Problem 95
Question
Oxygen Consumption If 5.00 L of hydrogen gas, measured at a temperature of 20.0°C and a pressure of 80.1 kPa, is burned in excess oxygen to form water, what mass of oxygen will be consumed? Assume temperature and pressure remain constant.
Step-by-Step Solution
Verified Answer
The mass of oxygen consumed when 5.00 L of hydrogen gas, measured at a temperature of 20.0°C and a pressure of 80.1 kPa, is burned in excess oxygen to form water is 3.44 g.
1Step 1: Convert temperature to Kelvin
Given temperature is 20.0°C. To convert this to Kelvin:
Temperature (K) = Temperature (°C) + 273.15
Temperature (K) = 20.0 + 273.15 = 293.15 K
2Step 2: Calculate moles of hydrogen gas
Using the Ideal Gas Law (PV=nRT),
n (H2) = PV / RT
We need to convert pressure from kPa to atm:
80.1 kPa * (1 atm / 101.3 kPa) = 0.790 atm
Now, use the given values and the gas constant (R = 0.08206 L.atm/(K.mol) ):
n (H2) = (0.790 atm) * (5.00 L) / (0.08206 L.atm/(K.mol) * 293.15 K)
n (H2) = 0.215 moles
3Step 3: Calculate moles of oxygen consumed
Using the balanced chemical equation, 2 moles of H2 react with 1 mole of O2:
2 H2 + O2 -> 2 H2O
n (O2) = (1/2) * n (H2)
n (O2) = (1/2) * 0.215 moles = 0.1075 moles
4Step 4: Calculate the mass of oxygen consumed
Using the molar mass of oxygen (16 g/mol for O, and 32 g/mol for O2):
Mass (O2) = n (O2) * Molar mass (O2)
Mass (O2) = 0.1075 moles * 32 g/mol = 3.44 g
The mass of oxygen consumed in the reaction is 3.44 g.
Key Concepts
Ideal Gas LawChemical ReactionsMole CalculationsGas Laws
Ideal Gas Law
The Ideal Gas Law is a fundamental equation in chemistry and physics. It allows us to relate pressure, volume, temperature, and the amount of gas in terms of moles. The equation is expressed as \( PV = nRT \), where:
In the context of our exercise, the Ideal Gas Law helps calculate the number of moles of hydrogen present in a given volume of gas.
- \( P \) stands for pressure.
- \( V \) is the volume.
- \( n \) represents the number of moles of gas.
- \( R \) is the ideal gas constant, commonly used as 0.08206 L.atm/(K.mol).
- \( T \) is the temperature in Kelvin.
In the context of our exercise, the Ideal Gas Law helps calculate the number of moles of hydrogen present in a given volume of gas.
Chemical Reactions
Chemical reactions are processes where reactants transform into products. These reactions can usually be described with a balanced chemical equation, which shows the relationship between reactant and product molecules.
In our case, the reaction is between hydrogen gas (\( H_2 \)) and oxygen gas (\( O_2 \)) to produce water (\( H_2O \)). The balanced equation is:
Understanding chemical reactions and how to balance them is fundamental for realizing the stoichiometry involved in calculating reactants and products.
In our case, the reaction is between hydrogen gas (\( H_2 \)) and oxygen gas (\( O_2 \)) to produce water (\( H_2O \)). The balanced equation is:
- 2 \( H_2 \) + \( O_2 \) → 2 \( H_2O \)
Understanding chemical reactions and how to balance them is fundamental for realizing the stoichiometry involved in calculating reactants and products.
Mole Calculations
Calculating moles is a core skill in chemistry. It allows us to quantify the amount of a substance using its chemical formula and the periodic table. A mole represents \(6.022 \times 10^{23}\) units of a substance, a number known as Avogadro's number.
To find the number of moles from a given mass, use the formula:
In the exercise, mole calculations were used twice: first, to determine the moles of hydrogen gas using the Ideal Gas Law, and second, to figure out how many moles of oxygen were consumed based on the stoichiometry of the chemical reaction.
To find the number of moles from a given mass, use the formula:
- \( n = \frac{m}{M} \)
In the exercise, mole calculations were used twice: first, to determine the moles of hydrogen gas using the Ideal Gas Law, and second, to figure out how many moles of oxygen were consumed based on the stoichiometry of the chemical reaction.
Gas Laws
Gas laws are a collection of laws that describe the properties of gases and how they behave under different conditions.
The Ideal Gas Law is a combination of several simpler gas laws, such as Boyle's Law, Charles's Law, and Avogadro's Law:
The Ideal Gas Law is a combination of several simpler gas laws, such as Boyle's Law, Charles's Law, and Avogadro's Law:
- Boyle's Law states that pressure and volume are inversely proportional when temperature and moles are constant (\( PV = ext{constant} \)).
- Charles's Law says that volume and temperature are directly proportional under constant pressure and moles (\( V/T = ext{constant} \)).
- Avogadro's Law notes that volume and moles are directly proportional if pressure and temperature remain the same (\( V/n = ext{constant} \)).
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