Problem 96
Question
Aluminum metal reacts with perchloric acid to produce hydrogen gas and a solution of aluminum perchlorate. Write the molecular equation for this reaction. Then write the corresponding net ionic equation.
Step-by-Step Solution
Verified Answer
The net ionic equation is: \[ 2Al(s) + 6H^+(aq) \rightarrow 3H_2(g) + 2Al^{3+}(aq) \]
1Step 1: Identify Reactants and Products
The reactants in this chemical reaction are aluminum metal (Al) and perchloric acid (HClO₄). The products are hydrogen gas (H₂) and aluminum perchlorate (Al(ClO₄)₃) in aqueous solution.
2Step 2: Write the Balanced Molecular Equation
The balanced chemical reaction for the reaction between aluminum metal and perchloric acid is written as:\[ 2Al(s) + 6HClO₄(aq) \rightarrow 3H_2(g) + 2Al(ClO₄)_3(aq) \]
3Step 3: Identify the States and Strong Electrolytes
Aluminum metal is a solid (s), perchloric acid is aqueous (aq), hydrogen gas is gaseous (g), and aluminum perchlorate is aqueous (aq). Perchloric acid is a strong acid, and aluminum perchlorate is a soluble ionic compound, which fully dissociates in water.
4Step 4: Write the Complete Ionic Equation
Represent the strong electrolytes (aqueous substances) as ions in the reaction:\[ 2Al(s) + 6H^+(aq) + 6ClO_4^-(aq) \rightarrow 3H_2(g) + 2Al^{3+}(aq) + 6ClO_4^-(aq) \]
5Step 5: Cancel Spectator Ions to Find Net Ionic Equation
Identify and cancel the spectator ions, which do not change during the reaction. In this reaction, \(ClO_4^-\) appears on both sides:\[ 2Al(s) + 6H^+(aq) \rightarrow 3H_2(g) + 2Al^{3+}(aq) \]
6Step 6: Write the Net Ionic Equation
The net ionic equation, simplified, for the reaction is:\[ 2Al(s) + 6H^+(aq) \rightarrow 3H_2(g) + 2Al^{3+}(aq) \]
Key Concepts
Chemical ReactionMolecular EquationBalanced EquationAluminum MetalPerchloric Acid
Chemical Reaction
A chemical reaction occurs when substances interact, resulting in the formation of new products. In this scenario, aluminum metal reacts with perchloric acid. This is a simple exchange of atoms or ions where new bonds are formed, leading to the creation of hydrogen gas and aluminum perchlorate.
In most chemical reactions:
In most chemical reactions:
- The reactants are the substances present at the beginning.
- The products are the substances formed after the reaction.
Molecular Equation
The molecular equation provides a detailed view of a chemical reaction by showing all the reactants and products in their original form. For the reaction between aluminum metal and perchloric acid, the molecular equation is:
\[ 2Al(s) + 6HClO_4(aq) \rightarrow 3H_2(g) + 2Al(ClO_4)_3(aq) \]
This equation shows:
\[ 2Al(s) + 6HClO_4(aq) \rightarrow 3H_2(g) + 2Al(ClO_4)_3(aq) \]
This equation shows:
- 2 aluminum atoms reacting.
- 6 perchloric acid molecules participating.
- The formation of hydrogen gas and aluminum perchlorate.
Balanced Equation
Balancing an equation is essential in ensuring the conservation of mass, as atoms cannot be created or destroyed. Each type of atom present in the reactants must also be accounted for in the products.
In the balanced equation \( 2Al(s) + 6HClO_4(aq) \rightarrow 3H_2(g) + 2Al(ClO_4)_3(aq) \), the quantities reflect that:
In the balanced equation \( 2Al(s) + 6HClO_4(aq) \rightarrow 3H_2(g) + 2Al(ClO_4)_3(aq) \), the quantities reflect that:
- 2 moles of aluminum react with 6 moles of perchloric acid.
- The reaction produces 3 moles of hydrogen gas.
- 2 moles of aluminum perchlorate are formed.
Aluminum Metal
Aluminum metal, denoted as \(Al\), is a lightweight, silvery-white metal known for its high conductivity and resistance to corrosion. In the given reaction:
- Aluminum acts as a reducing agent, donating electrons.
- It forms aluminum ions \((Al^{3+})\) upon reacting with the acid.
Perchloric Acid
Perchloric acid, \(HClO_4\), is a strong mineral acid known for its high reactivity. It fully dissociates in water, meaning it splits into hydrogen ions \((H^+)\) and perchlorate ions \((ClO_4^-)\). In this reaction:
- The hydrogen ions react with aluminum metal, facilitating the release of hydrogen gas.
- The perchlorate ions remain unchanged as spectator ions.
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