Problem 93
Question
Solve each equation. If necessary, round to the nearest ten-thousandth. $$ 4^{3 x}=77.2 $$
Step-by-Step Solution
Verified Answer
\(x\)=0.7802
1Step 1: Apply logarithms
Apply a natural logarithm (ln) to both sides of the equation. This gives us \(ln(4^{3 x})=ln(77.2)\).
2Step 2: Use properties of logarithms
Use properties of logarithms to bring down the exponent: \(3 x \cdot ln(4)=ln(77.2)\).
3Step 3: Isolate the variable
To isolate \(x\), divide both sides of the equation by \(3 ln(4)\). Giving \(x=\frac{ln(77.2)}{3 \cdot ln(4)}\).
4Step 4: Compute the value
Now calculate the numerical value using a calculator. Please remember to round the final answer to the nearest ten-thousandth if necessary.
Key Concepts
Natural LogarithmsProperties of LogarithmsSolving for Variables
Natural Logarithms
Natural logarithms are a fascinating and essential part of mathematics, especially when dealing with exponential equations. They are logarithms with the base "e," where "e" is approximately 2.71828. Unlike common logarithms that use "10" as their base, natural logarithms are often applied when working with natural growth patterns in science and mathematics.
To denote a natural logarithm, we use "ln", as seen in expressions like \( \ln(x) \). Acting as the inverse operation of exponential functions, they help simplify expressions involving exponents, making it easier to handle equations such as exponential growth or decay.
For instance, when solving the exponential equation \( 4^{3x} = 77.2 \), applying \( \ln \) to both sides helps manage the exponent, setting the stage for using more fundamental properties of logarithms.
To denote a natural logarithm, we use "ln", as seen in expressions like \( \ln(x) \). Acting as the inverse operation of exponential functions, they help simplify expressions involving exponents, making it easier to handle equations such as exponential growth or decay.
For instance, when solving the exponential equation \( 4^{3x} = 77.2 \), applying \( \ln \) to both sides helps manage the exponent, setting the stage for using more fundamental properties of logarithms.
Properties of Logarithms
The properties of logarithms are tools that make complex equations easier to handle. These properties transform challenging problems into more manageable forms.
One of the most crucial properties used in solving exponential equations is the "power rule," which states that \( \ln(a^b) = b \cdot \ln(a) \). This rule allows us to bring exponents down to the line in calculations, making it significantly simpler to isolate variables.
There's also the "product rule" \( \ln(ab) = \ln(a) + \ln(b) \) and the "quotient rule" \( \ln(\frac{a}{b}) = \ln(a) - \ln(b) \). Together, these properties provide flexibility in breaking down logarithmic expressions.
In our example with \( 4^{3x} = 77.2 \), we used the power rule to get \( 3x \cdot \ln(4) = \ln(77.2) \), which is crucial for simplifying the equation further.
One of the most crucial properties used in solving exponential equations is the "power rule," which states that \( \ln(a^b) = b \cdot \ln(a) \). This rule allows us to bring exponents down to the line in calculations, making it significantly simpler to isolate variables.
There's also the "product rule" \( \ln(ab) = \ln(a) + \ln(b) \) and the "quotient rule" \( \ln(\frac{a}{b}) = \ln(a) - \ln(b) \). Together, these properties provide flexibility in breaking down logarithmic expressions.
In our example with \( 4^{3x} = 77.2 \), we used the power rule to get \( 3x \cdot \ln(4) = \ln(77.2) \), which is crucial for simplifying the equation further.
Solving for Variables
Solving for variables is a key skill in mathematics, often requiring several steps to ensure that the variable is successfully isolated. It is a process of rearranging an equation so that the variable stands alone on one side of the equation sign.
In our equation \( 3x \cdot \ln(4) = \ln(77.2) \), we isolate \( x \) by dividing both sides by \( 3 \cdot \ln(4) \). This action rearranges the equation into \( x = \frac{\ln(77.2)}{3 \cdot \ln(4)} \).
The final step is computing the value of \( x \) using a calculator. It emphasizes precision, as numbers should often be rounded to a specified decimal place, like ten-thousandths here. By following these systematic steps, solving equations becomes a logical and orderly procedure.
In our equation \( 3x \cdot \ln(4) = \ln(77.2) \), we isolate \( x \) by dividing both sides by \( 3 \cdot \ln(4) \). This action rearranges the equation into \( x = \frac{\ln(77.2)}{3 \cdot \ln(4)} \).
The final step is computing the value of \( x \) using a calculator. It emphasizes precision, as numbers should often be rounded to a specified decimal place, like ten-thousandths here. By following these systematic steps, solving equations becomes a logical and orderly procedure.
Other exercises in this chapter
Problem 92
What is the logarithmic form of the exponential equation \(2^{4}=16 ?\) $$ \mathrm{F} . \log _{16} 2=4 \quad \text { G. } \log _{16} 4=2 \quad \text { H. } \log
View solution Problem 93
Which expression is equal to \(\log _{5} x+4 \cdot \log _{5} y-2 \cdot \log _{5} z ?\) \(\begin{array}{llll}{\text { A. } \log _{5}(-8 x y z)} & {\text { B. }-\
View solution Problem 93
Which function is the inverse of \(f(x)=2^{x-1} ?\) $$ \begin{array}{ll}{\text { A. } f^{-1}(x)=\log _{2}(x-1)} & {\text { B. } f^{-1}(x)=\log _{2}(x+1)} \\ {\t
View solution Problem 94
\(\log _{5} 10 \approx 1.4307\) and \(\log _{5} 20 \approx 1.8614 .\) Find the value of \(\log _{5}\left(\frac{1}{2}\right)\) without using a calculator. Explai
View solution