Problem 93
Question
Here is the definition of infinite right-hand limit. \begin{equation} \begin{array}{l}{\text { We say that } f(x) \text { approaches infinity as } x \text { approaches } c \text { from the }} \\ {\text { right, and write }}\end{array} \end{equation} \begin{equation} \lim _{x \rightarrow c^{+}} f(x)=\infty, \end{equation} \begin{equation} \begin{array}{l}{\text { if, for every positive real number } B \text { , there exists a corresponding }} \\ {\text { number } \delta>0 \text { such that for all } x}\end{array} \end{equation} \begin{equation} c < x < c+\delta \quad \Rightarrow \quad f(x)>B. \end{equation} Modify the definition to cover the following cases. $$\text{ a. }\lim _{x \rightarrow c^{-}} f(x)=\infty$$ $$\text{ b. }\lim _{x \rightarrow c^{+}} f(x)=-\infty$$ $$\text{ c. }\lim _{x \rightarrow c^{-}} f(x)=-\infty$$
Step-by-Step Solution
VerifiedKey Concepts
Right-Hand Limit
- To say \( f(x) \to \infty \) as \( x \to c^+ \), is to claim that for any number \( B \), you can find a range such that if \( x \) falls within this range (\( c < x < c + \delta \)), \( f(x) \) is greater than \( B \).
Left-Hand Limit
- For \( f(x) \to \infty \) as \( x \to c^- \), it means that for any positive number \( B \), you can choose a range where \( x \) lies within (\( c - \delta < x < c \)), ensuring \( f(x) \) exceeds \( B \).
Infinity in Limits
- If \( \lim_{x \to c^+} f(x) = -\infty \), for every negative number \( A \), there's a range such that any \( x \) within it results in \( f(x) \) being less than \( A \).
- For both right-left and negative-infinity scenarios, a precise range \( \delta \) (a gap) allows you to predict if the function dives negatively indefinitely.