Problem 94
Question
What is the value of \(x\) if \(32^{0.8} x=1 ?\) Simplify the answer.
Step-by-Step Solution
Verified Answer
The value of \(x\) in the given equation is \(\frac{1}{16}\).
1Step 1: Express the Given Equation
We start with the given equation \(32^{0.8} x = 1\). The aim is to find the value of \(x\).
2Step 2: Isolate the 'x'
In order to solve for \(x\), we should isolate it. We can do this by dividing both sides of the equation by \(32^{0.8}\). Like this: \[ x = \frac{1}{32^{0.8}} \]
3Step 3: Simplify the Value
The expression can be simplified by solving the exponent. In this case, \(32^{0.8}\) can be rewritten as \((2^5)^{0.8} = 2^{5*0.8} = 2^4 = 16\), giving us \[ x = \frac{1}{16} \]
Key Concepts
Exponent PropertiesIsolating VariablesSimplifying Expressions
Exponent Properties
Understanding exponent properties is crucial when solving exponential equations like the one in this exercise. Exponents indicate how many times a number, known as the base, is multiplied by itself. A simple example is that in the term \( a^b \), \( a \) is the base and \( b \) is the exponent. Here, the base \( a \) is raised to the power of \( b \).
When dealing with exponents, certain rules make calculations easier:
When dealing with exponents, certain rules make calculations easier:
- Product of Powers: For the same base, you can add exponents: \( a^m \times a^n = a^{m+n} \).
- Power of a Power: Multiply exponents: \( (a^m)^n = a^{m\cdot n} \).
- Quotient of Powers: Subtract exponents: \( \frac{a^m}{a^n} = a^{m-n} \).
- Zero Exponent: Any base raised to zero equals one: \( a^0 = 1 \).
- Negative Exponent: Turn into a reciprocal: \( a^{-m} = \frac{1}{a^m} \).
Isolating Variables
Isolating the variable is a key step in solving equations. The goal is to have the variable on one side of the equation, all by itself. This process makes it possible to determine its value.
In the equation \(32^{0.8} x = 1\), our aim is to solve for \(x\). The simplest way to isolate \(x\) is to perform the opposite operation of what is currently being applied to it. Here, \(x\) is multiplied by \(32^{0.8}\), meaning we should divide both sides by \(32^{0.8}\).
This step ensures:
In the equation \(32^{0.8} x = 1\), our aim is to solve for \(x\). The simplest way to isolate \(x\) is to perform the opposite operation of what is currently being applied to it. Here, \(x\) is multiplied by \(32^{0.8}\), meaning we should divide both sides by \(32^{0.8}\).
This step ensures:
- The variable \(x\) stands alone on one side: \(x = \frac{1}{32^{0.8}}\).
- The other side of the equation becomes the value representing \(x\).
Simplifying Expressions
Simplifying expressions is the process of making them as straightforward as possible. After isolating \(x\) in our original equation, the result was \(x = \frac{1}{32^{0.8}}\).
To simplify, it's helpful to first express the base in a simpler form. Here, 32 can be rewritten as \(2^5\), which is a smaller base with a known power. Using exponent properties, we further simplify:
Breaking complex expressions into smaller parts allows us to see the solution clearly. It makes calculations more manageable and ensures accurate results. Always aim to simplify step by step to avoid mistakes.
To simplify, it's helpful to first express the base in a simpler form. Here, 32 can be rewritten as \(2^5\), which is a smaller base with a known power. Using exponent properties, we further simplify:
- Convert \(32^{0.8}\) into \((2^5)^{0.8}\).
- By applying the power of a power rule, multiply the exponents: \(2^{5 \cdot 0.8}\), resulting in \(2^4\).
- Since \(2^4\) equals 16, we now have \(x = \frac{1}{16}\).
Breaking complex expressions into smaller parts allows us to see the solution clearly. It makes calculations more manageable and ensures accurate results. Always aim to simplify step by step to avoid mistakes.
Other exercises in this chapter
Problem 93
Which number is closest to \(\left(81 n^{2}\right)^{0.75}\) for \(n=2 ?\) \(\begin{array}{llll}{\text { E. } 45.4} & {\text { G. } 76.4} & {\text { H. } 243.0}
View solution Problem 94
If \(f(x)=3 x-4\) and \(g(x)=x+3,\) what does \((f \cdot g)(x)\) mean? What is \((f \cdot g)(x) ?\) Simplify the answer.
View solution Problem 95
Solve. Check for extraneous solutions. $$ \sqrt{x^{2}+3}=x+1 $$
View solution Problem 95
For \(x>0\) and \(y>0,\) write \(\sqrt{9 x^{5} y^{-6}}\) in simplest form.
View solution