Problem 91
Question
The equation \(r=|\cos \theta|\) represents (A) two circles of radii \(\frac{1}{2}\) each (B) two circles centered at \(\left(\frac{1}{2}, 0\right)\) and \(\left(-\frac{1}{2}, 0\right)\) (C) two circles touching each other at the origin (D) pair of straight lines
Step-by-Step Solution
Verified Answer
Option (C) is correct; the circles touch at the origin.
1Step 1: Understand the Equation
The given polar equation is \(r = |\cos \theta|\). This equation describes points whose distance from the origin is the absolute value of the cosine of the angle \(\theta\).
2Step 2: Analyze the Interval for Cosine
Recall that the cosine function \(\cos \theta\) varies between -1 and 1. Therefore, \(|\cos \theta|\) will vary between 0 and 1 because the absolute value function makes all negative values positive.
3Step 3: Convert to Cartesian Coordinates
The polar equation can be represented in Cartesian coordinates: \(r = x^2 + y^2\) and \( \cos \theta = \frac{x}{\sqrt{x^2+y^2}} \). Rearranging yields the equation \(x^2 + y^2 = |x|\), considering \(r = |\cos \theta| = |x| / \sqrt{x^2+y^2}\).
4Step 4: Simplify the Cartesian Equation
For \(x \geq 0\), the equation \(x^2 + y^2 = x\) represents a circle centered at \((\frac{1}{2}, 0)\) with radius \(\frac{1}{2}\). Similarly, for \(x < 0\), \(x^2 + y^2 = -x\) describes another circle centered at \((-\frac{1}{2}, 0)\) also with radius \(\frac{1}{2}\).
5Step 5: Identify the Touching Point
Both circles are tangent to the y-axis at the origin \((0,0)\). They touch each other at this point. Therefore, the statement (C) is verified.
Key Concepts
Polar EquationsCartesian CoordinatesCircle Geometry
Polar Equations
Polar equations describe the relationship between a point's distance from a central origin and the angle it forms with a reference direction, typically the positive x-axis. In polar coordinates, every point on the plane is specified by a radius and an angle.
For example, the equation \( r = |\cos \theta| \) describes a set of points where the distance \( r \) from the origin is the absolute value of the cosine of the angle \( \theta \). The absolute value ensures that \( r \) is always non-negative, which is crucial for defining radial distances.
Understanding and analyzing these equations often involves recognizing the behavior of trigonometric functions over their intervals.
For example, the equation \( r = |\cos \theta| \) describes a set of points where the distance \( r \) from the origin is the absolute value of the cosine of the angle \( \theta \). The absolute value ensures that \( r \) is always non-negative, which is crucial for defining radial distances.
Understanding and analyzing these equations often involves recognizing the behavior of trigonometric functions over their intervals.
- Cosine values range between -1 and 1.
- The absolute value of these values ranges between 0 and 1.
Cartesian Coordinates
Converting polar equations into Cartesian coordinates can provide more familiar forms of geometric shapes. Cartesian coordinates use \(x\) and \(y\) to describe a point's horizontal and vertical distances from the origin. This system makes understanding geometric figures intuitive and straightforward.
When translating from polar to Cartesian coordinates, you often rely on relationships such as \(x = r \cos \theta\) and \(y = r \sin \theta\). These conversions open up polar equations to algebraic manipulations and recognitions of common geometric shapes. For the equation \( r = |\cos \theta| \), when rewritten in Cartesian form, you can use the identities:
When translating from polar to Cartesian coordinates, you often rely on relationships such as \(x = r \cos \theta\) and \(y = r \sin \theta\). These conversions open up polar equations to algebraic manipulations and recognitions of common geometric shapes. For the equation \( r = |\cos \theta| \), when rewritten in Cartesian form, you can use the identities:
- \( r = \sqrt{x^2 + y^2} \)
- \( \cos \theta = \frac{x}{\sqrt{x^2 + y^2}} \)
Circle Geometry
Understanding the geometry of circles is essential when analyzing line and plane equations. Circles are defined by their center point and radius.
In Cartesian coordinates, a circle's equation typically takes the form \((x - h)^2 + (y - k)^2 = r^2\), where \((h, k)\) is the center and \(r\) is the radius. By examining such equations, you can determine important information about the circle's placement and size.
For the given equations resulting from the polar conversion, \(x^2 + y^2 = x\) and \(x^2 + y^2 = -x\) form two circles:
In Cartesian coordinates, a circle's equation typically takes the form \((x - h)^2 + (y - k)^2 = r^2\), where \((h, k)\) is the center and \(r\) is the radius. By examining such equations, you can determine important information about the circle's placement and size.
For the given equations resulting from the polar conversion, \(x^2 + y^2 = x\) and \(x^2 + y^2 = -x\) form two circles:
- Center at \((1/2, 0)\) with radius \(1/2\)
- Center at \((-1/2, 0)\) also with radius \(1/2\)
Other exercises in this chapter
Problem 88
Two vertices of an equilateral triangle are \((-1,0)\) and \((1,0)\). An equation of its circumcentre is (A) \(x^{2}+y^{2}+\frac{2}{\sqrt{3}} y-1=0\) (B) \(x^{2
View solution Problem 90
A tangent to the circle \(x^{2}+y^{2}=1\) through the point \((0,5)\) cuts the circle \(x^{2}+y^{2}=4\) at \(A\) and \(B\). The tangents for the circle \(x^{2}+
View solution Problem 92
If the polar of \(P\) with respect to the circle \(x^{2}+y^{2}=a^{2}\) touches the circle \((x-f)^{2}+(y-g)^{2}=b^{2}\), then its locus is given by the equation
View solution Problem 93
The pole of the line \(3 x+4 y=45\) with respect to the circle \(x^{2}+y^{2}-6 x-8 y+5=0\) is (A) \((6,8)\) (B) \((6,-8)\) (C) \((-6,8)\) (D) \((-6,-8)\)
View solution