Problem 92
Question
Explain the cooling effect experienced when ethanol is rubbed on your skin, given that \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}(l) \longrightarrow \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}(g) \quad \Delta H^{\circ}=42.2 \mathrm{~kJ} / \mathrm{mol}\)
Step-by-Step Solution
Verified Answer
Ethanol evaporates, absorbing heat from the skin for the endothermic process, causing cooling.
1Step 1: Understanding the Evaporation Process
Ethanol, when applied to the skin, transitions from a liquid phase to a gaseous phase (evaporation). This is represented by the process \( \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}(l) \rightarrow \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}(g) \). Evaporation occurs when molecules at the surface gain enough energy to overcome intermolecular forces and enter the gaseous state.
2Step 2: Analyze the Enthalpy Change
The given thermochemical equation states that the enthalpy change (\( \Delta H^{\circ} \)) for the evaporation of ethanol is \( 42.2 \mathrm{~kJ/mol} \). This positive value indicates that the process requires energy input, as it is an endothermic process.
3Step 3: Connect Energy Absorption to Cooling Effect
As ethanol evaporates from your skin, it absorbs heat energy from the skin in order to overcome the enthalpy change (\( 42.2 \mathrm{~kJ/mol} \)). This absorption of heat energy from the skin results in a decrease in skin temperature, leading to the sensation of cooling.
Key Concepts
EthanolEnthalpy ChangeEndothermic Process
Ethanol
Ethanol is a chemical compound with the formula \( C_2H_5OH \), commonly known as alcohol. It is widely used in industrial and consumer products, from fuel to antiseptic hand sanitizers. One of its notable properties is its ability to evaporate quickly. When you apply ethanol to your skin, its molecules transition from a liquid state to a gaseous state. This process is called evaporation. Ethanol's high volatility—meaning it easily transforms into vapor at room temperature—makes it effective in applications where quick drying is needed.
Ethanol has relatively weak intermolecular forces—specifically, hydrogen bonds—compared to heavier alcohols, which allows it to evaporate quickly.
This evaporation process on the skin brings about the cooling sensation we experience.
Understanding ethanol's characteristics is essential for recognizing its broad applications and effects on temperature changes during its evaporation.
Ethanol has relatively weak intermolecular forces—specifically, hydrogen bonds—compared to heavier alcohols, which allows it to evaporate quickly.
This evaporation process on the skin brings about the cooling sensation we experience.
Understanding ethanol's characteristics is essential for recognizing its broad applications and effects on temperature changes during its evaporation.
Enthalpy Change
Enthalpy change, represented by \( \Delta H^{\circ} \), refers to the heat absorbed or released in a chemical reaction at constant pressure. When ethanol evaporates, the enthalpy change is positive, specifically \( \Delta H^{\circ} = 42.2 \text{ kJ/mol} \).
This value tells us that the process requires an input of energy.
This value tells us that the process requires an input of energy.
- Positive \( \Delta H^{\circ} \): Indicates an endothermic process where energy is absorbed.
- The magnitude of \( 42.2 \text{ kJ/mol} \): Describes the energy required to convert 1 mole of liquid ethanol to its gaseous state.
Endothermic Process
An endothermic process is defined by the absorption of heat. In the context of ethanol on the skin, this process is what causes the cooling effect.
When ethanol evaporates:
When ethanol evaporates:
- Heat is absorbed from your skin to provide the necessary energy for molecular separation.
- This energy absorption corresponds to the enthalpy change \( \Delta H^{\circ} = 42.2 \text{ kJ/mol} \).
Other exercises in this chapter
Problem 87
You are given the following data: \(\begin{aligned} \mathrm{H}_{2}(g) & \longrightarrow 2 \mathrm{H}(g) & & \Delta H^{\circ}=436.4 \mathrm{~kJ} / \mathrm{mol} \
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For which of the following reactions does \(\Delta H_{\mathrm{rxn}}^{\circ}=\Delta H_{\mathrm{f}}^{\circ}\) ? (a) \(\mathrm{H}_{2}(g)+\mathrm{S}(\) rhombic \()
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Calculate the work done (in joules) when \(1.0 \mathrm{~mole}\) of water is frozen at \(0^{\circ} \mathrm{C}\) and \(1.0 \mathrm{~atm}\). The volumes of 1 mole
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