Problem 95
Question
If \(5 \mathrm{~g}\) of a radioactive substance has \(\mathrm{t}_{1 / 2}=14 \mathrm{hr}, 10 \mathrm{~g}\) of the same substance will have a \(t_{1 / 2}\) equal to (a) 14 hours (b) 28 hours (c) 50 hours (d) 70 hours
Step-by-Step Solution
Verified Answer
The correct answer is (a) 14 hours because the half-life is independent of the substance's mass.
1Step 1: Understanding Half-life
The half-life (\(t_{1/2}\) ) of a substance is the time required for a quantity to fall to half its initial value due to decay. One important characteristic is that the half-life is independent of the initial amount of the substance.
2Step 2: Applying Half-life Knowledge
Given that the half-life of the substance is 14 hours for 5 grams, we need to determine whether this changes when the mass is increased to 10 grams. Since half-life is an intrinsic property of the material and does not depend on the quantity, this value remains constant.
3Step 3: Selecting the Correct Answer
Since the half-life remains constant irrespective of the initial mass, the half-life for 10 grams is the same as for 5 grams. Therefore, it is still 14 hours, which corresponds to option (a).
Key Concepts
Half-lifeRadioactive SubstanceDecay Constant
Half-life
The half-life of a substance is a fascinating concept that helps us understand how certain materials degrade or lose their activity over time. Imagine a clock ticking on a piece of radioactive material, slowly losing its mass due to decay. Half-life is the period it takes for half of this material to disintegrate. It is a constant, unique property for each substance and is usually denoted by \( t_{1/2} \). Regardless of whether you start with 1 gram or 100 grams, the half-life remains the same.
**Example:** If you start with 10 grams of a substance with a half-life of 14 hours, after 14 hours, 5 grams will remain. After another 14 hours, 2.5 grams will remain, and so on.
**Example:** If you start with 10 grams of a substance with a half-life of 14 hours, after 14 hours, 5 grams will remain. After another 14 hours, 2.5 grams will remain, and so on.
- Half-life = Time for half of the substance to decay
- Constant over time
- Independent of initial quantity
Radioactive Substance
A radioactive substance is a material that contains unstable atoms which release energy in the form of radiation as they decay into more stable forms. This decay process is natural and occurs spontaneously. What makes a substance "radioactive" is its ability to emit radiation over time as it loses its unstable atomic particles.
**Characteristics of Radioactive Substances:**
**Characteristics of Radioactive Substances:**
- Contain unstable atoms
- Emit radiation during decay
- Decay into more stable elements
- Have unique half-lives
Decay Constant
The decay constant is a measure that helps to understand how quickly a radioactive substance undergoes decay. It is represented by the symbol \( \lambda \) and gives a sense of the proportionality of the decay rate of a substance. The larger the decay constant, the quicker the substance decays. Mathematically, it is related to the half-life and can be derived from the formula: \[ \lambda = \frac{\ln(2)}{t_{1/2}} \] Here, \( \ln(2) \approx 0.693 \) is the natural logarithm of 2, a constant value. The decay constant is incredibly useful because it provides insight on the time frame over which we can expect a radioactive substance to lose a significant amount of its mass.
**Key Points:**
**Key Points:**
- Relates to the rate of decay
- Inversely proportional to half-life
- Calculated using the natural logarithm of 2
Other exercises in this chapter
Problem 92
The radiations from a naturally occurring radioactive substance, as seen after deflection by a magnetic field in one direction, are (a) definitely beta rays (b)
View solution Problem 93
The half-life of a radio-isotope is three hours. If the mass of the undecayed isotope at the end of 18 hours is \(3.125 \mathrm{~g}\), what was its mass initial
View solution Problem 96
The energy released during the fission of \(1 \mathrm{~kg}\) of uranium is (a) \(9.0 \times 10^{16} \mathrm{erg}\) (b) \(9 \times 10^{20} \mathrm{erg}\) (c) \(9
View solution Problem 98
A radioactive element A decays by the sequence and with half-lives given below: \(\mathrm{A} \frac{\alpha}{30 \mathrm{~min}}>\mathrm{B} \frac{2 \beta}{2 \mathrm
View solution