Problem 94
Question
Give the exact real number value of each expression. Do not use a calculator. $$\cos \left(\sin ^{-1} \frac{3}{5}+\cos ^{-1} \frac{5}{13}\right)$$
Step-by-Step Solution
Verified Answer
The exact value of the expression is \(-\frac{16}{65}\).
1Step 1: Understanding the Problem
We need to find the exact value of the expression \( \cos \left( \sin^{-1} \frac{3}{5} + \cos^{-1} \frac{5}{13} \right) \). This involves using trigonometric identities and inverse trigonometric functions.
2Step 2: Define the Angles Using Inverse Functions
Let \( \theta = \sin^{-1} \frac{3}{5} \) and \( \beta = \cos^{-1} \frac{5}{13} \). This implies that \( \sin \theta = \frac{3}{5} \) and \( \cos \beta = \frac{5}{13} \). We need to find \( \cos(\theta + \beta) \).
3Step 3: Use Trigonometric Identities
We will use the identity \( \cos(\theta + \beta) = \cos \theta \cos \beta - \sin \theta \sin \beta \). We already have \( \cos \beta = \frac{5}{13} \) and \( \sin \theta = \frac{3}{5} \). We need to find \( \cos \theta \) and \( \sin \beta \).
4Step 4: Find Remaining Trigonometric Values
For \( \sin \theta = \frac{3}{5} \), using \( \cos^2 \theta = 1 - \sin^2 \theta \), we get \( \cos \theta = \sqrt{1 - \left(\frac{3}{5}\right)^2} = \frac{4}{5} \). For \( \cos \beta = \frac{5}{13} \), using \( \sin^2 \beta = 1 - \cos^2 \beta \), we get \( \sin \beta = \sqrt{1 - \left(\frac{5}{13}\right)^2} = \frac{12}{13} \).
5Step 5: Calculate \( \cos(\theta + \beta) \)
Substitute our known values into the identity: \( \cos(\theta + \beta) = \frac{4}{5} \cdot \frac{5}{13} - \frac{3}{5} \cdot \frac{12}{13} \). This simplifies to \( \cos(\theta + \beta) = \frac{20}{65} - \frac{36}{65} = \frac{-16}{65} \).
Key Concepts
Inverse Trigonometric FunctionsExact ValuesCosine Sum Formula
Inverse Trigonometric Functions
Inverse trigonometric functions play a significant role when dealing with angles and their ratios. They are the reverse operations of the standard trigonometric functions like sine, cosine, and tangent.
Instead of finding the ratio from an angle, they help find the angle from a given ratio. For example,
Instead of finding the ratio from an angle, they help find the angle from a given ratio. For example,
\( \sin^{-1} \)or arcsin is used when you have the sine ratio and need the angle.\( \cos^{-1} \)or arccos is used when you have the cosine ratio and need the angle.
- \( \sin^{-1} \frac{3}{5} \) determines the angle whose sine is
3/5. The result can be denoted as \( \theta \). - \( \cos^{-1} \frac{5}{13} \) determines the angle whose cosine is
5/13. The result can be denoted as \( \beta \).
Exact Values
Exact values in trigonometry allow us to resolve expressions without relying on decimal approximations. When finding the precise value of trigonometric expressions, we often revert to fundamental properties and identities.
In the problem at hand, determining exact trigonometric values involves finding the complementary or supplementary trigonometric values based on known ratios.
In the problem at hand, determining exact trigonometric values involves finding the complementary or supplementary trigonometric values based on known ratios.
- Given \( \sin \theta = \frac{3}{5} \), we find \( \cos \theta \) using the Pythagorean identity: \( \cos^2 \theta = 1 - \sin^2 \theta \), leading to \( \cos \theta = \frac{4}{5} \).
- Similarly, \( \cos \beta = \frac{5}{13} \) was used to find \( \sin \beta \) in the same manner, resulting in \( \sin \beta = \frac{12}{13} \).
Cosine Sum Formula
The cosine sum formula is essential in trigonometry for combining angles. It expresses the cosine of the sum of two angles in terms of their individual sines and cosines.
The formula is:
The formula is:
- \( \cos(\theta + \beta) = \cos \theta \cos \beta - \sin \theta \sin \beta \).
- Using known values: \( \cos \theta = \frac{4}{5} \) and \( \cos \beta = \frac{5}{13} \), and the previously calculated \( \sin \theta = \frac{3}{5} \) and \( \sin \beta = \frac{12}{13} \).
- The substitution into the formula gives \( \frac{4}{5} \times \frac{5}{13} - \frac{3}{5} \times \frac{12}{13} \).
- Solving these multiplications and performing a straightforward subtraction leads us to the exact answer: \( \frac{-16}{65} \).
Other exercises in this chapter
Problem 93
Verify that equation is an identity. \(\frac{(\sec \theta-\tan \theta)^{2}+1}{\sec \theta \csc \theta-\tan \theta \csc \theta}=2 \tan \theta\)
View solution Problem 94
Verify that each equation is an identity by using any of the identities introduced in the first three sections of this chapter. $$\frac{1-\sin t}{\cos t}=\frac{
View solution Problem 94
Verify that equation is an identity. \(\frac{1}{1-\sin \theta}+\frac{1}{1+\sin \theta}=2 \sec ^{2} \theta\)
View solution Problem 95
Give the exact real number value of each expression. Do not use a calculator. $$\sin \left(\sin ^{-1} \frac{1}{2}+\tan ^{-1}(-3)\right)$$
View solution