The paint bomb does not explode in both frames.
1Step 1: Calculate Tunnel Length in Train Frame
According to the theory of relativity, lengths contract in the direction of motion as perceived from a different inertial frame. The tunnel's proper length is given as \( L_0 = 200 \) m. The tunnel length in the train's frame can be calculated using the length contraction formula:\[ L = L_0 \sqrt{1 - \frac{v^2}{c^2}} \]Substitute \( v = 0.900c \):\[ L = 200 \sqrt{1 - (0.900)^2} = 200 \times \sqrt{0.19} \approx 86.6 \text{ m} \].
2Step 2: Determine Which Event Occurs First in Train Frame
By analyzing the sequence of events from the train's perspective: the train perceives the tunnel to be only 86.6 m long. Since the train's length remains its proper length of 200 m in its own frame, the rear end of the train will pass the near end (event RN) before the front of the train passes the far end (event FF) because the whole train cannot fit within this shortened tunnel.
3Step 3: Calculate Time Between Events in Train Frame
The events FF and RN are spatially separated events in the train frame. The time it takes for the rear of the train to cover the tunnel length of 86.6 m is calculated with the relative speed. This time is:\[ t = \frac{L}{v} = \frac{86.6 \text{ m}}{0.900c} = \frac{86.6}{0.9 \times 3 \times 10^8} \approx 3.21 \times 10^{-7} \text{ s} \].
4Step 4: Determine If Paint Bomb Explodes (Train Frame)
Because the signal to deactivate the bomb is sent first (event RN occurs first), the bomb is deactivated before it can explode when the front of the train exits the tunnel. Hence, the paint bomb does not explode in the train's frame.
5Step 5: Calculate Train Length in Tunnel Frame
From the tunnel’s perspective, the length of the moving train is contracted. The proper length of the train is given as 200 m. Calculating in the tunnel’s frame:\[ L' = L_0 \sqrt{1 - \frac{v^2}{c^2}} = 200 \times \sqrt{0.19} \approx 86.6 \text{ m} \].
6Step 6: Determine Which Event Occurs First in Tunnel Frame
In the tunnel’s frame, the contracted train fits exactly within the 200 m long tunnel since both are perceived to be the same length. However, both events happen simultaneously in the tunnel’s frame; thus, both events FF and RN occur at the same time.
7Step 7: Calculate Time Between Events in Tunnel Frame
In the tunnel’s frame, due to the simultaneity of both events occurring at once, the time duration between these two events is \( t = 0 \) seconds.
8Step 8: Determine If Paint Bomb Explodes (Tunnel Frame)
Since both events happen simultaneously (the deactivation signal is received at the same time the front passes the end of the tunnel), the bomb does not explode as sufficient time isn't given for any sequential event.
9Step 9: Resolve the Paradox
Both frames agree that the bomb does not explode. In the train frame, the deactivation signal is sent before the front exits the tunnel. In the tunnel frame, events RN and FF are simultaneous, thus extensive painting doesn't occur. Therefore, there's no paradox because all frames conclude that the paint bomb does not trigger.