Problem 92
Question
All radioactive decays are first order. Why is this so?
Step-by-Step Solution
Verified Answer
Radioactive decay is first order because the decay rate is proportional to the number of undecayed nuclei, fitting first-order kinetics.
1Step 1: Understanding First-Order Reactions
First-order reactions are characterized by the rate of reaction being directly proportional to the concentration of a single reactant. In mathematical terms, this is expressed in the rate law as \( r = k[A] \), where \( r \) is the reaction rate, \( k \) is the rate constant, and \( [A] \) is the concentration of the reactant.
2Step 2: Understanding Radioactive Decay
Radioactive decay is the process by which an unstable atomic nucleus loses energy by emitting radiation. This process depends solely on the radioactive substance itself and not on its concentration, environment, or the presence of other substances.
3Step 3: Analyzing the Relationship Between Decay and First-Order Kinetics
Radioactive decay fits the model of a first-order reaction because the rate of decay is directly proportional to the number of undecayed nuclei present at any given time. This aligns with the first-order rate law \( r = k[N] \), where \( [N] \) is the number of radioactive nuclei.
4Step 4: Expression of Radioactive Decay Mathematically
The mathematical expression for radioactive decay is \( N(t) = N_0 e^{-kt} \), where \( N(t) \) is the amount of substance remaining at time \( t \), \( N_0 \) is the initial amount of substance, \( k \) is the decay constant, and \( t \) is the time elapsed. This equation is derived from the first-order kinetics model.
5Step 5: Conclusion and Reasoning
Radioactive decay follows first-order kinetics because it is an exponential decay process where the rate of decay is a constant proportion of the remaining substance at any time, independent of the concentration, thus fitting the definition of first-order reactions.
Key Concepts
First-Order ReactionsRate LawExponential DecayDecay Constant
First-Order Reactions
First-order reactions are essential in understanding many chemical processes, especially radioactive decay. These reactions are unique because their rate is directly proportional to the concentration of one reactant. This can be expressed with the rate law equation:
- \( r = k[A] \)
- \( r \): reaction rate
- \( k \): rate constant
- \( [A] \): concentration of the reactant
Rate Law
The rate law provides a precise mathematical way to describe how a reaction rate depends on the concentration of reactants. It is significant because it quantitatively tells us about the reaction's speed and mechanism. In the case of first-order reactions, the rate law is:\[ r = k[A] \]Here are the key components:
- \( r \) - the speed of the reaction
- \( k \) - the specific rate constant for the reaction, unique to each reaction and conditions like temperature
- \( [A] \) - the concentration of the reactant
Exponential Decay
Exponential decay is a pattern where quantities decrease rapidly at first and then slow down significantly as time goes on. This concept is central to radioactive decay, where unstable nuclei lose energy.The mathematical representation of exponential decay in radioactive materials is:\[ N(t) = N_0 e^{-kt} \]Where:
- \( N(t) \): number of radioactive atoms remaining after time \( t \)
- \( N_0 \): initial number of atoms
- \( e \): base of natural logarithms
- \( k \): decay constant
- \( t \): time
Decay Constant
The decay constant, denoted by \( k \), is a pivotal element in understanding the rate of radioactive decay. It is a measure of the probability per unit time that a given atom will decay. The larger the decay constant, the quicker the rate of decay.In the exponential decay equation \( N(t) = N_0 e^{-kt} \), \( k \) governs how rapidly the number of undecayed atoms decreases over time. The decay constant links the unique properties of a substance to its half-life, which is the time required for half of the radioactive atoms in a sample to decay. This relationship is given by:\[ t_{1/2} = \frac{0.693}{k} \]Where \( t_{1/2} \) is the half-life. Understanding \( k \) not only reveals how quickly a substance decays but also helps in making practical decisions in fields such as nuclear medicine, carbon dating, and nuclear energy.
Other exercises in this chapter
Problem 89
Most students have no trouble understanding that \(1.5 \mathrm{~g}\) of a \(24-g\) sample of a radioisotope would remain after \(8 \mathrm{~h}\) if it had \(t_{
View solution Problem 90
Nuclear chemistry is a topic that raises many debatable issues. Briefly discuss your views on the following. (a) Twice a year the general public is allowed to v
View solution Problem 93
A sample of the alpha emitter \({ }_{86}^{222} \mathrm{Rn}\) had an initial activity, \(A_{0},\) of \(7.00 \times 10^{4}\) Bq. After 10.0 days its activity, \(A
View solution Problem 95
A chemist is setting up an experiment using \({ }_{20}^{47} \mathrm{Ca},\) which has a half-life of 4.5 days. She needs \(10.0 \mu \mathrm{g}\) of the calcium.
View solution