Problem 92
Question
Write electron configurations for \(\mathrm{O}, \mathrm{O}^{2+}\), and \(\mathrm{O}^{2-}\). Which form would you expect to find in most compounds of oxygen? Why?
Step-by-Step Solution
Verified Answer
The electron configurations for oxygen (O), oxygen cation (O²⁺), and oxygen anion (O²⁻) are:
- O: 1s^2 2s^2 2p^4
- O²⁺: 1s^2 2s^2 2p^2
- O²⁻: 1s^2 2s^2 2p^6
The most common form of oxygen in compounds is the anion, O²⁻, because gaining 2 electrons results in a stable, full outer electron shell (2p^6), resembling the noble gas neon. This stability enables O²⁻ to readily form chemical bonds with other elements through ionic bonding.
1Step 1: Identify the atomic number of oxygen
The atomic number of oxygen is 8, which means it has 8 protons and 8 electrons in its neutral form.
2Step 2: Write the electron configuration for the neutral oxygen atom (O)
To write the electron configuration for O, we will follow the Aufbau principle and the Pauli exclusion principle, filling in orbitals from lower to higher energy levels:
1s^2 2s^2 2p^4
We have filled the 1s, 2s, and 2p orbitals so that the sum of electrons is 8, the total number of electrons in a neutral oxygen atom.
3Step 3: Write the electron configuration for the oxygen cation with a 2+ charge (O²⁺)
For O²⁺, we need to remove two electrons from the electron configuration of the neutral oxygen atom. To do this, we will remove the electrons from the highest energy orbital, which is the 2p orbital.
Oxygen cation (O²⁺) electron configuration: 1s^2 2s^2 2p^2
4Step 4: Write the electron configuration for the oxygen anion with a 2- charge (O²⁻)
For O²⁻, we need to add two electrons to the electron configuration of the neutral oxygen atom. We will add the electrons to the highest energy orbital that is not yet full, which is the 2p orbital.
Oxygen anion (O²⁻) electron configuration: 1s^2 2s^2 2p^6
5Step 5: Identify the most common form for oxygen in compounds and explain why
The most common form of oxygen in compounds is the anion, O²⁻. This is because when oxygen gains 2 electrons, it becomes more stable, having a full outer electron shell (2p^6). In this configuration, the oxygen anion has the stable electron configuration of a noble gas – neon, which allows it to readily form chemical bonds with other elements in a process called ionic bonding.
Key Concepts
Oxygen AtomCation and AnionElectron OrbitalsAtomic NumberIonic Bonding
Oxygen Atom
Oxygen is a crucial element in both the environment and living organisms. Regularly found in water and organic compounds, the oxygen atom plays a vital role in life on Earth. The atomic number of oxygen is 8, which means it has 8 protons in its nucleus and, in a neutral state, 8 electrons. These electrons are configured in various shells around the nucleus, influencing the element’s chemical properties.
In its neutral form, the electron configuration of an oxygen atom is written as:
In its neutral form, the electron configuration of an oxygen atom is written as:
- 1s² 2s² 2p⁴
Cation and Anion
Ions are formed when atoms gain or lose electrons, leading to a charge imbalance. When an atom loses electrons, it becomes a cation with a positive charge. Conversely, when it gains electrons, it forms an anion, which has a negative charge.
For oxygen:
For oxygen:
- Cation (O²⁺): This occurs when oxygen loses two electrons, resulting in a 2+ charge. The electron configuration becomes 1s² 2s² 2p² due to the loss.
- Anion (O²⁻): This happens when oxygen gains two additional electrons, leading to a 2− charge. The electron configuration changes to 1s² 2s² 2p⁶, similar to the noble gas, neon.
Electron Orbitals
Electron orbitals describe regions in an atom where electrons are likely to be found. These orbitals are filled with electrons in a specific order, following rules known as the Aufbau principle, Hund's rule, and the Pauli exclusion principle.
Oxygen's electrons are located in the:
Oxygen's electrons are located in the:
- 1s orbital: the closest to the nucleus and holds 2 electrons.
- 2s orbital: next in line and can also accommodate 2 electrons.
- 2p orbitals: the highest energy level for electrons in oxygen, allowing up to 6 electrons. In its basic state, they hold 4 electrons.
Atomic Number
The atomic number is fundamental to defining an element. It represents the number of protons in the nucleus and is unique for each element. Oxygen has an atomic number of 8, identifying it unequivocally among other elements.
Understanding an element’s atomic number helps determine its position in the periodic table and predicts its chemical behavior.
Understanding an element’s atomic number helps determine its position in the periodic table and predicts its chemical behavior.
- The atomic number equals the number of electrons in a neutral atom.
- It affects the element's electron configuration and reactivity.
Ionic Bonding
Ionic bonding is a chemical bond formed between two ions with opposite charges. This type of bonding occurs when one atom donates electrons to another, resulting in a cation and an anion.
For oxygen, which commonly forms an O²⁻ anion, ionic bonding is typical when it reacts with elements that lose electrons (such as metals).
For oxygen, which commonly forms an O²⁻ anion, ionic bonding is typical when it reacts with elements that lose electrons (such as metals).
- The positive cation and the negative anion attract each other, creating a stable compound.
- This process often results in the formation of salts, like sodium chloride (table salt).
Other exercises in this chapter
Problem 90
How many valence electrons does each of these atoms have? (a) \(1 s^{2} 2 s^{2} 2 p^{3}\) (b) \(1 s^{2} 2 s^{1}\) (c) \(1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6}
View solution Problem 91
Regarding primary quantum number \(n\), which representative elements have valence electrons with an \(n\) value that is three times the \(n\) value of lithium'
View solution Problem 93
When using the periodic table to assign electron configurations, what is the rule for the \(n\) quantum number when you are in the \(d\) block? When you are in
View solution Problem 94
Why are the \(s, p, d\), and \(f\) blocks in the periodic table \(2,6,10\), and 14 blocks wide, respectively?
View solution