Problem 93
Question
Factor each trinomial completely. \(4 x^{2}(y-1)^{2}+25 x(y-1)^{2}+25(y-1)^{2}\)
Step-by-Step Solution
Verified Answer
The trinomial factors to \((y-1)^{2}(2x + 5)^{2}\).
1Step 1: Identify Common Factor
The given trinomial is \(4x^{2}(y-1)^{2} + 25x(y-1)^{2} + 25(y-1)^{2}\). Observe that \((y-1)^{2}\) is a common factor for each term.
2Step 2: Factor Out the Common Factor
Extract \((y-1)^{2}\) from the trinomial, which gives: \((y-1)^{2}(4x^{2} + 25x + 25)\).
3Step 3: Recognize the Perfect Square Trinomial
Identify that the expression inside the parentheses, \(4x^{2} + 25x + 25\), is a perfect square trinomial. It can be rearranged into the form \((2x + 5)^{2}\) since: - \((2x)^{2} = 4x^{2}\), - \(2 \cdot (2x) \cdot 5 = 20x + 5x = 25x\), - \(5^{2} = 25\).
4Step 4: Write the Completely Factored Form
Substitute the perfect square trinomial back into the expression to write the fully factored form: \((y-1)^{2}(2x + 5)^{2}\).
Key Concepts
Common FactorPerfect Square TrinomialFactoring Techniques
Common Factor
When factoring trinomials, one of the first steps is to look for a common factor. A common factor is a term that appears in every part of the expression. Identifying this can significantly simplify the process of factoring.
In the given trinomial, we see that \((y-1)^{2}\) is a common factor in all the terms: \(4x^{2}(y-1)^{2}\), \(25x(y-1)^{2}\), and \(25(y-1)^{2}\). This means that each part of the expression includes \((y-1)^{2}\), making it an ideal candidate to be factored out.
In the given trinomial, we see that \((y-1)^{2}\) is a common factor in all the terms: \(4x^{2}(y-1)^{2}\), \(25x(y-1)^{2}\), and \(25(y-1)^{2}\). This means that each part of the expression includes \((y-1)^{2}\), making it an ideal candidate to be factored out.
- Extracting common factors can simplify the expression.
- It sets the stage for further factoring steps.
Perfect Square Trinomial
A perfect square trinomial is a special pattern which can be factored into a binomial squared. Recognizing these patterns can greatly reduce the complexity of factoring.
In this exercise, once \((y-1)^{2}\) is factored out, we are left with the expression \(4x^{2} + 25x + 25\). This expression is a classic example of a perfect square trinomial.
In this exercise, once \((y-1)^{2}\) is factored out, we are left with the expression \(4x^{2} + 25x + 25\). This expression is a classic example of a perfect square trinomial.
- First, notice that \((2x)^{2} = 4x^{2}\).
- Then we check if the middle term, \(25x\), matches the pattern \(2 imes ext{{first term}} imes ext{{last term}}\).
- Finally, verify that \(5^{2} = 25\) is indeed the last term.
Factoring Techniques
Factoring techniques are the fundamental methods used to break down complex polynomials into simpler expressions.
In the given trinomial, a combination of techniques is applied:
In the given trinomial, a combination of techniques is applied:
- Initial factoring involves finding and removing common factors, in this case, \((y-1)^{2}\), to simplify the trinomial.
- Next, recognizing the structure of a perfect square trinomial helps us use the technique more efficiently.
- Finally, applying these combined techniques results in the completely factored form: \((y-1)^{2}(2x + 5)^{2}\).
Other exercises in this chapter
Problem 93
\(\left(x^{2}+6 x+9\right)-4 y^{2}\) (Hint: Factor the trinomial in parentheses first.)
View solution Problem 93
Which of the following is/are factored form(s) of \(-2 x+14 ?\) a. \(-2(x+7)\) b. \(-2 \cdot x+14\) c. \(-2(x-14)\) d. \(-2(x-7)\)
View solution Problem 94
\(\left(x^{2}+2 x+1\right)-36 y^{2}\) (Hint: Factor the trinomial in parentheses first.)
View solution Problem 94
Which of the following is/are factored form(s) of \(8 a-24 ?\) a. \(8 \cdot a-24\) b. \(8(a-3)\) c. \(4(2 a-12)\) d. \(8 \cdot a-2 \cdot 12\)
View solution