Problem 92
Question
Graph \(f(x)=2^{x}\) and its inverse function in the same rectangular coordinate system.
Step-by-Step Solution
Verified Answer
The graphs of \(f(x) = 2^{x}\) and its inverse function \(f^{-1}(x) = log_{2}{x}\) should be plotted on the same coordinate system. The former is an increasing curve crossing the y-axis at y=1. The latter is also an increasing curve, but crossing the x-axis at x=1. One can clearly see that both graphs are mirror images of each other about the line y=x.
1Step 1: Understanding the function
The function given is \(f(x) = 2^{x}\), which is an exponential function. For any real number x, 2 to the power of x is defined.
2Step 2: Plot the function
Create a table of values to help determine points on the graph of \(f(x) = 2^{x}\). Then use these points to sketch the graph. Include at least a few negative and positive values of x.
3Step 3: Finding the inverse function
The inverse function of \(f(x) = 2^{x}\) is found by swapping the roles of y and x. We write \(y = 2^{x}\) as \(x = 2^{y}\), which gives \(y = log_{2}{x}\). So, the inverse function is \(f^{-1}(x) = log_{2}{x}\).
4Step 4: Plot the inverse function
Similarly as in Step 2, create a table of values to help determine points on the graph of \(f^{-1}(x) = log_{2}{x}\). Then use these points to sketch the graph.
5Step 5: Include both graphs
Graph \(f(x) = 2^{x}\) and \(f^{-1}(x) = log_{2}{x}\) in the same rectangular coordinate system.
Other exercises in this chapter
Problem 91
In Exercises 81–100, evaluate or simplify each expression without using a calculator. $$ \ln \frac{1}{e^{6}} $$
View solution Problem 92
In Exercises 81–100, evaluate or simplify each expression without using a calculator. $$ \ln \frac{1}{e^{7}} $$
View solution Problem 93
Solve each equation. $$ 5^{2 x} \cdot 5^{4 x}=125 $$
View solution Problem 93
In Exercises 81–100, evaluate or simplify each expression without using a calculator. $$ e^{\ln 125} $$
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