Problem 94
Question
Estimate the temperature needed to achieve the fusion of deuterium to make an \(\alpha\) particle. The energy required can be estimated from Coulomb's law [use the form \(E=9.0 \times 10^{9}\) \(\left(Q_{1} Q_{2} / r\right),\) using \(Q=1.6 \times 10^{-19} \mathrm{C}\) for a proton, and \(r=2 \times\) \(10^{-15} \mathrm{m}\) for the helium nucleus; the unit for the proportionality constant in Coloumb's law is J \(\cdot \mathrm{m} / \mathrm{C}^{2} ]\)
Step-by-Step Solution
Verified Answer
To estimate the temperature needed for the fusion of deuterium to make an α particle (helium nucleus), we can use Coulomb's law to first calculate the energy required for the process. Using the given values, we find the energy to be approximately \(E \approx 7.68 \times 10^{-13} \mathrm{J}\). To relate this energy to temperature, we can use the equipartition theorem, which gives us the temperature value as approximately \(T \approx 3.71 \times 10^7 \mathrm{K}\). Therefore, the estimated temperature needed for the fusion of deuterium to make an α particle is approximately \(3.71\times 10^7 \mathrm{K}\).
1Step 1: Understand the given data
We are given the form of Coulomb's law as:
\[ E = 9.0 \times 10^9 \frac{Q_1 Q_2}{r} \]
where
\(Q_1\) and \(Q_2\) are the charges of the two particles (in this case, deuterium nuclei) with unit charge, i.e., the charge of a proton,
\(Q = 1.6 \times 10^{-19} \mathrm{C}\),
\(r = 2 \times 10^{-15} \mathrm{m}\) is the separation between the protons in the helium nucleus.
2Step 2: Calculate the energy using Coulomb's law
Using the given values, we can calculate the energy required for the fusion process:
\[ E = 9.0 \times 10^9 \frac{(1.6 \times 10^{-19})^2}{2 \times 10^{-15}} \]
Calculate this expression to find the energy value:
\[ E \approx 7.68 \times 10^{-13} \mathrm{J} \]
3Step 3: Estimate the temperature needed
Now, we need to estimate the temperature needed for the fusion process. We can relate energy and temperature using the equipartition theorem, which states that the average kinetic energy per particle is given by:
\[ \frac{3}{2} k_B T = E \]
where \(k_B = 1.38 \times 10^{-23} \mathrm{J/K}\) is the Boltzmann constant and \(T\) is the temperature in Kelvin.
Plugging in the energy value we found in step 2, we can solve for temperature:
\[ T = \frac{2E}{3k_B} = \frac{2 (7.68 \times 10^{-13} \mathrm{J})}{3 (1.38 \times 10^{-23} \mathrm{J/K})} \]
Calculate this expression to find the temperature value:
\[ T \approx 3.71 \times 10^7 \mathrm{K} \]
So, the estimated temperature needed to achieve the fusion of deuterium to make an α particle is approximately \(3.71\times 10^7 \mathrm{K}\).
Key Concepts
Deuteriumα ParticleCoulomb's LawEquipartition Theorem
Deuterium
Deuterium is an isotope of hydrogen. Unlike the more common hydrogen atom, which contains just a single proton, deuterium has both a proton and a neutron in its nucleus. This makes deuterium twice as heavy as ordinary hydrogen. It is often referred to as "heavy hydrogen" due to its extra neutron.
Deuterium plays a crucial role in nuclear fusion processes:
Deuterium plays a crucial role in nuclear fusion processes:
- Nuclear fusion reactions involving deuterium can produce significant amounts of energy.
- In the case of deuterium-deuterium (D-D) fusion, two deuterium nuclei combine to form either helium-3 and a neutron or tritium and a proton.
α Particle
The α particle, or alpha particle, is a type of ionizing radiation. It consists of two protons and two neutrons bound together, which is why it is identical to the nucleus of a helium atom.
Alpha particles are commonly emitted during radioactive decay:
- They typically come from the decay of heavy elements such as uranium, radium, and thorium.
- Because α particles have a +2 charge, they interact strongly with matter and can be stopped by a sheet of paper or human skin.
Coulomb's Law
Coulomb's Law describes the electrostatic interaction between charged particles. It states that the force between two charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. The formula is often written as:\[ F = k \frac{Q_1 Q_2}{r^2} \]where:
- \( F \) is the electrostatic force between the charges.
- \( k = 9.0 \times 10^9 \text{ Nm}^2/\text{C}^2 \) is the electrostatic constant.
- \( Q_1 \) and \( Q_2 \) are the charges.
- \( r \) is the separation distance between the charges.
Equipartition Theorem
The Equipartition Theorem is a principle of statistical mechanics. It states that energy is equally distributed among all available degrees of freedom of a system, each contributing \( \frac{1}{2} k_B T \) to the system's total energy, where \( k_B \) is the Boltzmann constant and \( T \) is the temperature.In the case of gases and other systems in thermal equilibrium:
- The translational kinetic energy for each degree of freedom is \( \frac{1}{2} k_B T \).
- For three-dimensional motion, as with gas particles, the total translational energy is therefore \( \frac{3}{2} k_B T \).
Other exercises in this chapter
Problem 92
The most significant source of natural radiation is radon-222. \(^{222} \mathrm{Rn},\) a decay product of \(^{238} \mathrm{U},\) is continuously generated in th
View solution Problem 93
To determine the \(K_{\mathrm{sp}}\) value of \(\mathrm{Hg}_{2} \mathrm{I}_{2},\) a chemist obtained a solid sample of \(\mathrm{Hg}_{2} \mathrm{I}_{2}\) in whi
View solution Problem 95
A reported synthesis of the transuranium element bohrium (Bh) involved the bombardment of berkelium-249 with neon-22 to produce bohrium-267. Write a nuclear rea
View solution Problem 96
Radioactive cobalt-60 is used to study defects in vitamin \(\mathrm{B}_{12}\) absorption because cobalt is the metallic atom at the center of the vitamin \(\mat
View solution