Problem 91
Question
The series of emission lines of the hydrogen atom for which \(n_{f}=4\) is called the Brackett series. (a) Determine the region of the electromagnetic spectrum in which the lines of the Brackett series are observed. (b) Calculate the wavelengths of the first three lines in the Brackett series-those for which \(n_{i}=5,6,\) and 7.
Step-by-Step Solution
Verified Answer
The Brackett series is observed in the infrared region. The wavelengths for transitions from \( n_i = 5, 6, \) and 7 to \( n_f = 4 \) are 4050 nm, 2620 nm, and 2170 nm, respectively.
1Step 1: Understanding the Brackett Series
The Brackett series of the hydrogen atom refers to the emission lines that occur when an electron falls to the principal quantum number level \( n_f = 4 \). This series is part of the infrared region of the electromagnetic spectrum.
2Step 2: Using the Rydberg Formula
The Rydberg formula is used to calculate the wavelengths of the spectral lines: \[\frac{1}{\lambda} = R_H \left(\frac{1}{n_f^2} - \frac{1}{n_i^2}\right)\]where \( R_H \) is the Rydberg constant \((1.097 \times 10^7 \text{ m}^{-1})\), \( n_f = 4 \), and \( n_i \) is the initial quantum number.
3Step 3: Calculate Wavelength for \( n_i = 5 \)
Substitute \( n_i = 5 \) into the Rydberg formula: \[\frac{1}{\lambda} = 1.097 \times 10^7 \left(\frac{1}{16} - \frac{1}{25}\right)\]Calculate the difference: \[\frac{1}{16} - \frac{1}{25} = \frac{9}{400}\]Now calculate \( \lambda \):\[\frac{1}{\lambda} = 1.097 \times 10^7 \times \frac{9}{400} = 2.469 \times 10^5 \]Thus, \( \lambda \approx 4.05 \times 10^{-6} \text{ m} \) or 4050 nm.
4Step 4: Calculate Wavelength for \( n_i = 6 \)
Substitute \( n_i = 6 \) into the Rydberg formula: \[\frac{1}{\lambda} = 1.097 \times 10^7 \left(\frac{1}{16} - \frac{1}{36}\right)\]Calculate the difference: \[\frac{1}{16} - \frac{1}{36} = \frac{5}{144}\]Now calculate \( \lambda \):\[\frac{1}{\lambda} = 1.097 \times 10^7 \times \frac{5}{144} = 3.816 \times 10^5 \]Thus, \( \lambda \approx 2.62 \times 10^{-6} \text{ m} \) or 2620 nm.
5Step 5: Calculate Wavelength for \( n_i = 7 \)
Substitute \( n_i = 7 \) into the Rydberg formula: \[\frac{1}{\lambda} = 1.097 \times 10^7 \left(\frac{1}{16} - \frac{1}{49}\right)\]Calculate the difference: \[\frac{1}{16} - \frac{1}{49} = \frac{33}{784}\]Now calculate \( \lambda \):\[\frac{1}{\lambda} = 1.097 \times 10^7 \times \frac{33}{784} = 4.617 \times 10^5 \]Thus, \( \lambda \approx 2.17 \times 10^{-6} \text{ m} \) or 2170 nm.
Key Concepts
Hydrogen Atom Emission LinesRydberg FormulaInfrared SpectrumQuantum Numbers
Hydrogen Atom Emission Lines
The hydrogen atom is a quite fascinating model in atomic physics. Emission lines are a key concept here, as they represent the specific wavelengths of light emitted when an electron falls to a lower energy level in the atom. Each transition has a characteristic line in the spectrum, creating unique series of lines, named after their discoverers.
When an electron in the hydrogen atom moves from a higher energy level (higher quantum number) to a lower one, it emits energy in the form of light. This energy translates into distinct emission lines, useful in identifying the presence of hydrogen in various cosmic and laboratory settings.
When an electron in the hydrogen atom moves from a higher energy level (higher quantum number) to a lower one, it emits energy in the form of light. This energy translates into distinct emission lines, useful in identifying the presence of hydrogen in various cosmic and laboratory settings.
- The Brackett series involves transitions that terminate at the quantum number level \( n_f = 4 \).
- Each series of lines falls within specific regions of the electromagnetic spectrum. For instance, the Lyman series lies in the ultraviolet region, while the Brackett series can be observed in the infrared spectrum.
Rydberg Formula
The Rydberg formula is a crucial mathematical tool used to calculate the wavelengths of the emitted or absorbed light for electron transitions in hydrogen. It's a wonderful example of how mathematics can help us understand physical phenomena.
The formula is given by: \[\frac{1}{\lambda} = R_H \left(\frac{1}{n_f^2} - \frac{1}{n_i^2}\right)\]Where:
The formula is given by: \[\frac{1}{\lambda} = R_H \left(\frac{1}{n_f^2} - \frac{1}{n_i^2}\right)\]Where:
- \( \lambda \) is the wavelength of the light emitted or absorbed.
- \( R_H \) is the Rydberg constant, approximately \( 1.097 \times 10^7 \text{ m}^{-1} \).
- \( n_f \) and \( n_i \) are the final and initial quantum numbers respective to an electron transition.
Infrared Spectrum
The infrared spectrum is a segment of the electromagnetic spectrum with wavelengths longer than visible light. While invisible to the human eye, infrared is crucial in scientific research thanks to its ability to reveal information invisible in other spectral regions.
The Brackett series of hydrogen falls within this infrared region. This is because the energy changes involved in the electron transitions to the \( n_f = 4 \) level correspond to light with wavelengths longer than those in the visible range.
The Brackett series of hydrogen falls within this infrared region. This is because the energy changes involved in the electron transitions to the \( n_f = 4 \) level correspond to light with wavelengths longer than those in the visible range.
- Infrared is often used in astrophysics to observe celestial objects obscured by interstellar dust that blocks visible light.
- It's highly useful in remote sensing, astronomy, and even certain medical imaging technologies.
Quantum Numbers
Quantum numbers are fundamental to understanding the structure of an atom. They describe the distribution and behavior of electrons in an atom, providing insights into their energies and orbits.
For hydrogen, and other atoms, there are four quantum numbers essential for this explanation:
For hydrogen, and other atoms, there are four quantum numbers essential for this explanation:
- Principal Quantum Number \( n \): Determines the energy level of an electron and its average distance from the nucleus. Larger values mean higher energy levels.
- Azimuthal Quantum Number \( l \): Describes the shape of the orbital, ranging from 0 to \( n-1 \).
- Magnetic Quantum Number \( m_l \): Describes the orientation of the orbital in space.
- Spin Quantum Number \( m_s \): Describes the intrinsic angular momentum (spin) of the electron.
Other exercises in this chapter
Problem 85
The rays of the Sun that cause tanning and burning are in the ultraviolet portion of the electromagnetic spectrum. These rays are categorized by wavelength. So-
View solution Problem 86
The watt is the derived SI unit of power, the measure of energy per unit time: \(1 \mathrm{~W}=1 \mathrm{~J} / \mathrm{s}\). A semiconductor laser in a DVD play
View solution Problem 92
When the spectrum of light from the Sun is examined in high resolution in an experiment similar to that illustrated in Figure 6.9 , dark lines are evident. Thes
View solution Problem 93
Determine whether each of the following sets of quantum numbers for the hydrogen atom are valid. If a set is not valid, indicate which of the quantum numbers ha
View solution