Problem 93
Question
Explain how to multiply two binomials using the FOIL method. Give an example with your explanation.
Step-by-Step Solution
Verified Answer
To utilize the FOIL method, first, treat each binomial as a separate entity and multiply the first terms of each, then the outer terms, followed by the inner terms, and finally, the last terms. Addition of these four products yields the final result. For the binomials \( (a+b) \) and \( (x+y) \), the answer using the FOIL method will be \( ax + ay + bx + by \).
1Step 1: Introduction of the binomials
Let's take two binomials as \( (a+b) \) and \( (x+y) \). We have to multiply these binomials using the FOIL method.
2Step 2: Applying the 'First' Step
First means we multiply the first terms in each binomial. Here it would be \( a \) and \( x \), yielding \( a*x \) as the first term of our result.
3Step 3: Applying the 'Outer' and 'Inner' Steps
Outer means we multiply the outside terms in the product, which are \( a \) and \( y \). Inner means we multiply the inside terms, \( b \) and \( x \). These yield \( a*y \) and \( b*x \) respectively.
4Step 4: Applying the 'Last' Step
Last means we multiply the last terms in each binomial, which are \( b \) and \( y \), to yield \( b*y \).
5Step 5: Combining the Results
Combine all obtained terms together in an algebraic expression, which is the end result of the FOIL method. This gives us the expression \( ax + ay + bx + by \).
Other exercises in this chapter
Problem 92
Write each number in scientific notation and use scientific notation to perform the operation(s). Express the answer in scientific notation. $$ \frac{66,000 \ti
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insert either \(\) in the box between the numbers to make the statement true. $$ -\pi \square-3.5 $$
View solution Problem 93
In Exercises \(85-94,\) simplify using properties of exponents. $$\frac{\left(3 y^{2 / 4}\right)^{3}}{y^{1 / 12}}$$
View solution Problem 93
In Exercises 85-94, factor and simplify each algebraic expression. $$(4 x-1)^{1 / 2}-\frac{1}{3}(4 x-1)^{3 / 2}$$
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