Problem 92
Question
Write chemical equations to represent the most probable outcome in each of the following. If no reaction is likely to occur, so state. (a) \(\mathrm{B}(\mathrm{OH})_{3} \stackrel{\Delta}{\longrightarrow}\) (b) \(\mathrm{Al}_{2} \mathrm{O}_{3}(\mathrm{s}) \stackrel{\Delta}{\longrightarrow}\) (c) \(\mathrm{CaSO}_{4} \cdot 2 \mathrm{H}_{2} \mathrm{O}(\mathrm{s}) \stackrel{\Delta}{\longrightarrow}\)
Step-by-Step Solution
Verified Answer
(a) \(\mathrm{B(OH)_3}\) \(\stackrel{\Delta}{\longrightarrow}\) \(\mathrm{B_2O_3}\) + \(3 \mathrm{H_2O}\) (b) \(\mathrm{Al_2O_3}\) \(\stackrel{\Delta}{\longrightarrow}\) no reaction (c) \(\mathrm{CaSO_4 \cdot 2 H_2O}\) \(\stackrel{\Delta}{\longrightarrow} \mathrm{CaSO_4 \cdot 0.5 H_2O}\) + \(1.5 \mathrm{H_2O}\)
1Step 1: Analyze boron hydroxide
Heat causes boron hydroxide (\(\mathrm{B(OH)_3}\)) to decompose into boron trioxide and water. The chemical equation is: \(\mathrm{B(OH)_3}\) \( \stackrel{\Delta}{\longrightarrow}\) \(\mathrm{B_2O_3}\) + \(3 \mathrm{H_2O}\)
2Step 2: Analyze aluminum oxide
Aluminium oxide (\(\mathrm{Al_2O_3}\)) is a very stable compound and does not decompose upon heating. Thus, no reaction occurs, which we can write as: \(\mathrm{Al_2O_3}\) \(\stackrel{\Delta}{\longrightarrow}\) no reaction
3Step 3: Analyze Calcium sulfate dihydrate
Calcium sulfate dihydrate (\(\mathrm{CaSO_4 \cdot 2 H_2O}\)) loses two water molecules upon heating to form Calcium sulfate hemihydrate, the equation being: \(\mathrm{CaSO_4 \cdot 2 H_2O}\) \(\stackrel{\Delta}{\longrightarrow} \mathrm{CaSO_4 \cdot 0.5 H_2O}\) + \(1.5 \mathrm{H_2O}\)
Key Concepts
Decomposition ReactionsThermal DecompositionChemical Equations
Decomposition Reactions
Decomposition reactions play a crucial role in understanding how compounds break down. When a compound undergoes a decomposition reaction, it splits into simpler substances or compounds. This type of chemical reaction often requires an input of energy such as heat or light to occur.
Imagine you have a complex Lego structure; when you take it apart, the individual Lego pieces represent the simpler substances resulting from decomposition.
Typically, decomposition reactions can be identified when a single compound breaks down into two or more products. Let's take a look at the types of decomposition reactions you might encounter:
Imagine you have a complex Lego structure; when you take it apart, the individual Lego pieces represent the simpler substances resulting from decomposition.
Typically, decomposition reactions can be identified when a single compound breaks down into two or more products. Let's take a look at the types of decomposition reactions you might encounter:
- Thermal decomposition: Requires heat to break down the compound, like heating boron hydroxide to produce boron trioxide and water.
- Electrolytic decomposition: Uses electricity to decompose a compound, such as the electrolysis of water into hydrogen and oxygen gases.
- Photolytic decomposition: Involves the use of light, often seen in the breakdown of silver bromide in photographic films.
Thermal Decomposition
Thermal decomposition is a specific type of decomposition reaction driven by the addition of heat. This heat provides the energy necessary to break chemical bonds in a compound, leading it to decompose into simpler substances.
For example, heating boron hydroxide (
Not all compounds decompose upon heating. A compound like aluminium oxide (
Thermal decomposition is quite significant in various industrial processes such as refining metals, producing ceramics, and creating cement. Understanding this reaction helps you appreciate the transformations happening at a molecular level when heat is applied.
For example, heating boron hydroxide (
B(OH)_3
) causes it to decompose into boron trioxide (
B_2O_3
) and water (
H_2O
). This reaction occurs because the supplied heat energy helps weaken and eventually break bonds within the compound, facilitating the formation of new, smaller molecules.
Not all compounds decompose upon heating. A compound like aluminium oxide (
Al_2O_3
) remains stable even when exposed to high temperatures. This stability shows that the energy supplied might not be sufficient to overcome the strong bonds within its structure.
Thermal decomposition is quite significant in various industrial processes such as refining metals, producing ceramics, and creating cement. Understanding this reaction helps you appreciate the transformations happening at a molecular level when heat is applied.
Chemical Equations
Chemical equations provide a concise way to express what happens during a chemical reaction. In a chemical equation, the substances on the left are the reactants, and those on the right are the products. An arrow (
For instance, the chemical equation for the thermal decomposition of calcium sulfate dihydrate is:\[\mathrm{CaSO_4 \cdot 2H_2O} \stackrel{\Delta}{\longrightarrow} \mathrm{CaSO_4 \cdot 0.5H_2O} + 1.5 \mathrm{H_2O}\]This equation tells us that heating calcium sulfate dihydrate turns it into calcium sulfate hemihydrate and water.
Balancing chemical equations is essential to reflect the law of conservation of mass. This law states that mass is neither created nor destroyed in a chemical reaction, meaning the number of atoms of each element should be the same on both sides of the equation. Understanding how to write and balance equations helps you accurately depict chemical processes, predict the products of reactions, and understand stoichiometric relationships in the reaction.
\rightarrow) separates them, indicating the direction of the reaction.For instance, the chemical equation for the thermal decomposition of calcium sulfate dihydrate is:\[\mathrm{CaSO_4 \cdot 2H_2O} \stackrel{\Delta}{\longrightarrow} \mathrm{CaSO_4 \cdot 0.5H_2O} + 1.5 \mathrm{H_2O}\]This equation tells us that heating calcium sulfate dihydrate turns it into calcium sulfate hemihydrate and water.
Balancing chemical equations is essential to reflect the law of conservation of mass. This law states that mass is neither created nor destroyed in a chemical reaction, meaning the number of atoms of each element should be the same on both sides of the equation. Understanding how to write and balance equations helps you accurately depict chemical processes, predict the products of reactions, and understand stoichiometric relationships in the reaction.
Other exercises in this chapter
Problem 90
Write the simplest chemical equation to represent the reaction of (a) \(\mathrm{K}_{2} \mathrm{CO}_{3}\left(\text { aq) and } \mathrm{Ba}(\mathrm{OH})_{2}(\math
View solution Problem 91
Write an equation to represent the reaction of gypsum, \(\mathrm{CaSO}_{4} \cdot 2 \mathrm{H}_{2} \mathrm{O},\) with ammonium carbonate to produce ammonium sulf
View solution Problem 93
A chemical dictionary gives the following descriptions of the production of some compounds. Write plausible chemical equations based on these descriptions. (a)
View solution Problem 94
Name the chemical compound(s) you would expect to be the primary constituent(s) of (a) stalactites; (b) gypsum; (c) "barium milkshake"; (d) blue sapphires.
View solution