Problem 96
Question
Factor $$3 x^{2}-15 x-42$$
Step-by-Step Solution
Verified Answer
The factored form of the given equation is \((3x + 6) (x - 7)\)
1Step 1: Multiply \(a\) and \(c\) in the given equation
Multiplication yields \(ac = 3(-42)=-126\)
2Step 2: Finding two numbers
Find two numbers that will multiply to -126 and add up to -15. These two numbers are -21 and 6.
3Step 3: Rewrite equation
With these numbers (6 and -21), rewrite the middle term: \(3x^2 - 21x + 6x -42\)
4Step 4: Factoring by Grouping
Group the results into two groups (3x^2 - 21x) and (6x -42) then factor out a common factor from each group, the expression becomes \(3x(x-7) + 6(x - 7)\)
5Step 5: Final Factoring
Since both groups include the factor \((x-7)\), it can be used as a common factor. The final factored equation is \((3x + 6) (x - 7)\)
Key Concepts
Polynomial FactorizationFactoring by GroupingAlgebraic Expressions
Polynomial Factorization
Understanding polynomial factorization is key to mastering algebra. It is a method of simplifying polynomials by expressing them as a product of their factors. By breaking down complex expressions into simpler components, we can solve equations more easily. In our exercise, our task is to factor the quadratic expression \(3x^2 - 15x - 42\). This means we need to express it as the product of two binomials or other simpler expressions.
To start, identify the coefficients from the expression: 3 is the coefficient of \(x^2\), -15 is the coefficient of \(x\), and -42 is the constant. The primary goal is to find two numbers that multiply to the product of the leading coefficient (3) and the constant term (-42) while also adding up to the middle coefficient (-15).
Once you successfully identify these numbers, you can split the linear term accordingly. This prepares you to apply various factoring techniques like grouping or using special identities, making polynomial factorization a powerful tool for simplifying algebraic expressions.
To start, identify the coefficients from the expression: 3 is the coefficient of \(x^2\), -15 is the coefficient of \(x\), and -42 is the constant. The primary goal is to find two numbers that multiply to the product of the leading coefficient (3) and the constant term (-42) while also adding up to the middle coefficient (-15).
Once you successfully identify these numbers, you can split the linear term accordingly. This prepares you to apply various factoring techniques like grouping or using special identities, making polynomial factorization a powerful tool for simplifying algebraic expressions.
Factoring by Grouping
Factoring by grouping is a strategic method used when a polynomial expression can’t be readily factored through simple techniques. This involves rearranging and combining terms to uncover common factors, making it easier to simplify the equation.
In the given exercise, the quadratic expression \(3x^2 - 15x - 42\) is rewritten by splitting the middle term. This is achieved after finding two numbers, -21 and 6, that multiply to the product of the first and last coefficients (-126) and add up to the middle coefficient (-15). Thus, the expression is rewritten as \(3x^2 - 21x + 6x - 42\).
In the given exercise, the quadratic expression \(3x^2 - 15x - 42\) is rewritten by splitting the middle term. This is achieved after finding two numbers, -21 and 6, that multiply to the product of the first and last coefficients (-126) and add up to the middle coefficient (-15). Thus, the expression is rewritten as \(3x^2 - 21x + 6x - 42\).
- First group terms: \((3x^2 - 21x) + (6x - 42)\).
- Identify common factors in each group: \(3x\) in the first, and 6 in the second group.
- Factor out these common factors: you get \(3x(x-7) + 6(x-7)\).
Algebraic Expressions
Algebraic expressions are combinations of numbers, variables, and operations (such as addition and multiplication) that act as the building blocks of algebra. They allow us to model real-world situations and solve various mathematical problems.
When working with algebraic expressions like \(3x^2 - 15x - 42\), it’s crucial to recognize terms, distinguish between coefficients and constants, and apply appropriate operations to simplify or solve equations. For effective manipulation, understanding how these parts interact is vital. Coefficients (like 3 and -15) adjust the rate of change or slope in linear components, while constants (-42) shift the overall graph or value in the expression.
When working with algebraic expressions like \(3x^2 - 15x - 42\), it’s crucial to recognize terms, distinguish between coefficients and constants, and apply appropriate operations to simplify or solve equations. For effective manipulation, understanding how these parts interact is vital. Coefficients (like 3 and -15) adjust the rate of change or slope in linear components, while constants (-42) shift the overall graph or value in the expression.
- Terms are the separated components (e.g., \(3x^2, -15x, -42\)).
- The coefficients are the numeric factors (like 3 and -15) multiplying the variable terms.
- Constant terms are the standalone numbers without variables (e.g., -42).
Other exercises in this chapter
Problem 96
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