Problem 93
Question
Determine the number of moles in each substance. \begin{equation}\begin{array}{l}{\text { a. } 3.25 \times 10^{20} \text { atoms of lead }} \\ {\text { b. } 4.96 \times 10^{24} \text { molecules of glucose }} \\ {\text { c. } 1.56 \times 10^{23} \text { formula units of sodium hydroxide }} \\ {\text { d. } 1.25 \times 10^{25} \text { copper (II) ions }}\end{array}\end{equation}
Step-by-Step Solution
Verified Answer
a. \(5.40 \times 10^{-4}\) moles of lead; b. 8.23 moles of glucose; c. 0.259 moles of NaOH; d. 20.75 moles of Cu^{2+}.
1Step 1: Understanding Avogadro's Number
Avogadro's number, which is \(6.022 \times 10^{23}\), represents the number of atoms, molecules, or formula units in one mole of a substance. It is a fundamental constant used to convert between atoms/molecules and moles.
2Step 2: Calculating Moles for Lead
Given: \(3.25 \times 10^{20}\) atoms of lead. Number of moles is calculated using: \[\text{moles} = \frac{\text{atoms}}{6.022 \times 10^{23}}\] Plug the values: \[\text{moles of lead} = \frac{3.25 \times 10^{20}}{6.022 \times 10^{23}} \approx 5.40 \times 10^{-4}\]
3Step 3: Calculating Moles for Glucose
Given: \(4.96 \times 10^{24}\) molecules of glucose. Use the formula: \[\text{moles} = \frac{\text{molecules}}{6.022 \times 10^{23}}\] Plug the values: \[\text{moles of glucose} = \frac{4.96 \times 10^{24}}{6.022 \times 10^{23}} \approx 8.23\]
4Step 4: Calculating Moles for Sodium Hydroxide
Given: \(1.56 \times 10^{23}\) formula units of sodium hydroxide. Use the formula: \[\text{moles} = \frac{\text{formula units}}{6.022 \times 10^{23}}\] Plug the values: \[\text{moles of NaOH} = \frac{1.56 \times 10^{23}}{6.022 \times 10^{23}} \approx 0.259\]
5Step 5: Calculating Moles for Copper (II) Ions
Given: \(1.25 \times 10^{25}\) copper (II) ions. Use the formula: \[\text{moles} = \frac{\text{ions}}{6.022 \times 10^{23}}\] Plug the values: \[\text{moles of Cu^{2+}} = \frac{1.25 \times 10^{25}}{6.022 \times 10^{23}} \approx 20.75\]
Key Concepts
Moles CalculationAtoms to Moles ConversionMolecules to Moles ConversionFormula Units to Moles Conversion
Moles Calculation
Moles are a fundamental unit in chemistry that allows scientists to count particles like atoms, molecules, and ions in a convenient way. One mole of any substance contains exactly Avogadro's number of particles, which is crucial for doing calculations involving very large or very small amounts. To convert the number of atoms, molecules, or formula units to moles, you use the relationship:
Identifying what kind of particles you are dealing with (atoms, molecules, etc.) and using Avogadro's number correctly is key to getting accurate calculations.
- Moles = \(\text{Number of Particles} / 6.022 \times 10^{23}\)
Identifying what kind of particles you are dealing with (atoms, molecules, etc.) and using Avogadro's number correctly is key to getting accurate calculations.
Atoms to Moles Conversion
When you want to convert atoms into moles, it is essential to understand that any element has atoms that are countable using Avogadro's number. For example, if you know there are \(3.25 \times 10^{20}\) atoms of lead, you would use the formula:
- Moles of lead = \(\frac{3.25 \times 10^{20} \text{ atoms}}{6.022 \times 10^{23}}\)
Molecules to Moles Conversion
Much like atoms, molecules can also be converted to moles using Avogadro's number. For molecules like glucose, if given \(4.96 \times 10^{24}\) molecules, the conversion is as follows:
- Moles of glucose = \(\frac{4.96 \times 10^{24} \text{ molecules}}{6.022 \times 10^{23}}\)
Formula Units to Moles Conversion
Lastly, converting formula units into moles is a similar process applied to ionic compounds. If you're working with sodium hydroxide, with \(1.56 \times 10^{23}\) formula units, use the formula:
- Moles of sodium hydroxide = \(\frac{1.56 \times 10^{23} \text{ formula units}}{6.022 \times 10^{23}}\)
Other exercises in this chapter
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