Problem 93
Question
What are the electron configurations of \(\mathrm{Li}, \mathrm{Li}^{+}, \mathrm{Ca}, \mathrm{F}^{-}\) \(\mathrm{Na}^{+}, \mathrm{Mg}^{2+},\) and \(\mathrm{Al}^{3+} ?\)
Step-by-Step Solution
Verified Answer
Based on the step-by-step solution above, the electron configurations for the given atoms and ions are:
1. Li: 1s²2s¹
2. Li+: 1s²
3. Ca: 1s²2s²2p⁶3s²3p⁶4s²3d⁰
4. F-: 1s²2s²2p⁶
5. Na+: 1s²2s²2p⁶
6. Mg2+: 1s²2s²2p⁶
7. Al3+: 1s²2s²2p⁶
Provide the corresponding electron configuration for each of the given atoms and ions.
1Step 1: Determine the atomic numbers of the elements
To find the electron configurations for each atom and ion, we need to first determine the atomic numbers (number of protons) for the given elements. Using the periodic table, we can find the atomic numbers for Li (Lithium), Ca (Calcium), F (Fluorine), Na (Sodium), Mg (Magnesium), and Al (Aluminum).
Li: Atomic Number = 3
Ca: Atomic Number = 20
F: Atomic Number = 9
Na: Atomic Number = 11
Mg: Atomic Number = 12
Al: Atomic Number = 13
2Step 2: Find electrons for the given ions
Next, we need to determine the number of electrons for each ion. For neutral atoms, the number of electrons is the same as the atomic number. For ions, we adjust the number of electrons based on the charge of the ion.
Li: 3 electrons
Li+: 3 - 1 = 2 electrons
Ca: 20 electrons
F-: 9 + 1 = 10 electrons
Na+: 11 - 1 = 10 electrons
Mg2+: 12 - 2 = 10 electrons
Al3+: 13 - 3 = 10 electrons
3Step 3: Write the electron configurations based on Aufbau principle, Hund's rule, and Pauli Exclusion Principle
Now, we can find the electron configurations for each atom/ion:
Li (3 electrons):
1s²2s¹
Li+ (2 electrons):
1s²
Ca (20 electrons):
1s²2s²2p⁶3s²3p⁶4s²3d⁰
F- (10 electrons):
1s²2s²2p⁶
Na+ (10 electrons):
1s²2s²2p⁶
Mg2+ (10 electrons):
1s²2s²2p⁶
Al3+ (10 electrons):
1s²2s²2p⁶
So, the electron configurations for the given atoms/ions are:
Li: 1s²2s¹
Li+: 1s²
Ca: 1s²2s²2p⁶3s²3p⁶4s²3d⁰
F-: 1s²2s²2p⁶
Na+: 1s²2s²2p⁶
Mg2+: 1s²2s²2p⁶
Al3+: 1s²2s²2p⁶
Key Concepts
Atomic NumberIonsAufbau Principle
Atomic Number
The atomic number of an element is a fundamental property that tells us how many protons are in the nucleus of its atoms. It is unique for each element and can be found on the periodic table. In neutral atoms, the atomic number is equal to the number of electrons, defining its electron configuration. Knowing the atomic number is crucial when determining the basic electron setup of any atom.
For instance:
For instance:
- Lithium (Li) has an atomic number of 3, so it contains 3 protons and, in its neutral state, 3 electrons.
- Calcium (Ca) has an atomic number of 20, with 20 protons and 20 electrons in its neutral form.
- Fluorine (F) holds an atomic number of 9, so it has 9 protons and 9 electrons if neutral.
- Sodium (Na), Magnesium (Mg), and Aluminum (Al) have respective atomic numbers of 11, 12, and 13.
Ions
Ions are atoms or molecules that have gained or lost one or more electrons, resulting in a net charge. This process changes the electron configuration from that of a neutral atom, affecting the chemical properties. Ions are crucial in chemical reactions and biological processes.
For example:
For example:
- A lithium ion (Li⁺) has lost one electron compared to its neutral state, leaving it with only 2 electrons.
- A fluoride ion (F⁻), however, has gained an electron, resulting in 10 electrons total, like a neon atom.
- Sodium and magnesium form Na⁺ and Mg²⁺ ions by losing electrons, achieving stable electron configurations similar to Ne.
Aufbau Principle
The Aufbau principle is a rule used to systematically build electron configurations in atoms. It states that electrons fill atomic orbitals of the lowest available energy level before occupying higher levels. This helps in determining how electrons are distributed among the orbitals.
According to the Aufbau principle:
According to the Aufbau principle:
- Electrons first fill the 1s orbital before moving to the 2s, then to the 2p, and so on.
- For instance, calcium (Ca) with 20 electrons, would fill orbitals in the order: 1s², 2s², 2p⁶, 3s², 3p⁶, then 4s².
- For ions, the same principle applies after adjusting the total number of electrons as per the ion's charge.
Other exercises in this chapter
Problem 91
List the following orbitals in order of increasing energy in a multielectron atom: a. \(n=3, \ell=2\) b. \(n=5, \ell=1\) c. \(n=3, \ell=0\) d. \(n=4, \ell=1, m_
View solution Problem 92
Place the following orbitals in order of increasing energy in a multielectron atom: a. \(n=2, \ell=1\) b. \(n=5, \ell=3\) c. \(n=3, \ell=2\) d. \(n=4, \ell=3\)
View solution Problem 95
What are the condensed electron configurations of \(\mathrm{K}, \mathrm{K}^{+}\) \(\mathrm{S}^{2-}, \mathrm{N}, \mathrm{Ba}, \mathrm{Ti}^{4+},\) and \(\mathrm{A
View solution Problem 96
In what way are the electron configurations of \(\mathrm{H}, \mathrm{Li}, \mathrm{Na}, \mathrm{K}\) \(\mathrm{Rb},\) and \(\mathrm{Cs}\) similar?
View solution