Problem 93
Question
Show that a gamma pdf has the unique mode \(\frac{r-1}{\lambda}\); that is, show that the function \(f_{Y}(y)=\frac{\alpha^{\prime}}{\Gamma(r)} y^{\prime-1} e^{-\lambda y}\) takes its maximum value at \(y_{\text {mode }}=\frac{r-1}{\lambda}\) and at no other point.
Step-by-Step Solution
Verified Answer
To show the Gamma pdf has a unique mode at \(y_{\text {mode}}=\frac{r-1}{\lambda}\), differentiate the function and set it equal to zero. Solve for y to get the critical points. Verify that the unique mode is \(\frac{r-1}{\lambda}\) by substituting it into the locations where y equals the solution from the differentiation.
1Step 1: Identify the function and mode
The Gamma pdf is given as \(f_{Y}(y)=\frac{\alpha^{\prime}}{\Gamma(r)} y^{\prime-1} e^{-\lambda y}\). The mode which we expect the function to achieve its maximum is \(y_{\text {mode}}=\frac{r-1}{\lambda}\).
2Step 2: Differentiate the Gamma pdf
Differentiate the function with respect to y. Noting that the derivative of \(y^{\prime-1}\) is \((\prime-1)y^{\prime-2}\) and the derivative of \(e^{-\lambda y}\) is \(-\lambda e^{-\lambda y}\), the derivative of the function \(f_{Y}(y)\) can be found.
3Step 3: Find the critical points
Set the derivative of the function to zero and solve for y. This gives the critical points of the function.
4Step 4: Verify the mode
Substitute \(\frac{r-1}{\lambda}\) into the places where y equals the solution from step 3. If it is true, then it shows that the function reaches its maximum at \(y_{\text {mode}}=\frac{r-1}{\lambda}\) and at no other point.
Key Concepts
Probability Density FunctionMode of a DistributionDifferentiation in CalculusCritical Points in Functions
Probability Density Function
In the realm of statistics, the **Probability Density Function** (PDF) is fundamental when dealing with continuous random variables. A PDF specifies the likelihood of a given random variable falling within a specific range. For the Gamma Distribution, the PDF is given by the formula:\[f_{Y}(y) = \frac{\alpha^{'}}{\Gamma(r)} y^{\prime-1} e^{-\lambda y}\]Here:
- \(\alpha^{'}\) and \(\Gamma(r)\) are constants.
- \(y^{\prime-1}\) represents raising \(y\) to the power minus one.
- \(e^{-\lambda y}\) is an exponential decay based on the parameter \(\lambda\).
Mode of a Distribution
The **Mode of a Distribution** is a well-known statistical measure that indicates the value at which a probability distribution attains its highest peak. In simpler terms, for a continuous distribution like the Gamma distribution, it's where the PDF is at its greatest.When exploring the Gamma distribution, we are interested in finding the mode of the PDF, which effectively captures the most "likely" outcome. In our case, this mode is theoretically predicted to be:\[y_{\text{mode}} = \frac{r-1}{\lambda}\]This formula suggests that as the shape parameter \(r\) increases, the mode also shifts to the right, provided that \(\lambda\) remains constant. Understanding the mode helps in summarizing the central tendency of the distribution.
Differentiation in Calculus
**Differentiation in Calculus** is a powerful tool used to explore functions, including determining maxima and minima. It involves computing the derivative of a function with respect to an independent variable to see how the function behaves as that variable changes.In the exercise related to the Gamma distribution, differentiation is used to find the derivative of the Gamma PDF. By differentiating:\[f_{Y}(y) = \frac{\alpha^{'}}{\Gamma(r)} y^{\prime-1} e^{-\lambda y}\]We look for where this derivative equals zero, as these points suggest potential maxima or minima, known as critical points. The first derivative tells us about the function's slope, and a zero-value derivative often indicates a turning point, useful in identifying modes, as we are doing here.
Critical Points in Functions
**Critical Points in Functions** are vital in understanding the behavior of functions. They occur where the derivative of a function is zero or undefined, and they may indicate places where the function reaches a local maximum, a local minimum, or a saddle point.In the context of the Gamma PDF, finding critical points involves setting the derivative to zero and solving for \(y\). These critical points are candidates for the mode of the distribution, where the function could potentially achieve its maximum value.In our problem, the critical point\[y_{\text{critical}} = \frac{r-1}{\lambda}\]matches our predicted mode. By verifying this point against our PDF, we confirm it achieves the maximum value at this particular point and thus identify it as the distribution's mode. This verification emphasizes the importance of critical points in assessing distribution properties.
Other exercises in this chapter
Problem 89
An Arctic weather station has three electronic wind gauges. Only one is used at any given time. The lifetime of each gauge is exponentially distributed with a m
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Demonstrate that \(\lambda\) plays the role of a scale parameter by showing that if \(Y\) is gamma with parameters \(r\) and \(\lambda\), then \(\lambda Y\) is
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Prove that \(\Gamma\left(\frac{1}{2}\right)=\sqrt{\pi}\). (Hint: Consider \(E\left(Z^{2}\right)\), where \(Z\) is a standard normal random variable.)
View solution Problem 95
Show that \(\Gamma\left(\frac{7}{2}\right)=\frac{15}{8} \sqrt{\pi}\).
View solution