Problem 92
Question
Metallic magnesium can be made by the electrolysis of molten \(\mathrm{MgCl}_{2}\) (a) What mass of \(\mathrm{Mg}\) is formed by passing a current of 4.55 A through molten \(\mathrm{MgCl}_{2}\), for 4.50 days? (b) How many minutes are needed to plate out \(25.00 \mathrm{~g} \mathrm{Mg}\) from molten \(\mathrm{MgCl}_{2}\) using \(3.50 \mathrm{~A}\) of current?
Step-by-Step Solution
Verified Answer
For part (a), the mass of magnesium produced is 222.92 g. For part (b), it will take 947.77 minutes to plate out 25 g of magnesium using a current of 3.50 A.
1Step 1: Identify relevant information
Given data for (a):
- Current (I): 4.55 A
- Time (t): 4.50 days
- Molar mass of Mg: 24.31 g/mol
- Faraday's constant (F): 96485 C/mol
Given data for (b):
- Mass of Mg: 25.00 g
- Current (I): 3.50 A
2Step 2: Calculate the charge passed through the electrolyte for part (a)
First, convert time from days to seconds:
Time (t) = 4.50 days * (24 hours/1 day) * (60 minutes/1 hour) * (60 seconds/1 minute) = 388800 seconds
Next, calculate the charge (Q) using Q = It:
Q = (4.55 A) * (388800 seconds) = 1769040 C
3Step 3: Calculate the moles of Mg produced for part (a)
Use Faraday's Law to find the moles of Mg produced (n):
n = Q / (2 * F)
n = 1769040 C / (2 * 96485 C/mol) = 9.17 mol
4Step 4: Calculate the mass of Mg produced for part (a)
Use the molar mass of Mg to find the mass of Mg produced:
Mass of Mg = n * Molar Mass of Mg
Mass of Mg = 9.17 mol * 24.31 g/mol = 222.92 g
So, the mass of magnesium produced is 222.92 g.
5Step 5: Calculate the charge passed through the electrolyte for part (b)
We know the mass of Mg to be produced is 25 g. First, we'll find the moles of Mg:
n = Mass of Mg / Molar Mass of Mg
n = 25 g / 24.31 g/mol = 1.03 mol
Now we'll use Faraday's Law to find the charge required:
Q = n * (2 * F)
Q = 1.03 mol * (2 * 96485 C/mol) = 199032.7 C
6Step 6: Calculate time needed to plate out Mg for part (b)
Use the relationship Q = It to find the time (t):
t = Q / I
t = 199032.7 C / 3.50 A = 56866.47 seconds
Now convert the time to minutes:
t = 56866.47 seconds * (1 minute / 60 seconds) = 947.77 minutes
So, it will take 947.77 minutes to plate out 25 g of Mg using a current of 3.50 A.
Key Concepts
Faraday's LawCurrent and Charge CalculationMoles and Molar Mass
Faraday's Law
Faraday's Law plays a crucial role in understanding the process of electrolysis. It essentially allows us to determine the amount of substance produced at an electrode during electrolysis. The essence of Faraday's Law is captured in the formula:\[ n = \frac{Q}{zF} \]where:
- \( n \) is the amount of substance (in moles) produced,
- \( Q \) is the total electric charge passed through the substance (in coulombs),
- \( z \) is the number of electrons involved in the reaction (which is 2 for magnesium since it forms \( \text{Mg}^{2+} \)),
- \( F \) is the Faraday's constant, approximately 96485 C/mol.
Current and Charge Calculation
Calculating the charge that passes through the electrolyte is an important step in electrolysis problems. The charge \( Q \) can be obtained through the relationship:\[ Q = It \]where:
- \( I \) is the current in amperes (A), and
- \( t \) is time in seconds (s).
Moles and Molar Mass
The concept of moles and molar mass is fundamental to chemical calculations. In the context of electrolysis, we use these concepts to link the microscopic world of atoms to measurable macroscopic quantities.To find the moles of substance produced, the formula:\[ n = \frac{\text{Mass}}{\text{Molar Mass}} \]comes into play. Molar mass is the weight of one mole of a substance and is typically expressed in grams per mole (g/mol).For magnesium, given that its molar mass is 24.31 g/mol, we can calculate the number of moles from a given mass. For example, if you need to produce 25 g of Mg, the calculation would be:\[ n = \frac{25 \text{ g}}{24.31 \text{ g/mol}} \approx 1.03 \text{ mol} \]This calculated moles of magnesium are then essential for determining the charge required during electrolysis, thereby linking Faraday's Law, current, charge, and the physical quantity of magnesium required.
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