Problem 95
Question
Solve using any method, and eliminate extraneous solutions. $$e^{\log x}=e$$
Step-by-Step Solution
Verified Answer
The solution to \(e^{log x} = e\) is \(x=e\).
1Step 1: Understand the Expression
The expression \(e^{\log x}=e\) is defined for \(x>0\) as we're taking logarithm of \(x\). The problem is to solve for \(x\).
2Step 2: Simplify the Expression
In the next step, using the property of exponentials and logarithms where they cancel each other out, simplify \(e^{\log x}\) to \(x\).
3Step 3: Solve for \(x\)
After simplifying the expression, the equation to solve becomes \(x=e\).
4Step 4: Evaluate for Extraneous Solutions
e (approx 2.718) is greater than 0 which fits with our initial criteria for the problem (logarithm of \(x\) for \(x>0\)). Thus \(x=e\) is not an extraneous solution.
Key Concepts
Exponential and Logarithmic PropertiesExtraneous Solutions in LogarithmsProperties of Natural Logarithms
Exponential and Logarithmic Properties
Understanding exponential and logarithmic properties is crucial when solving equations involving them. Exponential functions are defined by an equation of the form
These properties work well together because logarithms convert multiplication into addition, division into subtraction, powers into multiplication, and roots into division. Several key properties include:
y = a^x, where a is a constant, and x is the exponent. The inverse of an exponential function is a logarithm. The properties of logarithms are rooted in their definition: for any positive number a and b, where a is not equal to 1, \(\log_a b = c\) if and only if a^c = b.These properties work well together because logarithms convert multiplication into addition, division into subtraction, powers into multiplication, and roots into division. Several key properties include:
- Product Property: \(\log_a (xy) = \log_a x + \log_a y\)
- Quotient Property: \(\log_a (\frac{x}{y}) = \log_a x - \log_a y\)
- Power Property: \(\log_a (x^c) = c \log_a x\)
Extraneous Solutions in Logarithms
In the context of logarithmic equations, extraneous solutions can arise when we apply operations that may introduce results which are not valid in the original equation. This typically happens when we raise both sides of an equation to a power or take a root of both sides. Since the domain of logarithmic functions is limited to positive real numbers, after algebraic manipulations, we need to check that the solutions we find actually make sense in the original equation.
To identify extraneous solutions, it is important to:
To identify extraneous solutions, it is important to:
- Always check the domain conditions of the original equation after solving it.
- Verify each potential solution by substituting it back into the original equation.
- Understand that not every solution generated by algebraic manipulation will be valid, particularly if they result in taking the logarithm of a negative number or zero, which is undefined in real numbers.
Properties of Natural Logarithms
The natural logarithm, denoted as \(\ln x\), is a specific instance of a logarithm with base \(e\), where \(e\) is an irrational and transcendental number approximately equal to 2.71828. Its properties closely coincide with those of general logarithms but specifically apply to the base \(e\).
Some of the key properties of natural logarithms include:
Some of the key properties of natural logarithms include:
- Logarithm of 1: \(\ln(1) = 0\), because \(e^0 = 1\).
- Logarithm of \(e\): \(\ln(e) = 1\), by definition of the natural logarithm.
- Inverse Properties: For any positive number
x, \(\ln(e^x) = x\) and \(e^{\ln(x)} = x\). This inverse relationship is crucial when solving equations involving natural logarithms. - Continuous Growth: Natural logarithms are often used in contexts involving continuous growth or decay because they are the inverse of the natural exponential function, which models continuous growth.
Other exercises in this chapter
Problem 94
Solve using any method, and eliminate extraneous solutions. $$\ln (\log x)=1$$
View solution Problem 94
This set of exercises will draw on the ideas presented in this section and your general math background. Explain why In 4 is between 1 and \(2,\) without using
View solution Problem 95
Explain how you could use the following table of values for the function \(f(x)=10^{x}\) to find the given quantity. $$\begin{array}{cc} x & f(x)=10^{x} \\ 0.47
View solution Problem 96
Solve using any method, and eliminate extraneous solutions. $$\log _{5}|x-2|=2$$
View solution