Midpoint Formula
The Midpoint Formula helps you find the center point of a line segment connecting two points in a coordinate plane. It essentially averages the x-coordinates and y-coordinates of the two endpoints. The midpoint is represented as:\[M\left(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}\right)\]Given points P(12y, -3y) and Q(20y, 12y):
This formula is quite helpful in dividing segments into equal halves and is frequently used in graphical analysis and applications where symmetry and central points are assessed.
- The average of the x-coordinates is \(\frac{12y + 20y}{2} = \frac{32y}{2} = 16y\)
- The average of the y-coordinates is \(\frac{-3y + 12y}{2} = \frac{9y}{2}\)
This formula is quite helpful in dividing segments into equal halves and is frequently used in graphical analysis and applications where symmetry and central points are assessed.
Coordinate Geometry
Coordinate Geometry, also known as Analytic Geometry, combines algebra and geometry to study geometric figures on a coordinate plane. Here are some key aspects:
By practicing with these formulas, students gain a deeper insight into how shapes and lines behave within a coordinate grid, building a foundation for more complex geometrical concepts and analytical methods.
- Allows the determination of distances, midpoints, and slopes of lines through algebraic formulas.
- Provides a way to solve geometrical problems numerically.
- Facilitates the visualization of algebraic equations as geometric figures, bridging abstract and concrete concepts.
By practicing with these formulas, students gain a deeper insight into how shapes and lines behave within a coordinate grid, building a foundation for more complex geometrical concepts and analytical methods.
Other exercises in this chapter
Problem 95
Find (a) the distance between P and Q and (b) the coordinates of the midpoint M of the segment joining P and Q. $$P(13 x,-23 x), Q(6 x, x), \quad x>0$$
View solution Problem 96
Solve each inequality analytically. Write the solution set in interval notation. Support your answer graphically. $$-0.9 x-(0.5+0.1 x)>-0.3 x-0.5$$
View solution Problem 97
Suppose that P is an endpoint of a segment PQ and M is the midpoint of \(P Q .\) Find the coordinates of endpoint Q. $$P(7,-4), M(8,5)$$
View solution Problem 97
Solve each inequality analytically. Write the solution set in interval notation. Support your answer graphically. $$-\frac{1}{2} x+0.7 x-5>0$$
View solution