Problem 92
Question
Determine whether each statement is true or false. If the statement is false, make the necessary change(s) to produce a true statement. Graph \(f(x)=2^{x}\) and its inverse function in the same rectangular coordinate system.
Step-by-Step Solution
Verified Answer
The original function is \(f(x) = 2^{x}\) and the inverse function is \(f^{-1}(x) = \log_{2}(x)\). They can be graphed on the same coordinate system, with the latter being a reflection of the former over the line \(y = x\).
1Step 1: Function Identification
The given function is \(f(x) = 2^{x}\) . Find the inverse function to this.
2Step 2: Finding the Inverse Function
The inverse of a function can be found by switching the roles of \(y\) and \(x\). In this case, change \(f(x) = 2^{x}\) to \(x = 2^{y}\), and then solve for \(y\) . Use the property of logarithms to rewrite the equation as \(y = \log_{2}(x)\) . This equation is the inverse of \(f(x) = 2^{x}\)
3Step 3: Graphing the Function and Its Inverse
Now that both functions are known, they can be graphed on the same coordinate plane. \(f(x) = 2^{x}\) is an exponential function that increases rapidly as x grows and approaches 0 as x decreases. The graph of \(y = \log_{2}(x)\) is a reflection of \(f(x) = 2^{x}\) over the line \(y = x\), since a function and its inverse are reflections of each other on the line \(y = x\). So, the graph of \(y = \log_{2}(x)\) increases at a slower rate as x grows and approaches negative infinity as x gets smaller.
Key Concepts
Exponential FunctionsLogarithmsGraphing Functions
Exponential Functions
Exponential functions, like the one in the exercise, are mathematical expressions where the variable is an exponent. They typically take the form \( f(x) = a^x \), where \( a \) is a positive constant. In the original exercise, \( f(x) = 2^x \) represents an exponential function where the base is 2.
These functions are characterized by their rapid growth: as the value of \( x \) increases, \( f(x) \) rises steeply. Conversely, as \( x \) becomes more negative, \( f(x) \) approaches zero but never really reaches it, producing a horizontal asymptote at \( y=0 \).
Exponential functions are common in many real-world contexts, such as population growth, radioactive decay, and investment growth. Their increasing nature and the presence of an asymptote make them easy to spot when graphing.
These functions are characterized by their rapid growth: as the value of \( x \) increases, \( f(x) \) rises steeply. Conversely, as \( x \) becomes more negative, \( f(x) \) approaches zero but never really reaches it, producing a horizontal asymptote at \( y=0 \).
Exponential functions are common in many real-world contexts, such as population growth, radioactive decay, and investment growth. Their increasing nature and the presence of an asymptote make them easy to spot when graphing.
- Key characteristic: Rapid increase or decrease.
- Intersects y-axis: Always at y = 1 unless there's a vertical shift.
- Horizontal Asymptote: Generally along the line y=0.
Logarithms
Logarithms are essentially the inverse operations to exponential functions. They help to solve equations involving exponents by converting them into a form where they can be more easily managed. In the solution, the function \( y = \log_2(x) \) is obtained by reversing the roles of \( x \) and \( y \) in \( f(x) = 2^x \).
The logarithm \( \log_2(x) \) answers the question: "To what power must 2 be raised, to equate to \( x \)?" Essentially, if \( 2^y = x \), then \( \log_2(x) = y \).
This inverse relationship with exponential functions means logarithmic functions grow much more slowly. This growth is essential in fields like computer science and information theory where multiplicative processes are analyzed.
The logarithm \( \log_2(x) \) answers the question: "To what power must 2 be raised, to equate to \( x \)?" Essentially, if \( 2^y = x \), then \( \log_2(x) = y \).
This inverse relationship with exponential functions means logarithmic functions grow much more slowly. This growth is essential in fields like computer science and information theory where multiplicative processes are analyzed.
- Basic Form: \( \log_b(x) \)
- Interpretation: What power does b need to become x?
- Non-Continuous at Origin: Undefined at \( x=0 \) and negative values.
Graphing Functions
Graphing functions is a visual method to understand mathematical relationships, allowing one to see trends, intersections, and growth patterns quickly. The exercise involves graphing \( f(x) = 2^x \) and its inverse \( y = \log_2(x) \), providing an excellent way to observe their inverse nature.
When graphing \( f(x) = 2^x \), expect a curve that starts near the horizontal asymptote \( y=0 \) for low \( x \) values, rising steeply as \( x \) increases.
The inverse function \( y = \log_2(x) \) will appear as a reflection of \( f(x) = 2^x \) along the line \( y = x \). It will increase slowly and is defined only for \( x > 0 \).
When graphing \( f(x) = 2^x \), expect a curve that starts near the horizontal asymptote \( y=0 \) for low \( x \) values, rising steeply as \( x \) increases.
The inverse function \( y = \log_2(x) \) will appear as a reflection of \( f(x) = 2^x \) along the line \( y = x \). It will increase slowly and is defined only for \( x > 0 \).
- Reflection Principle: Inverse functions are reflections over the line \( y=x \).
- Graphing Tool: Use tools like graph paper or software for perfect accuracy.
- Asymptotes: Indicative of function behavior as x approaches extreme values.
Other exercises in this chapter
Problem 91
Solve each logarithmic equation. Be sure to reject any value of \(x\) that is not in the domain of the original logarithmic expressions. Give the exact answer.
View solution Problem 92
Evaluate or simplify each expression without using a calculator. $$\ln \frac{1}{e^{7}}$$
View solution Problem 92
Solve each logarithmic equation. Be sure to reject any value of \(x\) that is not in the domain of the original logarithmic expressions. Give the exact answer.
View solution Problem 93
Evaluate or simplify each expression without using a calculator. $$e^{\ln 125}$$
View solution