Problem 92
Question
Suppose an Olympic diver who weighs \(52.0 \mathrm{~kg}\) executes a straight dive from a 10 -m platform. At the apex of the dive, the diver is \(10.8 \mathrm{~m}\) above the surface of the water. (a) What is the potential energy of the diver at the apex of the dive, relative to the surface of the water? (b) Assuming that all the potential energy of the diver is converted into kinetic energy at the surface of the water, at what speed, in \(\mathrm{m} / \mathrm{s}\), will the diver enter the water? (c) Does the diver do work on entering the water? Explain. 5.93 The air bags that provide protection in automobiles in the event of an accident expand because of a rapid chemical reaction. From the viewpoint of the chemical reactants as the system, what do you expect for the signs of \(q\) and \(w\) in this process?
Step-by-Step Solution
VerifiedKey Concepts
Understanding Kinetic Energy
\[ KE = \frac{1}{2} m v^2 \]
- \( m \) is the mass of the object.
- \( v \) is the velocity or speed of the object.
The conversion of energy shows us a fundamental principle that when energy is transferred from one form to another, the total energy remains the same.
The Principle of Conservation of Energy
In the context of the Olympic diver:
- At the top of their dive, the diver has maximum potential energy and no kinetic energy.
- As the diver falls, potential energy decreases while kinetic energy increases.
- Just before hitting the water, all the potential energy has converted into kinetic energy.
Exploring the Work-Energy Theorem
When the Olympic diver hits the water, the water exerts a force that slows the diver down. Here’s how the work-energy theorem applies:
- The diver has kinetic energy upon entering the water.
- The water exerts an upward force, opposing the diver's motion.
- This force does work on the diver, turning kinetic energy into work as it brings the diver to a stop.