Problem 95
Question
Let z \(=3-2 i\), \(u=-4+3 i, v=3+5 i\), and \(w=1-i .\) Compute the following expressions: \(\overline{z+v}\)
Step-by-Step Solution
Verified Answer
The value of \(\overline{z+v}\) is \(6 - 3i\).
1Step 1: Add the Complex Numbers
First, compute the sum of the complex numbers \(z\) and \(v\). The complex number \(z = 3 - 2i\) and \(v = 3 + 5i\). Adding these together, we work component-wise: add the real parts and the imaginary parts separately.\[(3 + 3) + (-2i + 5i) = 6 + 3i\]
2Step 2: Compute the Conjugate
Now, compute the conjugate of the resulting complex number from Step 1. The conjugate of a complex number \(a + bi\) is \(a - bi\). Thus, for \(6 + 3i\), its conjugate is:\[6 - 3i\]
Key Concepts
Understanding Complex ConjugateAddition of Complex NumbersReal and Imaginary Components
Understanding Complex Conjugate
A complex conjugate is a concept that often puzzles students initially, but it's quite straightforward once you get the hang of it! Think of a complex number in the form of \(a + bi\), where \(a\) and \(b\) are real numbers, and \(i\) is the imaginary unit with the property \(i^2 = -1\). The complex conjugate is simply a reflection across the real axis. To find it, you keep the real part \(a\) unchanged, and flip the sign of the imaginary part \(b\).
- Original complex number: \(a + bi\)
- Complex conjugate: \(a - bi\)
Addition of Complex Numbers
Adding complex numbers is very much like adding traditional numbers, but with a twist! Each complex number consists of a real part and an imaginary part. During addition, you combine these components separately, which is very straightforward.
Here's how:
- The real parts: \(3 + 3 = 6\)- The imaginary parts: \(-2i + 5i = 3i\)
So, when you add them, you get the resultant complex number \(6 + 3i\). Addition in complex numbers is commutative and associative, meaning you can add them in any order and still get the same result!
Here's how:
- Add the real parts of the numbers together.
- Add the imaginary parts of the numbers together.
- The real parts: \(3 + 3 = 6\)- The imaginary parts: \(-2i + 5i = 3i\)
So, when you add them, you get the resultant complex number \(6 + 3i\). Addition in complex numbers is commutative and associative, meaning you can add them in any order and still get the same result!
Real and Imaginary Components
Real and imaginary components are fundamental to understanding complex numbers. Each complex number comprises two parts:
Having these two components allows complex numbers to represent phenomena in multiple dimensions, such as waves and oscillations in electrical engineering. It's crucial to handle the real and imaginary parts properly in operations like addition, subtraction, multiplication, and division to accurately work with complex numbers.
- The real part is the "regular" number you're used to, like \(3\) in the number \(3 - 2i\).
- The imaginary part is the component multiplied by \(i\), like \(-2i\) in \(3 - 2i\).
Having these two components allows complex numbers to represent phenomena in multiple dimensions, such as waves and oscillations in electrical engineering. It's crucial to handle the real and imaginary parts properly in operations like addition, subtraction, multiplication, and division to accurately work with complex numbers.
Other exercises in this chapter
Problem 94
Let z \(=3-2 i\), \(u=-4+3 i, v=3+5 i\), and \(w=1-i .\) Compute the following expressions: \(z+u\)
View solution Problem 95
For each given pair of functions, use a graphing calculator to compare the functions. Describe what you see. \(y=\tan x\) and \(y=2 \tan x\)
View solution Problem 96
For each given pair of functions, use a graphing calculator to compare the functions. Describe what you see. \(y=\tan x\) and \(y=\tan (2 x)\)
View solution Problem 96
Let z \(=3-2 i\), \(u=-4+3 i, v=3+5 i\), and \(w=1-i .\) Compute the following expressions: \(\overline{v-w}\)
View solution