Problem 92
Question
In the detection of sulphur, sodium nitroprusside solution is added to the Lassaigne's test solution, a purple coloured is obtained. It is due to (a) \(\mathrm{Na}_{3}\left[\mathrm{Fe}(\mathrm{CN})_{5} \mathrm{NOSNa}\right]\) (b) \(\mathrm{Na}_{3}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]\) (c) \(\mathrm{Fe}(\mathrm{CNS})_{3}\) (d) \(\mathrm{Na}_{3}\left[\mathrm{Fe}(\mathrm{CN})_{5} \mathrm{NS}\right]\)
Step-by-Step Solution
Verified Answer
The purple color is due to ext{Na}_3[ ext{Fe}( ext{CN})_5 ext{NOS}], best approximated by option (a).
1Step 1: Understanding Lassaigne's Test for Sulphur
Lassaigne's test is used to detect the presence of sulphur in an organic compound. In this test, the organic compound is fused with sodium, and then various reagents are added to detect different elements present, including sulphur.
2Step 2: Forming the Lassaigne's Solution
When an organic compound containing sulphur is fused with sodium, it forms sodium sulphide ( ext{Na}_2 ext{S}). This is a key product used in the detection of sulphur.
3Step 3: Reacting with Sodium Nitroprusside
The sodium sulphide solution obtained from Lassaigne's test is treated with sodium nitroprusside ( ext{Na}_2[ ext{Fe}( ext{CN})_5 ext{NO}]). If sulphide ions ( ext{S}^{2-}) are present, they react with sodium nitroprusside to produce a purple-colored complex.
4Step 4: Identifying the Complex Formed
The reaction of sodium sulphide with sodium nitroprusside results in the formation of the complex ext{Na}_3[ ext{Fe}( ext{CN})_5 ext{NOS}], which is responsible for the characteristic purple color observed. This signals the presence of sulphur.
5Step 5: Selecting the Correct Option
Among the given options, option (a) ext{Na}_3[ ext{Fe}( ext{CN})_5 ext{NOSNa}] is the closest representation. However, the correct form for the complex responsible for the purple color is ext{Na}_3[ ext{Fe}( ext{CN})_5 ext{NOS}], which is slightly different but aligns with the selection.
Key Concepts
Sulphur DetectionSodium NitroprussidePurple Complex Formation
Sulphur Detection
Detecting sulphur is essential in chemistry, especially within Lassaigne's test. This fascinating test reveals how organic compounds interact with other elements. In Lassaigne's test, the organic compound undergoes fusion with sodium. This isn't merely for fun; it has a purpose!
- The fusion aims to convert covalently bonded sulphur into ionic form, making it easier to detect.
- When sodium combines with sulphur, it turns into sodium sulphide ( Na_2S ).
- This compound, sodium sulphide, acts as a landmark, indicating where sulphur is present.
Sodium Nitroprusside
Sodium nitroprusside is not only a mouthful to say, but it also plays a crucial role in detecting sulphur. It's a key reagent in Lassaigne's test for sulphur detection. This compound, sodium nitroprusside, has a specific purpose:
- It reacts specifically with sulphide ions ( S^{2-} ), which are released when sodium sulphide is mixed in water.
- One cannot perform the magic of turning invisible sulphides into a visible spectacle without it.
- It detects these sulphide ions and signals their presence via a color change.
Purple Complex Formation
In the dramatic finale of the sulphur detection in Lassaigne's test, the formation of the purple complex occurs. When sodium nitroprusside meets the sulphide ions, a vibrant transformation takes place:
- The reaction between sodium nitroprusside and the sulphide ions results in the emergence of a purple-colored complex.
- This complex, Na_3[Fe(CN)_5NOS] , confirms the presence of sulphur conclusively.
- The color change to purple is a bright indicator of sulphur and is easy to identify even without sophisticated instruments.
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